DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 23, Problem 2P
Calculate the rpm
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5.) Calculate the machining time required to reduce from 60mm diameter shaft to 50mm diameter, for a length of 1500mm with depth of cut 2mm for rough cut and 1mm for finish cut. Cutting speed and feed may be assumed as 30m/min and 0.5mm/rev respectively.
Figure and table given below shows the design details of a taper turning operation with a cutting speed of 22 m/ minute, feed 0.2 mm/ revolution; Depth of cut of 0.5 mm.
(c) Time for n passes to complete taper turning in minutes .
The cutting speed in in/min of a 12 mm drill operating at 600 rpm is nearly equal to
Chapter 23 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 23 - How is the tool-work relationship in turning...Ch. 23 - What different kinds of surfaces can be produced...Ch. 23 - How does form turning differ from ordinary...Ch. 23 - What is the basic difference between facing and a...Ch. 23 - Which operations shown in Figure 23.3 do not form...Ch. 23 - Why is it difficult to make heavy cuts if a form...Ch. 23 - Show how equation 23.6 is an approximate equation.Ch. 23 - Why is the spindle of the lathe hollow?Ch. 23 - What function does a lathe carriage have?Ch. 23 - Why is feed specified for a boring operation...
Ch. 23 - Why are depths of cut in boring usually smaller...Ch. 23 - How can work be held and supported in a lathe?Ch. 23 - How is a workpiece that is mounted between centers...Ch. 23 - What will happen to the workpiece when turned, if...Ch. 23 - Why is it not advisable to hold hot-rolled steel...Ch. 23 - How does a steady rest differ from a follow rest?Ch. 23 - What are the advantages and disadvantages of a...Ch. 23 - Why should the distance the cutting tool overhangs...Ch. 23 - Prob. 19RQCh. 23 - How can a tapered part be turned on a lathe?Ch. 23 - Why might it be desirable to use a heavy depth of...Ch. 23 - If the rpm for a facing cut (assuming given work...Ch. 23 - Why is it usually necessary to take relatively...Ch. 23 - How does the corner radius of the tool influence...Ch. 23 - What effect does a BUE have on the diameter of the...Ch. 23 - How does the multiple-spindle screw machine differ...Ch. 23 - Why does boring ensure concentricity between the...Ch. 23 - Why are vertical spindle machines better suited...Ch. 23 - Prob. 29RQCh. 23 - Prob. 30RQCh. 23 - In which figures in this chapter is a dead center...Ch. 23 - Prob. 32RQCh. 23 - In which figures in this chapter showing setups do...Ch. 23 - How many form tools are being utilized in the...Ch. 23 - Prob. 35RQCh. 23 - Select the speed, feed, and depth of cut for...Ch. 23 - Calculate the rpm NS to run the spindle on a lathe...Ch. 23 - The lathe in problem 2 has rpm settings of 20, 30,...Ch. 23 - Calculate the cutting time if the length of cut is...Ch. 23 - Calculate the metal removal rate for machining at...Ch. 23 - Determine the speed, feed, and depth of cut when...Ch. 23 - At a speed of 90 fpm, feed of 0.030 ipr, and depth...Ch. 23 - Calculate the cutting time for a 4-in. length of...Ch. 23 - For a boring operation at V=90,fr=0.030, and...Ch. 23 - A cutting speed of 100 sfpm has been selected for...Ch. 23 - The following data apply for machining a part on a...Ch. 23 - A finish cut for a length of 10 in. on a diameter...Ch. 23 - A workpiece 10 in. in diameter is to be faced down...Ch. 23 - A hole 89 mm in diameter is to be drilled and...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- In a turning operation, the operator has established that a single pass on the cylindrical workpiece must be completed in 5.0 min. The piece is 400 mm long and 150 mm in diameter. Using a feed of 0.30 mm / rev and a depth of cut of 4.0 mm, what speed of cut should be used to meet this machining time?arrow_forward1.) On a lathe, a cylindrical work piece of 100mm diameter is being turned. The RPM is 100. The cutting speed is _________?(m/min)arrow_forwardFind the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by using a carbide insert. If the approach length and over run length is taken as 5 mm, Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mmarrow_forward
- For the operation of straight turning in a lathe machine, the diameter of the workpiece is 80 mm, the length is 0.12 m, the cutting speed is 80 m / min, the feed is 0.5 mm / rev and the depth of cut is 0.002 m . Find the material removing rate and the time of machining.arrow_forwardIn an orthogonal cutting operation an 8 mm deep groove is to be turned on a 50 mm diameter steel bar. Spindle speed is 300 rpm and a feed rate of 0.25 mm/rev is given to the tool. Produced chips have a width of 2 mm. Calculate the material removal rate at the beginning and at the end of the cut. Can u help me please?arrow_forwardIn face milling, assume that the Diameter of the cutter is 200 mm, the width of the block is 60 mm, and the length of the block is 344 mm, if the depth of cut is 3 mm, = 0.6 mm/min, and N = 100 rpm. The cutter has 12 inserts, and the workpiece material is bronze. Calculate the estimated power required, the cutting force, and the torque.arrow_forward
- What is the feed speed (mm/min) of an end milling cutter if it mills a distance of 300 mm in ten minutes? What is the feed per tooth if it is rotating at 800 rpm?arrow_forwardFigure and table given below shows the design details of a taper turning operation with a cutting speed of 22 m/ minute, feed 0.2 mm/ revolution; Depth of cut of 0.5 mm. Using the given data find the following. (d) Time for single pass "Tsingle" in minutesarrow_forwardIn an orthogonal turning process, the chip thickness is 0.32 mm , feed is 0.2 mm/rev, then calculate the cutting ratio.arrow_forward
- During orthogonal cutting of MS with a 10 ° rake angle tool, the chip thickness ratio was obtained as 0.4. Calculate shear anglearrow_forwardCalculate the machining time required for making 60 holes on an MS plate of 80 mm thickness with a drillbit of diameter 20 mm with a cutting speed V= 40 m/min, the feed f = 0.2 mm/rev. (Assume approach length,A and over run O as 2mm and point angle as 110o). Calculate material removal rate.arrow_forwardFigure and table given below shows the design details of a taper turning operation with a cutting speed of 22 m/ minute, feed 0.2 mm/ revolution; Depth of cut of 0.5 mm. Using the given data find the following. (a) Diameter "D" in mm . (b) Spindle speed in rpm. (c) Time for n passes to complete taper turning in minutes.arrow_forward
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