Physics
Physics
5th Edition
ISBN: 9781260486919
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 24, Problem 49P

(a)

To determine

The distance between the lenses.

(a)

Expert Solution
Check Mark

Answer to Problem 49P

The distance between the lenses is 19.0cm.

Explanation of Solution

From problem 48P, image distance for the eyepiece is 25.0 cm and the image distance for the objective 16.5cm and focal length of eyepiece is 2.80cm.

Write the lens equation for the eyepiece.

  1pe+1qe=1fe

Here, pe is the object distance for the eyepiece, qe is the image distance for the eyepiece, and fe is the focal length of the eyepiece.

Rearrange above equation to get pe.

  pe=(1fe1qe)1                                                                                                      (I)

Write the expression for the distance between the lenses.

  d=qo+pe                                                                                                              (II)

Here, d is the distance between lenses and qo is the image distance for the objective.

Conclusion:

Substitute 2.80cm for fe and 25.0cm for qe in equation (I) to get pe.

  pe=(12.80cm125.0cm)1=2.518cm=2.52cm

Substitute 2.52cm for pe and 16.5cm for qo in equation (II) to get d.

  d=16.5cm+2.52cm=19.0cm

Therefore, the distance between the lenses is 19.0cm.

(b)

To determine

The angular magnification.

(b)

Expert Solution
Check Mark

Answer to Problem 49P

The angular magnification of the microscope is 318.

Explanation of Solution

Write the angular magnification for the eyepiece.

  Me=Npe                                                                                                                 (III)

Here, Me is the angular magnification of eyepiece and N is the near point.

Write the expression for the transverse magnification of the objective.

  mo=qopo                                                                                                             (IV)

Here, mo is the transverse magnification of the objective and po is the object distance for the objective lens.

Write the lens equation for objective lens.

  1po+1qo=1fo

Here, fo is the focal length objective lens.

Rearrange above equation to get 1po.

  1po=1fo1qo                                                                                                          (V)

Substitute 1fo1qo for 1po in equation (IV) to get mo.

  mo=qo(1fo1qo)

Write the expression for total magnification.

  Mtotal=moMe                                                                                                         (VI)

Substitute qo(1fo1qo) for mo and Npe for Me in equation (VI) to get Mtotal.

  Mtotal=qo(1fo1qo)×Npe                                                                                  (VII)

Conclusion:

Substitute 16.5cm for qo, 5.00mm for fo, 25.0cm for N and 2.518cm for pe in equation (VII) to get Mtotal.

  Mtotal=(16.5cm)(15.00mm1 cm10 mm116.5cm)×25.0cm2.518cm=318

Therefore, the angular magnification of the microscope is 318.

(c)

To determine

The distance from the objective at which the object should be placed to get the final image at viewer’s near point.

(c)

Expert Solution
Check Mark

Answer to Problem 49P

The distance from the objective at which the object should be placed to get the final image at viewer’s near point is 5.16mm.

Explanation of Solution

Rearrange equation (V) to get p0.

  po=(1fo1qo)1                                                                                                 (VIII)

Conclusion:

Substitute 16.5cm for qo and 5.00mm for fo in equation (VIII) to get po.

  po=(15.00mm116.5cm×10mm1cm)1=5.16mm

Therefore, the distance from the objective at which the object should be placed to get the final image at viewer’s near point is 5.16mm.

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Chapter 24 Solutions

Physics

Ch. 24.5 - Prob. 24.7PPCh. 24.6 - Prob. 24.6CPCh. 24.6 - Prob. 24.8PPCh. 24 - Prob. 1CQCh. 24 - Prob. 2CQCh. 24 - Prob. 3CQCh. 24 - Prob. 4CQCh. 24 - Prob. 5CQCh. 24 - Prob. 6CQCh. 24 - Prob. 7CQCh. 24 - Prob. 8CQCh. 24 - Prob. 9CQCh. 24 - 10. For human eyes, about 70% of the refraction...Ch. 24 - Prob. 11CQCh. 24 - Prob. 12CQCh. 24 - Prob. 13CQCh. 24 - Prob. 14CQCh. 24 - Prob. 15CQCh. 24 - Prob. 16CQCh. 24 - Prob. 17CQCh. 24 - Prob. 18CQCh. 24 - Prob. 19CQCh. 24 - Prob. 1MCQCh. 24 - Prob. 2MCQCh. 24 - Prob. 3MCQCh. 24 - Prob. 4MCQCh. 24 - Prob. 5MCQCh. 24 - Prob. 6MCQCh. 24 - Prob. 7MCQCh. 24 - Prob. 8MCQCh. 24 - Prob. 9MCQCh. 24 - Prob. 10MCQCh. 24 - Prob. 1PCh. 24 - Prob. 2PCh. 24 - Prob. 3PCh. 24 - Prob. 4PCh. 24 - Prob. 5PCh. 24 - Prob. 6PCh. 24 - Prob. 7PCh. 24 - Prob. 8PCh. 24 - Prob. 9PCh. 24 - Prob. 10PCh. 24 - Prob. 11PCh. 24 - Prob. 12PCh. 24 - Prob. 13PCh. 24 - Prob. 14PCh. 24 - Prob. 15PCh. 24 - Prob. 16PCh. 24 - Prob. 17PCh. 24 - Prob. 18PCh. 24 - Prob. 19PCh. 24 - Prob. 20PCh. 24 - Prob. 21PCh. 24 - Prob. 22PCh. 24 - Prob. 23PCh. 24 - Prob. 24PCh. 24 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 30PCh. 24 - 31. Suppose the distance from the lens to the...Ch. 24 - 32. ✦ Veronique is nearsighted; she cannot see...Ch. 24 - Prob. 33PCh. 24 - Prob. 35PCh. 24 - Prob. 37PCh. 24 - Prob. 36PCh. 24 - Prob. 38PCh. 24 - Prob. 34PCh. 24 - Prob. 39PCh. 24 - Prob. 40PCh. 24 - Prob. 41PCh. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - Prob. 45PCh. 24 - Prob. 46PCh. 24 - Prob. 47PCh. 24 - Prob. 48PCh. 24 - Prob. 49PCh. 24 - Prob. 50PCh. 24 - Prob. 51PCh. 24 - Prob. 52PCh. 24 - Prob. 53PCh. 24 - Prob. 54PCh. 24 - Prob. 55PCh. 24 - Prob. 56PCh. 24 - Prob. 57PCh. 24 - Prob. 58PCh. 24 - Prob. 59PCh. 24 - Prob. 61PCh. 24 - Prob. 60PCh. 24 - 62. ✦ The eyepiece of a Galilean telescope is a...Ch. 24 - Prob. 63PCh. 24 - Prob. 64PCh. 24 - Prob. 65PCh. 24 - Prob. 66PCh. 24 - Prob. 67PCh. 24 - Prob. 68PCh. 24 - Prob. 69PCh. 24 - Prob. 70PCh. 24 - Prob. 71PCh. 24 - Prob. 72PCh. 24 - Prob. 73PCh. 24 - Prob. 74PCh. 24 - Prob. 75PCh. 24 - Prob. 76PCh. 24 - Prob. 77PCh. 24 - Prob. 78PCh. 24 - Prob. 79PCh. 24 - Prob. 80PCh. 24 - Prob. 81PCh. 24 - Prob. 82PCh. 24 - Prob. 83PCh. 24 - Prob. 84PCh. 24 - Prob. 85PCh. 24 - 86. (a) What is the angular size of the Moon as...Ch. 24 - Prob. 86P
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