General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Chapter 23, Problem 25E
To determine
The interference pattern of double slit.
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General Physics, 2nd Edition
Ch. 23 - Prob. 1RQCh. 23 - Prob. 2RQCh. 23 - Prob. 3RQCh. 23 - Prob. 4RQCh. 23 - Prob. 5RQCh. 23 - Prob. 6RQCh. 23 - Prob. 7RQCh. 23 - Prob. 8RQCh. 23 - Prob. 9RQCh. 23 - Prob. 10RQ
Ch. 23 - Prob. 11RQCh. 23 - Prob. 12RQCh. 23 - Prob. 1ECh. 23 - Prob. 2ECh. 23 - Prob. 3ECh. 23 - Prob. 4ECh. 23 - Prob. 5ECh. 23 - Prob. 6ECh. 23 - Prob. 7ECh. 23 - Prob. 8ECh. 23 - Prob. 9ECh. 23 - Prob. 10ECh. 23 - Prob. 11ECh. 23 - Prob. 12ECh. 23 - Prob. 13ECh. 23 - Prob. 14ECh. 23 - Prob. 15ECh. 23 - Prob. 16ECh. 23 - Prob. 17ECh. 23 - Prob. 18ECh. 23 - Prob. 19ECh. 23 - Prob. 20ECh. 23 - Prob. 21ECh. 23 - Prob. 22ECh. 23 - Prob. 23ECh. 23 - Prob. 24ECh. 23 - Prob. 25ECh. 23 - Prob. 26ECh. 23 - Prob. 27ECh. 23 - Prob. 28ECh. 23 - Prob. 29ECh. 23 - Prob. 30ECh. 23 - Prob. 31ECh. 23 - Prob. 32ECh. 23 - Prob. 33ECh. 23 - Prob. 34ECh. 23 - Prob. 35ECh. 23 - Prob. 36ECh. 23 - Prob. 37ECh. 23 - Prob. 38ECh. 23 - Prob. 39ECh. 23 - Prob. 40ECh. 23 - Prob. 41ECh. 23 - Prob. 42ECh. 23 - Prob. 43ECh. 23 - Prob. 44ECh. 23 - Prob. 45ECh. 23 - Prob. 46ECh. 23 - Prob. 47ECh. 23 - Prob. 48ECh. 23 - Prob. 49ECh. 23 - Prob. 50ECh. 23 - Prob. 51ECh. 23 - Prob. 52ECh. 23 - Prob. 53ECh. 23 - Prob. 54ECh. 23 - Prob. 55ECh. 23 - Prob. 56ECh. 23 - Prob. 57ECh. 23 - Prob. 58ECh. 23 - Prob. 59ECh. 23 - Prob. 60ECh. 23 - Prob. 61ECh. 23 - Prob. 62ECh. 23 - Prob. 63ECh. 23 - Prob. 64ECh. 23 - Prob. 65ECh. 23 - Prob. 66ECh. 23 - Prob. 67ECh. 23 - Prob. 68ECh. 23 - Prob. 69ECh. 23 - Prob. 70ECh. 23 - Prob. 71ECh. 23 - Prob. 72ECh. 23 - Prob. 73ECh. 23 - Prob. 74ECh. 23 - Prob. 75ECh. 23 - Prob. 76ECh. 23 - Prob. 77ECh. 23 - Prob. 78ECh. 23 - Prob. 79ECh. 23 - Prob. 80E
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- A diffraction pattern is produced on a screen 1.40 m from a single slit, using monochromatic light of wavelength 5.00 102 nm. The distance from the center of the central maximum to the first-order maximum is 3.00 mm. Calculate the slit width. Hint: Assume that the first-order maximum is halfway between the first- and second-order minima.arrow_forwardAn effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.30 m apart are powered by a single-function generator producing sine waves at 1200-Hz frequency. A student walks along a line 12.5 m away and parallel to the line between the speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is (a) the wavelength of this sound and (b) the distance between the central maximum and the first maximum (loud) position along this line?arrow_forwardMonochromatic light is incident on a pair of slits that are separated by 0.200 mm. The screen is 2.50 m away from the slits. a. If the distance between the central bright fringe and either of the adjacent bright fringes is 1.67 cm, find the wavelength of the incident light. b. At what angle does the next set of bright fringes appear?arrow_forward
- Coherent light of wavelength 501.5 nm is sent through two parallel slits in an opaque material. Each slit is 0.700 m wide. Their centers are 2.80 m apart. The light then falls on a semicylindrical screen, with its axis at the midline between the slits. We would like to describe the appearance of the pattern of light visible on the screen. (a) Find the direction for each two-slit interference maximum on the screen as an angle away from the bisector of the line joining the slits. (b) How many angles are there that represent two-slit interference maxima? (c) Find the direction for each single-slit interference minimum on the screen as an angle away from the bisector of the line joining the slits. (d) How many angles are there that represent single-slit interference minima? (e) How many of the angles in part (d) are identical to those in part (a)? (f) How many bright fringes are visible on the screen? (g) If the intensity of the central fringe is Imax, what is the intensity of the last fringe visible on the screen?arrow_forwardA double-slit experiment is to be set up so that the bright fringes appear 1.27 cm apart on a screen 2.13 m away from the two slits. The light source was wavelength 500 nm. What should be the separation between the two slits?arrow_forwardLight of wavelength 632.8 nm illuminates a single slit, and a diffraction pattern is formed on a screen 1.00 m from the slit. (a) Using the data in the following table, plot relative intensity versus position. Choose an appropriate value for the slit width a and, on the same graph used for the experimental data, plot the theoretical expression for the relative intensity IImax=sin22 where = (a sin )/. (b) What value of a gives the best fit of theory and experiment? Position Relative to Maximum (mm) Relative Intensity 0 1.00 0.8 0.95 1.6 0.80 3.2 0.39 4.8 0.079 6.5 0.003 8.1 0.036 9.7 0.043 11.3 0.013 12.9 0.000 3 14.5 0.012 16.1 0.015 17.7 0.004 4 19.3 0.000 3arrow_forward
- Show that the distribution of intensity in a double-slit pattern is given by Equation 36.9. Begin by assuming that the total magnitude of the electric field at point P on the screen in Figure 36.4 is the superposition of two waves, with electric field magnitudes E1=E0sintE2=E0sin(t+) The phase angle in in E2 is due to the extra path length traveled by the lower beam in Figure 36.4. Recall from Equation 33.27 that the intensity of light is proportional to the square of the amplitude of the electric field. In addition, the apparent intensity of the pattern is the time-averaged intensity of the electromagnetic wave. You will need to evaluate the integral of the square of the sine function over one period. Refer to Figure 32.5 for an easy way to perform this evaluation. You will also need the trigonometric identity sinA+sinB=2sin(A+B2)cos(AB2)arrow_forwardA beam of monochromatic green light is diffracted by a slit of width 0.550 mm. The diffraction pattern forms on a wall 2.06 m beyond the slit. The distance between the positions of zero intensity on both sides of the central bright fringe is 4.10 mm. Calculate the wavelength of the light.arrow_forwardTwo slits 4.0106 m apart are illuminated by light of wavelength 600 nm. What is the highest order fringe in the interference pattern?arrow_forward
- Red light (wavelength 632.8 nm in air) from a Helium-Neon laser is incident on a single slit of width 0.05 mm. The entire apparatus is immersed in water of refractive index 1.333. Determine the angular width of the central peak.arrow_forwardUltraviolet light of wavelength 350 nm is incident on a diffraction grating with slit spacing d and forms an interference pattern on a screen a distance L away. The angular positions bright of the interference maxima are large. The locations of the bright fringes are marked on the screen. Now red light of wavelength 700 nm is used with a diffraction grating to form another diffraction pattern on the screen. Will the bright fringes of this pattern be located at the marks on the screen if (a) the screen is moved to a distance 2L from the grating, (b) the screen is moved to a distance L/2 from the grating, (c) the grating is replaced with one of slit spacing 2d, (d) the grating is replaced with one of slit spacing d/2, or (e) nothing is changed?arrow_forwardThe intensity on the screen at a certain point in a double- slit interference pattern is 64.0% of the maximum value. (a) What minimum phase difference (in radians) between sources produces this result? (b) Express this phase difference as a path difference for 486.1-nm light.arrow_forward
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Spectra Interference: Crash Course Physics #40; Author: CrashCourse;https://www.youtube.com/watch?v=-ob7foUzXaY;License: Standard YouTube License, CC-BY