Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133559897
Author: KALPAKJIAN
Publisher: PEARSON
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Chapter 24, Problem 43QTP
A 12-in.-long, 1-in.-thick plate is being cut on a band saw at 150 ft/min. The saw has 12 teeth per inch. If the feed per tooth is 0.003 inch, how long will it take to saw the plate along its length?
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An orthogonal cutting operation is being carried out under the following conditions: t0=0.38 mm, tc=0.65 mm, width of the cut= 2.5 mm, V=3.5 m/s, rake angle=6°, Fc= 515 N, and Ft=210 N. Calculate the percentage of the total energy that is dissipated in the shear plane.
2 1.57 Show that, for the same shear angle, there are two rake angles that give the same cutting ratio.
A mild steel block of width 40 mm is being milled using a straight slab cutter 70 mm diameter with 30 teeth. If the cutter rotates at 40 rpm, and depth of cut is 2 mm, what is the value of maximum uncut chip thickness when the table feed is 20 mm/min?
Chapter 24 Solutions
Manufacturing Engineering & Technology
Ch. 24 - Explain why milling is such a versatile machining...Ch. 24 - Describe a milling machine. How is it different...Ch. 24 - Describe the different types of cutters used in...Ch. 24 - Define the following: face milling, peripheral...Ch. 24 - Can threads be machined on a mill? Explain.Ch. 24 - What is the difference between feed and feed per...Ch. 24 - Explain the relative characteristics of climb...Ch. 24 - Describe the geometric features of a broach and...Ch. 24 - What is a pull broach? A push broach?Ch. 24 - Why is sawing a commonly used process? Why do some...
Ch. 24 - What advantages do bed-type milling machines have...Ch. 24 - Explain why the axis of a hob is tilted with...Ch. 24 - What is a shell mill? Why is it used?Ch. 24 - Why is it difficult to saw thin sheet metals?Ch. 24 - Of the processes depicted in Fig. 24.2, which is...Ch. 24 - Describe the tool motion during gear shaping.Ch. 24 - When is filing necessary?Ch. 24 - Would you consider the machining processes...Ch. 24 - Why is end milling such an important versatile...Ch. 24 - List and explain factors that contribute to poor...Ch. 24 - Explain why broaching crankshaft bearings is an...Ch. 24 - Several guidelines are presented in this chapter...Ch. 24 - What are the advantages of helical teeth over...Ch. 24 - Explain why hacksaws are not as productive as band...Ch. 24 - What similarities and differences are there in...Ch. 24 - Why do machined gears have to be subjected to...Ch. 24 - How would you reduce the surface roughness shown...Ch. 24 - Why are machines such as the one shown in Fig....Ch. 24 - Comment on your observations concerning the...Ch. 24 - Explain how contour cutting could be started in a...Ch. 24 - Prob. 32QLPCh. 24 - Describe the parts and conditions under which...Ch. 24 - Explain the reason that it is difficult to use...Ch. 24 - Would you recommend broaching a keyway on a gear...Ch. 24 - Prob. 37QTPCh. 24 - A slab-milling operation is being performed at a...Ch. 24 - Show that the distance lc in slab milling is...Ch. 24 - Prob. 40QTPCh. 24 - Calculate the chip depth of cut, tc, and the...Ch. 24 - Estimate the time required to face mill a...Ch. 24 - A 12-in.-long, 1-in.-thick plate is being cut on a...Ch. 24 - A single-thread hob is used to cut 40 teeth on a...Ch. 24 - Assume that m the face-milling operation shown in...Ch. 24 - A slab-milling operation will take place on a part...Ch. 24 - Prob. 47QTPCh. 24 - In describing the broaching operations and the...Ch. 24 - The parts shown in Fig. 24.1 are to be machined...Ch. 24 - Would you prefer to machine the part in Fig. 24....Ch. 24 - Prob. 51SDPCh. 24 - Suggest methods whereby milling cutters of various...Ch. 24 - Prepare a comprehensive table of the process...Ch. 24 - Prob. 55SDPCh. 24 - Make a list of all the processes that can be used...
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- Find the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by using a carbide insert. If the approach length and over run length is taken as 5 mm, Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mmarrow_forward21.53 An orthogonal cutting operation is being carried out under the following conditions: to = 0.1 mm, tc = 0.2 mm, width of cut = 4 mm, V = 3 m/s, rake angle = 10°, Fc = 500 N, and Ft = 200 N. Calculate the percentage of the total energy that is dissipated in the shear plane.arrow_forwardIn orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool. the cutting velocity is 90 m/min The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm If the orthogonal rake angle is zero and the principal cutting edge angle is 90° Calculate the shear angle in degree.arrow_forward
- Write down the steps required to proof the mathematical relation for SHEAR PLANE ANGLE in Orthogonal Cutting Model. i-e. Prove the following relation:arrow_forward2 1.49 Assume that, in orthogonal cutting, the rake angle is 15° and the coefficient of friction is 0.2. Using Eq. (21.4),determine the percentage increase in chip thickness when the friction is doubled.arrow_forward2 1.46 Explain why the power requirements in cutting depend on the cutting force but not the thrust force.arrow_forward
- A bar of 70 mm diameter is being cut orthogonally and is reduced to 68 mm by cutting tool in case mean length of the chip is 68.9 mm. find the cutting ratio determine shear angle also if the rake angle is 10 degree.arrow_forwardFind the time required for one full cut on a work piece of 350mm long and 20 mm in diameter. The cutting speed is 30 meters per minute and the feed is 0.5mm per revolution. Average. SHOW YOUR SOLUTION WITH DRAWINGSarrow_forwardNote: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.arrow_forward
- Assuming that the coefficient of friction is 0.25, calculate the maximum depth of cut forturning a hard aluminium alloy on a 15-kW lathe (with a mechanical efficieny of 80%) at awidth of cut of 6 mm, rake angle of 0˚, and a cutting speed of 90 m/min, shear strength of 150 MPa.arrow_forwardIn orthogonal turning of a bar 100 mm diameter with a feed of 0.25 mm/rev., depth of cut = 4 mm, cutting velocity = 90 m/min. it is observed that the main cutting force is perpendicular to friction force acting at the chip tool interface and cutting force is 1500 N. find (i) rake angle (ii) normal force.arrow_forwardA student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy= 1200 ksi. If the width of cut is 0.30 in. and the student set a rake angle of 0° and a cutting speed of 200 ft/ min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?arrow_forward
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