Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919



Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem

Checkpoint 4 Worked-out solution available at

At time t = 0, a diver jumps from a diving board that is 12 feet high with an initial velocity of 16 feet per second. The diver’s position function is s = −16t2 + 16t + 12.

a. When does the diver hit the water?

b. What is the diver’s velocity at impact?


To determine

To calculate: The time when the diver hits the water, when at time t=0 the diver jumps from the diving board which is 12 feet high with an initial velocity of 16 feet per second. The diver's position function is modeled by s=16t2+16t+12.


Given Information:

At time t=0 the diver jumps from the diving board which is 12 feet high with an initial velocity of 16 feet per second and the diver's position function is modeled by s=16t2+16t+12.

Formula used:

Zero product law:

If ab=0 then either a=0 or b=0.

Where a, b belongs to set of real numbers.


The position function of the diver is given by


To find the time when the diver hits the water, substitute s=0 in the function s=16t2+16t+12.


Factor out (4) from the left side of the equation


It can be further si


To determine

To calculate: The velocity at impact when the diver hits the water where the diver's position function is given by s=16t2+16t+12

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