Concept explainers
(a)
Position of the final image.
(a)
Answer to Problem 53P
The image is
Explanation of Solution
Consider the mirror and write the equation for radius of curvature
Here,
Rearrange (I) in terms of
The image of the mirror serves as the object for the lens.
The object distance for the lens would be
Write the mirror equation.
Here
Rewrite (III) in terms of
The final image will be at a distance
Conclusion:
Substitute
Substitute
Substitute
Thus the final image will be at
(b)
Whether the image is real or virtual
(b)
Answer to Problem 53P
The image is virtual.
Explanation of Solution
The sign of image distance decides the nature of the image.\
The positive sign indicates that the image is real. Negative sign suggests that the image is virtual
Conclusion:
As the image distance is
(c)
Whether the image is upright or inverted..
(c)
Answer to Problem 53P
The image is upright.
Explanation of Solution
Sign of magnification decides whether the image is upright or inverted.
If magnification is positive, image is upright. If magnification is negative the image is inverted,
Write the equation for magnification mirror and lens
Write the equation for overall magnification
Conclusion:
Substitute
Substitute
Substitute
As the magnification is positive, the image is upright.
(d)
Overall magnification of the image.
(d)
Answer to Problem 53P
Magnification is
Explanation of Solution
Refer sub part (c) and write the equation for overall magnification
Conclusion:
Substitute
Magnification is
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Chapter 26 Solutions
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