Interpretation:
The chemical composition of pig iron should be determined.
Concept introduction:
An alloy is a type of substance that made by the melting of two or more elements together. In the alloy, at least one the element is a metal. The components of the alloy cannot be separated by the physical process.
The examples of alloy are brass, bronze, pig iron, chromite ore, ferromanganese, stainless steel, blister copper etc.
Interpretation:
The composition of ferromanganese alloy should be determined.
Concept introduction:
An alloy is a type of substance that made by the melting of two or more elements together. In the alloy, at least one the element is a metal. The components of the alloy cannot be separated by the physical process.
Interpretation:
The composition of chromite ore should be determined.
Concept introduction:
A type of naturally occurring rock or solid material which contains minerals with important elements including metals is said to be an ore.
(d)
Interpretation:
The composition of brass should be determined.
Concept introduction:
An alloy is a type of substance that made by the melting of two or more elements together. In the alloy, at least one the element is a metal. The components of the alloy cannot be separated by the physical process.
(e)
Interpretation:
The composition of aqua regia should be determined.
Concept introduction:
An alloy is a type of substance that made by the melting of two or more elements together. In the alloy, at least one the element is a metal. The components of the alloy cannot be separated by the physical process.
(f)
Interpretation:
The composition of blister copper should be determined.
Concept introduction:
An alloy is a type of substance that made by the melting of two or more elements together. In the alloy, at least one the element is a metal. The components of the alloy cannot be separated by the physical process.
(g)
Interpretation:
The composition of in stainless steel should be determined.
Concept introduction:
An alloy is a type of substance that made by the melting of two or more elements together. In the alloy, at least one the element is a metal. The components of the alloy cannot be separated by the physical process.
Trending nowThis is a popular solution!
Chapter 23 Solutions
GENERAL CHEMISTRY-MOD.MASTERINGCHEM.
- Write detailed answers to the following.a. Discuss the structure of diborane.b. Explain how silicon is used in the preparation of solar cell.arrow_forwardGaseous F2reacts with water to form HF and O₂,. In NaOH solution, F₂, forms F⁻, water, and oxygen difluoride (OF₂,), ahighly toxic gas and powerful oxidizing agent. The OF₂, reacts with excess OH, forming O₂,, water, and F⁻. (a) For each reac-tion, write a balanced equation, give the oxidation state of O inall compounds, and identify the oxidizing and reducing agents.(b) Draw a Lewis structure for OF₂,, and predict its shape.arrow_forwardWhich is larger, the band of Si or that of AIP. why?arrow_forward
- (a) Write the electronic configuration of Cu2+ (Atomic No of Cu=29) (b) Explain Cr has the configurations (Ar) 4s1 3d5 rather than (Ar) 4s2 3d4 (C)HF has 19°C whereas H2O has a of 100°Carrow_forwardA 0.4740-g pesticide sample was decomposed by wet ashing and then diluted to 200.0 mL in a volumetric flask. The analysis was completed by treating aliquots of this solution as indicated. Calculate the percentage of copper in the sample.arrow_forwardThe lanthanide elements react with oxygen to give compounds of the type Ln2O3 (where Ln standsfor a lanthanide element). However, there are interesting exceptions, such as a common oxide of terbium,TbxOy. a) Given that the compound is73.945% Tb, what is its formula? b) What is the oxidation number ofterbium in this compound? c) Write a balanced equation for the reaction of terbium andoxygen to give this oxide. Also indicate the physical states of all the reagents and product/s. Alstoichiometric coefficients must be whole numbers.arrow_forward
- Why is the highest oxidation state observed for CrCl4 onlythe +4 oxidation state, in contrast to the +6 stateobserved in CrF6?arrow_forwardChlorine reacts with oxygen to form Cl2O7. (a) What is thename of this product ? (b) Write a balancedequation for the formation of Cl2O7(l) from the elements.(c) Would you expect Cl2O7 to be more reactive towardH+(aq) or OH-(aq)? (d) If the oxygen in Cl2O7 is consideredto have the -2 oxidation state, what is the oxidation state ofthe Cl? What is the electron configuration of Cl in this oxidationstate?arrow_forwardWhat is the dominant iron species in water samples ? What environmental factors may have contributed. why is it necesseyy to to investigate Fe3+ concentration and total Fe concentration dpeedtaely ? Why do we need to do the sample to determine total Fe concentration ? And how did then determine Fe2+ concentration?arrow_forward
- The main reason alkali metal dihalides (MX₂) do notformis the high IE₂ of the metal. (a) Why is IE₂ so high for alkalimetals? (b) The IE2for Cs is 2255 kJ/mol, low enough for CsF₂to form exothermically (ΔHf=-125 kJ/mol). This compoundcannot be synthesized, however, because CsF forms with a muchgreater release of heat (ΔHf=-530 kJ/mol). Thus, the break-down of CsF₂ to CsF happens readily. Write the equation for thisbreakdown, and calculate the heat of reaction per mole of CsF.arrow_forwardThe diameter of a rubidium atom is 4.95 A° . We will considertwo different ways of placing the atoms on a surface. In arrangementA, all the atoms are lined up with one anotherto form a square grid. Arrangement B is called a close-packedarrangement because the atoms sit in the “depressions”formed by the previous row of atoms:(a) Using arrangement A, how many Rb atoms could be placedon a square surface that is 1.0 cm on a side? (b) How many Rbatoms could be placed on a square surface that is 1.0 cm on aside, using arrangement B? (c) By what factor has the numberof atoms on the surface increased in going to arrangement Bfrom arrangement A? If extended to three dimensions, whicharrangement would lead to a greater density for Rb metal?arrow_forwardThe diameter of a rubidium atom is 4.95 A° . We will considertwo different ways of placing the atoms on a surface. In arrangementA, all the atoms are lined up with one anotherto form a square grid. Arrangement B is called a close-packedarrangement because the atoms sit in the “depressions”formed by the previous row of atoms: (a) Using arrangement A, how many Rb atoms could be placedon a square surface that is 1.0 cm on a side? (b) How many Rbatoms could be placed on a square surface that is 1.0 cm on aside, using arrangement B? (c) By what factor has the numberof atoms on the surface increased in going to arrangement Bfrom arrangement A? If extended to three dimensions, whicharrangement would lead to a greater density for Rb metal?arrow_forward
- Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co