The cyclic hemiacetal formed for the given hydroxyaldehyde in acidic condition should be drawn. Concept introduction: Hemiacetal are formed for the compound having both hydroxyl group and aldehyde group in acidic condition. The –OH group of compound attacks the carbonyl group of the same compound, thereby a ring is formed by the carbon atoms and oxygen atom of –OH group with incorporating into the ring. To determine: the size of the ring (hemiacetal) formed by the given molecule.

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Answer 1

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 24.5, Problem 1LTS

Interpretation Introduction

Interpretation:

The cyclic hemiacetal formed for the given hydroxyaldehyde in acidic condition should be drawn.

Concept introduction:

Hemiacetal are formed for the compound having both hydroxyl group and aldehyde group in acidic condition.

The –OH group of compound attacks the carbonyl group of the same compound, thereby a ring is formed by the carbon atoms and oxygen atom of –OH group with incorporating into the ring.

To determine: the size of the ring (hemiacetal) formed by the given molecule.

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Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 24.5, Problem 1LTS

Interpretation Introduction

Interpretation:

The cyclic hemiacetal formed for the given hydroxyaldehyde in acidic condition should be drawn.

Concept introduction:

Hemiacetal are formed for the compound having both hydroxyl group and aldehyde group in acidic condition.

The –OH group of compound attacks the carbonyl group of the same compound, thereby a ring is formed by the carbon atoms and oxygen atom of –OH group with incorporating into the ring.

To determine: the size of the ring (hemiacetal) formed by the given molecule.

Expert Solution & Answer

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Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 24.5, Problem 1LTS

Interpretation Introduction

Interpretation:

The cyclic hemiacetal formed for the given hydroxyaldehyde in acidic condition should be drawn.

Concept introduction:

Hemiacetal are formed for the compound having both hydroxyl group and aldehyde group in acidic condition.

The –OH group of compound attacks the carbonyl group of the same compound, thereby a ring is formed by the carbon atoms and oxygen atom of –OH group with incorporating into the ring.

To determine: the size of the ring (hemiacetal) formed by the given molecule.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 24.5, Problem 1LTS

Interpretation Introduction