ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<
ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<
9th Edition
ISBN: 9781337034623
Author: McMurry
Publisher: CENGAGE C
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Chapter 25.SE, Problem 26VC
Interpretation Introduction

a)

Interpretation:

The configurational stereochemistry of the molecules to be determined.

Expert Solution
Check Mark

Answer to Problem 26VC

The Fischer projection follows as

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 25.SE, Problem 26VC , additional homework tip  1

It is D sugar the molecule is a retrose. Elclose or eldotetrose, is 4-carbon elclose.

Explanation of Solution

Concept strategy: The Fischer projection of the given monosaccharide is drawn vertically, by rotating the molecule anticlockwise 90° so that the carbonyl aldehyde -CHO group is vertically at the top and the CH2OH group is at the bottom. [The red balls represent oxygen atoms, the black balls represent carbon atoms, and each smell white ball represents hydrogen]. The intention –H and –OH are drawn to the sides, pointing art of the page towards the review. Thus the given model becomes

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 25.SE, Problem 26VC , additional homework tip  2

Review from front side C-3-OH is to the right By convention the molecule has the C-3 hyduxyl at the right. So it is D sugar the molecule is a retrose. Elclose or eldotetrose, is 4-carbon elclose.

Conclusion

Based on the Fischer projection formula for the given sugars it is a B-D-glucopyranose monosaccharide.

Interpretation Introduction

b)

Interpretation:

The configurational stereochemistry of the molecules to be determined.

Expert Solution
Check Mark

Answer to Problem 26VC

The given model is the cyclic structures of an aldohexose in six membered pyranose form.

Strategy: We redraw the model as

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 25.SE, Problem 26VC , additional homework tip  3

Explanation of Solution

By convention, the terminal -CH2OH group is on the top of the chair Pyranose structure. Thus it is a D sugar. The molecule is an aldohexose is B-D-glucopyranose, all the –OH groups are equatorial (and more stable due to minimum repulsion) conformation.

Conclusion

Based on the Fischer projection formula for the given sugars it is a B-D-glucopyranose monosaccharide.

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Students have asked these similar questions
Trehalose, C12H22O11, is a nonreducing sugar that is only 45% as sweet as sugar. When hydrolyzed by aqueous acid or the enzyme maltase, it formsonly d-glucose. When it is treated with excess methyl iodide in the presence of Ag2O and then hydrolyzed with water under acidic conditions, only2,3,4,6-tetra-O-methyl-d-glucose is formed. Draw the structure of trehalose.
3 Trehalose is a disaccharide that can be obtained from fungi, sea urchins and insects. Acid hydrolysis of trehalose yields only D-glucose. Trehalose is hydrolysed by α-glucosidase and not by β-glucosidase enzymes. Methylation of trehalose followed by hydrolysis yields two molar equivalents of2,3,4,6-tetra-O-methyl-D-glucopyranose.From the following experimental data, deduce the structure of trehalose.What will be the effect of trehalose on Fehling’s solution?
Treatment of D-glucose with NaBH4 gives an alditol A. What L-aldohexose also yields A when treated with NaBH4?

Chapter 25 Solutions

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