Organic Chemistry, Books a la Carte Plus Mastering Chemistry with Pearson eText -- Access Card Package (8th Edition)
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Chapter 26, Problem 34P

The amino acid sequences of peptide fragments obtained from a normal protein were compared with those obtained from the same protein synthesized by a defective gene. They were found to differ in only one peptide fragment. Their amino acid sequences are shown here:

Normal: Gln-Tyr-Gly-Thr-Arg-Tyr-Val

Mutant: Gln-Ser-Glu-Pro-Gly-Thr

  1. a. What is the defect in DNA?
  2. b. It was later determined that the normal peptide fragment is an octapeptide with a C-terminal Val-Leu. What is the C-terminal amino acid of the mutant peptide?
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A peptide has the sequence   Glu–His–Trp–Ser–Gly–Leu–Arg–Pro–Gly   The p?a values for the peptide’s side chains, terminal amino groups, and carboxyl groups are provided in the table. Amino acid Amino pKa Carboxyl pKa Side‑chain pKa glutamate 9.609.60 2.342.34 4.254.25 histidine 9.179.17 1.821.82 6.006.00 tryptophan 9.399.39 2.382.38   serine 9.159.15 2.212.21   glycine 9.609.60 2.342.34   leucine 9.609.60 2.362.36   arginine 9.049.04 2.172.17 12.4812.48 proline 10.9610.96 1.991.99       Calculate the net charge of the molecule at pH 11 and estimate the isoelectric point (pI)(pI) for this peptide.
5 ased on molecular weights of purified (no beta-Me) and (beta-Me) sample, which are 97.4 kDa and 47.2 kDa, what can be said about the number and size of the protein monomers, as well as the nature of the bonds holding together the complete quaternary structure of the proteins?

Chapter 26 Solutions

Organic Chemistry, Books a la Carte Plus Mastering Chemistry with Pearson eText -- Access Card Package (8th Edition)

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