Concept explainers
Interpretation:
The fact that 2, 2, 6-trimethylcyclohexanone yields no detectable aldol product even though it has an acidic α-hydrogen is to be explained.
Concept introduction:
To explain:
The fact that 2, 2, 6-trimethylcyclohexanone yields no detectable aldol product even though it has an acidic α-hydrogen.
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Chapter 23 Solutions
Bundle: Organic Chemistry, Loose-leaf Version, 9th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
- Show the products you would obtain by acid-catalyzed reaction of cyclohexanone with ethylamine, CH3CH2NH2, and with diethylamine, (CH3CH2) 2NH.arrow_forwardThe Meerwein-Ponndorf-Verley reaction involves reduction of a ketone by treatment with an excess of aluminum triisopropoxide, [(CH3)2CHO]3Al. The mechanism of the process is closely related to the Cannizzaro reaction in that a hydride ion acts as a leaving group. Propose a mechanism.arrow_forwardTreatment of an aldehyde or ketone with cyanide ion (-:C=N), followed by protonation of the tetrahedral alkoxide ion intermediate, gives a cyanohydrin. Show the structure of the cyanohydrin obtained from cyclohexanone.arrow_forward
- Propose a mechanism to account for the formation of 3, 5-dimethyl- pyrazole from hydrazine and 2, 4-pentanedione. Look carefully to see what has happened to each carbonyl carbon in going from starting material to product.arrow_forwardIn the mixed Claisen reaction of cyclopentanone with ethyl formate, a much higher yield of the desired product is obtained by first mixing the two carbonyl components and then adding base, rather than by first mixing base with cyclopentanone and then adding ethyl formate. Explain.arrow_forwardShow the products from reaction of p-bromoaniline with the following reagents: (a) CH3I (excess) (b) HCl (c) HNO2, H2SO4 (d) CH3COCl (e) CH3MgBr (f) CH3CH2Cl, AlCl3 (g) Product of (c) with CuCl, HCl (h) Product of (d) with CH3CH2Cl, AlCl3arrow_forward
- Propose a mechanism for the following reaction: 2 C5H11OH <---> C5H11-O-C5H11 + H2O (pentan-1-ol <---> di-n-pentyl ether + water) Why is this the major product rather than 1-pentene?arrow_forwardThe base-promoted rearrangement of an a-haloketone to a carboxylic acid, known as the Favorskii rearrangement, is illustrated by the conversion of 2-chlorocyclohexanone to cyclopentanecarboxylic acid. Jo Han Sow La NaOH, THF O Nat H3O+ OH NaOH, THF The mechanism involves the following 5 steps: -ō cyclopropanone intermediate 1. Abstraction of a proton to form enolate anion 1; 2. Formation of a cyclopropanone intermediate 2 with expulsion of chloride ion; 3. Addition of hydroxide ion to form tetrahedral intermediate 3; 4. Collapse of the tetrahedral intermediate and breakage of the three-membered ring to form carbanion intermediate 4; 5. Proton transfer to form the rearranged carboxylic acid. For the following reaction, draw the reaction out on paper, and then draw the structure of cyclopropanone intermediate 2 in the window. 1. NaOH, THF 2. H3O* OHarrow_forwardshow the generation of the electrophile and predict the products.(a) benzene + cyclohexene + HFarrow_forward