ORG.CHEM W/TEXT+SOLU.MANUAL
ORG.CHEM W/TEXT+SOLU.MANUAL
15th Edition
ISBN: 9780393252125
Author: KARTY
Publisher: W.W.NORTON+CO.
Question
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Chapter 23, Problem 23.65P
Interpretation Introduction

(a)

Interpretation:

The complete mechanism is to be drawn for the given reaction. The major product of the reaction is to be predicted.

Concept introduction:

Aromatic compounds undergo electrophilic aromatic substitution reactions. The reaction is actually an addition-elimination rather than direct substitution. The mechanism consists of the addition of the incoming electrophile to a ring carbon, producing an arenium cation, with a positive charge on an adjacent carbon. The second step is the elimination of the proton from the same carbon where the electrophile is attached. When alternate sites are available, the electrophile preferentially attaches to the position that produces the most stable arenium cation.

Any substituents already present on the aromatic ring influence the position of substitution via their directing effect. Substituents that are electron-donating or weakly electron-withdrawing tend to direct the incoming electrophile to ortho-para positions. Substituents that are strongly electron-withdrawing tend to direct the incoming electrophile to meta positions.

In the case of substituted aromatic compounds containing more than one aromatic ring, the nature of existing substituents determines on which ring the further substitution will occur. An activating substuent will favor new substitution on the same ring while a deactivating substituent will favor new substitution on the other ring.

Electrophilic aromatic substitution on naphthalene generally favors substitution at the α-carbon over substitution at the β-carbon.

Expert Solution
Check Mark

Answer to Problem 23.65P

The complete mechanism for the given reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  1

The major product of the reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  2

Explanation of Solution

The given reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  3

The substrate has two aromatic rings, with an OH substituent on one ring. This is an activating substituent, with a resonance electron-donating ability. The OH will, therefore, activate the ring it is attached to. Also, as an electron-donating substituent, it is ortho-para directing. The para position is blocked, so the substitution must occur at one of the two ortho positions. Substitution at the ortho position closer to the second ring (α-carbon) is more likely as the arenium cation formed is more stable than if the substitution occurs at the other ortho position.

The incoming electrophile is +NO2, formed as a result of protonation and dehydration of HNO3 by the stronger acid H2SO4.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  4

The electrophile will add to the carbon ortho to the OH group, adjacent to the second ring to form an arenium cation.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  5

In the next step, a solvent molecule will extract the proton from that carbon. The CH bond pair will move toward the positively charged carbon to form a double bond to regain the aromatic character and form the final product.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  6

Therefore, the complete mechanism for the reaction can be drawn as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  7

The major product of the reaction will be

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  8

Conclusion

The mechanism and major product of the given reaction were determined on the basis of the existing substuents and their activating/deactivating nature.

Interpretation Introduction

(b)

Interpretation:

The complete mechanism is to be drawn for the given reaction. The major product of the reaction is to be predicted.

Concept introduction:

Aromatic compounds undergo electrophilic aromatic substitution reactions. The reaction is actually an addition-elimination rather than direct substitution. The mechanism consists of the addition of the incoming electrophile to a ring carbon, producing an arenium cation, with a positive charge on an adjacent carbon. The second step is the elimination of the proton from the same carbon where the electrophile is attached. When alternate sites are available, the electrophile preferentially attaches to the position that produces the most stable arenium cation.

Any substituents already present on the aromatic ring influence the position of substitution via their directing effect. Substituents that are electron-donating or weakly electron-withdrawing tend to direct the incoming electrophile to ortho-para positions. Substituents that are strongly electron-withdrawing tend to direct the incoming electrophile to meta positions.

In the case of substituted aromatic compounds containing more than one aromatic ring, the nature of existing substituents determines on which ring the further substitution will occur. An activating substuent will favor new substitution on the same ring while a deactivating substituent will favor new substitution on the other ring.

Electrophilic aromatic substitution on naphthalene generally favors substitution at the α-carbon over substitution at the β-carbon.

Expert Solution
Check Mark

Answer to Problem 23.65P

The complete mechanism for the given reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  9

The major product of the reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  10

Explanation of Solution

The given reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  11

The methyl substituent already present is electron-donating and, therefore, an activating substituent. The substitution will occur on the same ring. Methyl group is ortho-para directing. One of the ortho positions is blocked, so substitution can occur at the other ortho position or the para position. The para position is an α-carbon; therefore, substitution at this position is favored over substitution at the ortho position.

The incoming electrophile is generated as a result of the coordination of the acyl chloride with the Lewis acid AlCl3.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  12

The electrophile will add to the α-carbon of the unsubstituted ring in the first step, generating an arenium cation.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  13

In the next step, the ion formed in the initial step will extract a proton from the α-carbon, reforming the aromatic ring and the major product.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  14

Thus, the complete mechanism for the reaction can be drawn as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  15

And the major product will be

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  16

Conclusion

The mechanism and major product of the given reaction were determined on the basis of the existing substuents and their activating/deactivating nature.

Interpretation Introduction

(c)

Interpretation:

The complete mechanism is to be drawn for the given reaction. The major product of the reaction is to be predicted.

Concept introduction:

Aromatic compounds undergo electrophilic aromatic substitution reactions. The reaction is actually an addition-elimination rather than direct substitution. The mechanism consists of the addition of the incoming electrophile to a ring carbon, producing an arenium cation, with a positive charge on an adjacent carbon. The second step is the elimination of the proton from the same carbon where the electrophile is attached. When alternate sites are available, the electrophile preferentially attaches to the position that produces the most stable arenium cation.

Any substituents already present on the aromatic ring influence the position of substitution via their directing effect. Substituents that are electron-donating or weakly electron-withdrawing tend to direct the incoming electrophile to ortho-para positions. Substituents that are strongly electron-withdrawing tend to direct the incoming electrophile to meta positions.

In the case of substituted aromatic compounds containing more than one aromatic ring, the nature of existing substituents determines on which ring the further substitution will occur. An activating substuent will favor new substitution on the same ring while a deactivating substituent will favor new substitution on the other ring.

Electrophilic aromatic substitution on naphthalene generally favors substitution at the α-carbon over substitution at the β-carbon.

Expert Solution
Check Mark

Answer to Problem 23.65P

The complete mechanism of the reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  17

The major product is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  18

Explanation of Solution

The given reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  19

The nitro group already present is strongly electron-withdrawing, and therefore, a deactivating substituent. The substitution will occur on the other ring. On this ring, substitution at the α-carbon will be favored.

The incoming electrophile is generated as a result of the coordination of the bromine molecule with the Lewis acid FeBr3

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  20

The electrophile will add to the α-carbon to generate an arenium cation.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  21

In the next step, the FeBr4 will extract a proton from the α-carbon to reform the aromatic ring and produce the major product.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  22

Thus, the complete mechanism can be drawn as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  23

The major product will be

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  24

Conclusion

The mechanism and major product of the given reaction were determined on the basis of the existing substuents and their activating/deactivating nature.

Interpretation Introduction

(d)

Interpretation:

The complete mechanism is to be drawn for the given reaction. The major product of the reaction is to be predicted.

Concept introduction:

Aromatic compounds undergo electrophilic aromatic substitution reactions. The reaction is actually an addition-elimination rather than direct substitution. The mechanism consists of the addition of the incoming electrophile to a ring carbon, producing an arenium cation, with a positive charge on an adjacent carbon. The second step is the elimination of the proton from the same carbon where the electrophile is attached. When alternate sites are available, the electrophile preferentially attaches to the position that produces the most stable arenium cation.

Any substituents already present on the aromatic ring influence the position of substitution via their directing effect. Substituents that are electron-donating or weakly electron-withdrawing tend to direct the incoming electrophile to ortho-para positions. Substituents that are strongly electron-withdrawing tend to direct the incoming electrophile to meta positions.

In the case of substituted aromatic compounds containing more than one aromatic ring, the nature of existing substituents determines on which ring the further substitution will occur. An activating substuent will favor new substitution on the same ring while a deactivating substituent will favor new substitution on the other ring.

Electrophilic aromatic substitution on naphthalene generally favors substitution at the α-carbon over substitution at the β-carbon.

Expert Solution
Check Mark

Answer to Problem 23.65P

The complete mechanism for the given reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  25

The major product of the reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  26

Explanation of Solution

The given reaction is

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  27

The substituent already present is activating as the nitrogen can donate electrons to the ring. The substitution will, therefore, occur on the same ring. The electron-donating substituent is ortho-para directing. One of the ortho positions is aready blocked. Out of the remaining ortho position and the para position, a substitution at the para position will be favored as this is also the α-carbon of this ring.

The elecrophile is generated as a result of the coordination of the chlorine molecule with the Lewis acid FeCl3.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  28

The electrophile will add to the α-carbon of the substituted ring to generate an arenium cation.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  29

In the next step, +FeCl4 will extract the proton on the α-carbon to reform the aromatic ring and produce the major product.

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  30

Thus, the complete mechanism for the reaction can be drawn as

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  31

And the major product of the reaction will be

ORG.CHEM W/TEXT+SOLU.MANUAL, Chapter 23, Problem 23.65P , additional homework tip  32

Conclusion

The mechanism and major product of the given reaction were determined on the basis of the existing substuents and their activating/deactivating nature.

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Chapter 23 Solutions

ORG.CHEM W/TEXT+SOLU.MANUAL

Ch. 23 - Prob. 23.11PCh. 23 - Prob. 23.12PCh. 23 - Prob. 23.13PCh. 23 - Prob. 23.14PCh. 23 - Prob. 23.15PCh. 23 - Prob. 23.16PCh. 23 - Prob. 23.17PCh. 23 - Prob. 23.18PCh. 23 - Prob. 23.19PCh. 23 - Prob. 23.20PCh. 23 - Prob. 23.21PCh. 23 - Prob. 23.22PCh. 23 - Prob. 23.23PCh. 23 - Prob. 23.24PCh. 23 - Prob. 23.25PCh. 23 - Prob. 23.26PCh. 23 - Prob. 23.27PCh. 23 - Prob. 23.28PCh. 23 - Prob. 23.29PCh. 23 - Prob. 23.30PCh. 23 - Prob. 23.31PCh. 23 - Prob. 23.32PCh. 23 - Prob. 23.33PCh. 23 - Prob. 23.34PCh. 23 - Prob. 23.35PCh. 23 - Prob. 23.36PCh. 23 - Prob. 23.37PCh. 23 - Prob. 23.38PCh. 23 - Prob. 23.39PCh. 23 - Prob. 23.40PCh. 23 - Prob. 23.41PCh. 23 - Prob. 23.42PCh. 23 - Prob. 23.43PCh. 23 - Prob. 23.44PCh. 23 - Prob. 23.45PCh. 23 - Prob. 23.46PCh. 23 - Prob. 23.47PCh. 23 - Prob. 23.48PCh. 23 - Prob. 23.49PCh. 23 - Prob. 23.50PCh. 23 - Prob. 23.51PCh. 23 - Prob. 23.52PCh. 23 - Prob. 23.53PCh. 23 - Prob. 23.54PCh. 23 - Prob. 23.55PCh. 23 - Prob. 23.56PCh. 23 - Prob. 23.57PCh. 23 - Prob. 23.58PCh. 23 - Prob. 23.59PCh. 23 - Prob. 23.60PCh. 23 - Prob. 23.61PCh. 23 - Prob. 23.62PCh. 23 - Prob. 23.63PCh. 23 - Prob. 23.64PCh. 23 - Prob. 23.65PCh. 23 - Prob. 23.66PCh. 23 - Prob. 23.67PCh. 23 - Prob. 23.68PCh. 23 - Prob. 23.69PCh. 23 - Prob. 23.70PCh. 23 - Prob. 23.71PCh. 23 - Prob. 23.72PCh. 23 - Prob. 23.73PCh. 23 - Prob. 23.74PCh. 23 - Prob. 23.75PCh. 23 - Prob. 23.76PCh. 23 - Prob. 23.77PCh. 23 - Prob. 23.78PCh. 23 - Prob. 23.79PCh. 23 - Prob. 23.80PCh. 23 - Prob. 23.81PCh. 23 - Prob. 23.82PCh. 23 - Prob. 23.83PCh. 23 - Prob. 23.84PCh. 23 - Prob. 23.85PCh. 23 - Prob. 23.86PCh. 23 - Prob. 23.87PCh. 23 - Prob. 23.88PCh. 23 - Prob. 23.89PCh. 23 - Prob. 23.90PCh. 23 - Prob. 23.91PCh. 23 - Prob. 23.92PCh. 23 - Prob. 23.93PCh. 23 - Prob. 23.94PCh. 23 - Prob. 23.95PCh. 23 - Prob. 23.96PCh. 23 - Prob. 23.97PCh. 23 - Prob. 23.1YTCh. 23 - Prob. 23.2YTCh. 23 - Prob. 23.3YTCh. 23 - Prob. 23.4YTCh. 23 - Prob. 23.5YTCh. 23 - Prob. 23.6YTCh. 23 - Prob. 23.7YTCh. 23 - Prob. 23.8YTCh. 23 - Prob. 23.9YTCh. 23 - Prob. 23.10YTCh. 23 - Prob. 23.11YTCh. 23 - Prob. 23.12YTCh. 23 - Prob. 23.13YTCh. 23 - Prob. 23.14YT
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