BIOCHEM-ACHIEVE(FIRST DAY DISCOUNTED)
9th Edition
ISBN: 2818000069358
Author: BERG
Publisher: MAC HIGHER
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Question
Chapter 26, Problem 24P
Interpretation Introduction
Interpretation:
The mechanism for the change of glutamine codon (CAA) into a stop codon should be determined.
Concept introduction:
A codon can be defined as a sequence of three DNA or RNA
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Translation. Write the anti-codon sequence of the MRNA transcript. Translate the
MRNA transcript into peptide sequence using both the 3 letter abbreviation and 1 letter
abbreviation.
ANTI-CODON
3'
5'
SEQUENCE
AMINO ACID
N-
C-
SEQUENCE (3 letter terminus
Abbreviation)
Terminus
AMINO ACID
N-
C-
SEQUENCE (1 letter terminus
Abbreviation)
Terminus
An extra piece. In one type of mutation leading to a form of
thalassemia, the mutation of a single base (G to A) generates a new 3'
3' splice site (blue in the illustration below) akin to the normal one
(yellow) but farther upstream.
Normal 3' end
of intron
5' CCTATTGGTCTATTITCCACCCITAGGCTGCTG 3'
5' CCTATTAGTCTAIIIICCACCCTTAGGCTGCTG 3'
What is the amino acid sequence of the extra segment of protein
synthesized in a thalassemic patient having a mutation leading to
aberrant splicing? The reading frame after the splice site begins with
TCT.
Leaderless. The MRNA for the A repressor begins with 5'-AUG-3',
5'-AUG-3', which encodes the methionine residue that begins the
protein. What is unusual about this beginning? Would it cause the
MRNA to translate efficiently or not?
Chapter 26 Solutions
BIOCHEM-ACHIEVE(FIRST DAY DISCOUNTED)
Ch. 26 - Prob. 1PCh. 26 - Prob. 2PCh. 26 - Prob. 3PCh. 26 - Prob. 4PCh. 26 - Prob. 5PCh. 26 - Prob. 6PCh. 26 - Prob. 7PCh. 26 - Prob. 8PCh. 26 - Prob. 9PCh. 26 - Prob. 10P
Ch. 26 - Prob. 11PCh. 26 - Prob. 12PCh. 26 - Prob. 13PCh. 26 - Prob. 14PCh. 26 - Prob. 15PCh. 26 - Prob. 16PCh. 26 - Prob. 17PCh. 26 - Prob. 18PCh. 26 - Prob. 19PCh. 26 - Prob. 20PCh. 26 - Prob. 21PCh. 26 - Prob. 22PCh. 26 - Prob. 23PCh. 26 - Prob. 24PCh. 26 - Prob. 25PCh. 26 - Prob. 26PCh. 26 - Prob. 27PCh. 26 - Prob. 28PCh. 26 - Prob. 29PCh. 26 - Prob. 30PCh. 26 - Prob. 31PCh. 26 - Prob. 32PCh. 26 - Prob. 33PCh. 26 - Prob. 34PCh. 26 - Prob. 35PCh. 26 - Prob. 36PCh. 26 - Prob. 37PCh. 26 - Prob. 38PCh. 26 - Prob. 39PCh. 26 - Prob. 40PCh. 26 - Prob. 41PCh. 26 - Prob. 42PCh. 26 - Prob. 43PCh. 26 - Prob. 44PCh. 26 - Prob. 45PCh. 26 - Prob. 46PCh. 26 - Prob. 47P
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- Im just lost and confused. Please help mearrow_forwardTrue or False. Explain. A) At no time during protein synthesis does an amino acid make direct contact with the mRNA being translated. B) Because the two strands of DNA are complementary, the mRNA of a gene can be synthesized using either strand as a template.arrow_forwardTRUE or FALSE. If false, write the word/s that make(s) the statement incorrect. 1. The Kozak sequence can be found 10 bases before the start codon. 2. Simultaneous transcription and translation occurs in prokaryotes only.arrow_forward
- Be sure to answer all parts. Write a possible mRNA sequence that codes for each peptide. a. His-Cys-Tyr-Val-Ser 5¹- b. Phe-Val-Thr-Tyr-Glu 5'- 5'- c. Trp-Phe-Asn-Gln -3' U -3' с Table 26.2 The Genetic Code-Triplets in Messenger RNA First Base (5' end) -3' U UUU UUC UUA UUG CUU CUC CUA CUG AUL Phe Phe Leu Leu Leu Leu Leu Leu la C UCU UCC UCA UCG CCU CCC CCA CCG Second Base A UAU UAC UAA UAG CAU CAC CAA CAG Ser Ser Ser Ser Pro Pro Pro Pro Tyr 55 Tyr Stop Stop His His Gin Gin G UGU UGC UGA UGG CGU CGC CGA CGG Cys Cys Stop Trp Arg Arg Arg Arg Third Base (3¹ ond) DUAC DU AG с А Аarrow_forwardPolymerase inhibition. Cordycepin inhibits poly(A) synthesis at low concentrations and RNA synthesis at higher concentrations. NH2 H. он Cordycepin (3'-deoxyadenosine) a. What is the basis of inhibition by cordycepin? b. Why is poly(A) synthesis more sensitive than the synthesis of other RNAS to the presence of cordycepin? c. Does cordycepin need to be modified to exert its effect?arrow_forwardtRNA enzyme. Any given aminoacyl-tRNA synthetase: a. Attaches the amino acid to the 5′-end '5end of the tRNA b. Always recognizes only one specific tRNA c. Recognizes all tRNA molecules d. Forms an ester linkage between the amino acid and the tRNAarrow_forward
- AAAGAGAAAAGAAUA to AAAGAGAAAUGAAUA. Suppose the codon sequence has a single base pair mutation If the old protein sequence was Lys-Glu-Lys-Arg-Ile, what will be the new sequence encoded by the mutant gene? (Use the 3-letter amino acid abbreviations with hyphens and no spaces in between, i.e. Ser-Asn-Tyr-Leu-Pro.) Submit Answer Retry Entire Group No more group attempts remainarrow_forwardPlease answer. ASAP. Thank you!arrow_forwardNo options are there.Fill up blanks by your knowledge.arrow_forward
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