Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 26, Problem 38P
Interpretation Introduction
Interpretation:
The reason for the modification of proteins by the covalent linking of a farnesyl or a geranylgeranyl unit to the carboxyl-terminal cysteine residue should be determined.
Concept introduction:
Phospholipids are the basic constituent of all cell membranes. They usually form lipid bilayers. The structure of a phospholipid molecule has a tail made up of two hydrophobic fatty acid and a hydrophilic head comprising of a phosphate group.
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resting state of the protein, the Lys 216 Schiff base has pKa = 9.5 and Asp 85 has pKa = 3.5. When the conformational change occurs, the proton that was on the Schiff base moves to Asp 85. This should tell you that one or both of these two pKas
changed with the conformational change. How does the pKa of Asp 85 compare with the pKa of the Lys 216 Schiff base after the conformational change?
cip sequence rule in ephedrine
Upload a drawing of Gly-Met-Asn-Glu-His
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Chapter 26 Solutions
Biochemistry
Ch. 26 - Prob. 1PCh. 26 - Prob. 2PCh. 26 - Prob. 3PCh. 26 - Prob. 4PCh. 26 - Prob. 5PCh. 26 - Prob. 6PCh. 26 - Prob. 7PCh. 26 - Prob. 8PCh. 26 - Prob. 9PCh. 26 - Prob. 10P
Ch. 26 - Prob. 11PCh. 26 - Prob. 12PCh. 26 - Prob. 13PCh. 26 - Prob. 14PCh. 26 - Prob. 15PCh. 26 - Prob. 16PCh. 26 - Prob. 17PCh. 26 - Prob. 18PCh. 26 - Prob. 19PCh. 26 - Prob. 20PCh. 26 - Prob. 21PCh. 26 - Prob. 22PCh. 26 - Prob. 23PCh. 26 - Prob. 24PCh. 26 - Prob. 25PCh. 26 - Prob. 26PCh. 26 - Prob. 27PCh. 26 - Prob. 28PCh. 26 - Prob. 29PCh. 26 - Prob. 30PCh. 26 - Prob. 31PCh. 26 - Prob. 32PCh. 26 - Prob. 33PCh. 26 - Prob. 34PCh. 26 - Prob. 35PCh. 26 - Prob. 36PCh. 26 - Prob. 37PCh. 26 - Prob. 38PCh. 26 - Prob. 39PCh. 26 - Prob. 40PCh. 26 - Prob. 41PCh. 26 - Prob. 42PCh. 26 - Prob. 43PCh. 26 - Prob. 44PCh. 26 - Prob. 45PCh. 26 - Prob. 46PCh. 26 - Prob. 47P
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