Concept explainers
(a)
Position of the image.
(a)
Answer to Problem 70P
The image distance is
Explanation of Solution
Write the mirror equation.
Here,
Rearrange (I) in terms of
The real image is the object of second lens.
Here
Write the mirror equation for lens 2.
Here
Rewrite (IV) in terms of
Conclusion:
Substitute
Substitute
Substitute
The image distance is
(b)
Magnification of the final image.
(b)
Answer to Problem 70P
Magnification is
Explanation of Solution
Write the equation for magnification for two lenses.
Write the equation for overall magnification
Conclusion:
Substitute
Substitute
Substitute
Magnification is
(c)
Whether the image is upright or inverted.
(c)
Answer to Problem 70P
The image is inverted.
Explanation of Solution
Sign of magnification decides whether the image is upright or inverted.
If magnification is positive, image is upright. If magnification is negative the image s inverted
Conclusion:
As the magnification is
(d)
Nature of the image for a given condition.
(d)
Answer to Problem 70P
The image would be inverted at a distance
Overall magnification is
Explanation of Solution
The ray diagram is as shown
Refer sub part (a) and (b) and to determine the image position and magnification
Conclusion:
Substitute
Substitute
Substitute
As the overall magnification is negative, the image is inverted.
The image would be inverted at a distance
Overall magnification is
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Chapter 26 Solutions
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