BIOLOGY
4th Edition
ISBN: 9781266739606
Author: Hoefnagels
Publisher: MCG
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Question
Chapter 23.5, Problem 2MC
Summary Introduction
To describe:
The purpose of two control solutions.
Concept introduction:
Carnivorous plants have the mechanism to trap insects and are adapted to digest the protein matter contained in insects. They feature a deep cavity filled with liquid, insects such as flies are attracted to this cavity, often by color and by the nectar within.
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Describe and discuss which factors influence the choice of bioreactor design?(in long explanation please)
The following data, presented by G. Bowes and W. L. Ogre in J. Biol. Chem.
(1972) 247:2171-2176, describe the relative rates of incorporation of CO, by
Rubisco under N, and under pure Oz. Decide whether Oz is a competitive or
uncompetitive inhibitor.
[CO] (mM)
Under N2
Under O2
0.20
16.7
10
0.10
12.5
5.6
0.067
8.3
4.2
0.050
7.1
3.2
Find the control Vmax and Km value, and use this to find the Vmax apparent for inhibitor A.
Chapter 23 Solutions
BIOLOGY
Ch. 23.1 - Prob. 1MCCh. 23.1 - How do plants acquire C, H, O, N, and P?Ch. 23.1 - Prob. 3MCCh. 23.2 - Prob. 1MCCh. 23.2 - Prob. 2MCCh. 23.2 - Prob. 3MCCh. 23.3 - Prob. 1MCCh. 23.3 - Prob. 2MCCh. 23.3 - Prob. 3MCCh. 23.4 - Prob. 1MC
Ch. 23.4 - Prob. 2MCCh. 23.5 - Prob. 1MCCh. 23.5 - Prob. 2MCCh. 23.5 - Prob. 3MCCh. 23 - What is the difference between a macronutrient and...Ch. 23 - Prob. 2MCQCh. 23 - Prob. 3MCQCh. 23 - Prob. 4MCQCh. 23 - Prob. 5MCQCh. 23 - Prob. 6MCQCh. 23 - Prob. 7MCQCh. 23 - Prob. 8MCQCh. 23 - Explain the relationship between transpiration and...Ch. 23 - Prob. 2WIOCh. 23 - Prob. 3WIOCh. 23 - Prob. 4WIOCh. 23 - Prob. 5WIOCh. 23 - Prob. 6WIOCh. 23 - Prob. 7WIOCh. 23 - Prob. 8WIOCh. 23 - Prob. 9WIOCh. 23 - Prob. 10WIOCh. 23 - Prob. 11WIOCh. 23 - Prob. 12WIOCh. 23 - Prob. 13WIOCh. 23 - Prob. 14WIOCh. 23 - Prob. 15WIOCh. 23 - Prob. 1PITCh. 23 - Prob. 2PITCh. 23 - Prob. 3PIT
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- Calculate, or make a best estimate of, the unknown factors in the situations listed in Table 1. Table 1. Data for problem 1. To find Data (i) Ek [K+]out = 4 mM; [K+]in = 130 mM (ii) [Cl-]in [Cl-]out = 570 mM; ECl = -65 mV (iii) ECl [Cl-]out = 150 mM; [Cl-]in = 8 mM; in a mammal (iv) [Na+]in Overshoot of action potential = +35 mV; saline [Na+] = 112 mM (v) [K+]in Blood [K+] = 3.2 mM; undershoot of action potential = -87 mV (vi) ECa [Ca2+]out = 5.6 mM; free [Ca2+]in = 0.8 mM (vii) [K+]out [K+]in = 350 mM; Ek = -82 mVarrow_forwardThe following data, presented by G. Bowes and W. L. Ogre in J. Biol. Chem. (1972) 247:2171–2176, describe the relative rates of incorporation of CO2 by Rubisco under N2 and under pure O2. Decide whether O2 is a competitive or uncompetitive inhibitor.arrow_forwardCompounds I, II, and III are in the following biochemical pathway: precursor compound I enzyme A enzyme B compound II ► compound III enzyme Mutation a inactivates enzyme A, mutation b inactivates enzyme B, and mutation c inactivates enzyme C. Mutants, each having one of these defects, were tested on minimal medium to which compound I, II, or III was added. Fill in the results expected of these tests by placing a plus sign (+) for growth or a minus sign (-) for no growth in the table below. Minimal medium to which is added Strain with mutation Compound I Compound II Compound IIIarrow_forward
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