ORGANIC CHEMISTRY (LOOSELEAF)
ORGANIC CHEMISTRY (LOOSELEAF)
6th Edition
ISBN: 9781260475630
Author: SMITH
Publisher: MCG
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Chapter 26, Problem 63P
Interpretation Introduction

Interpretation: The stepwise mechanism for the isomerization of D-glucose to form the given compounds is to be drawn.

Concept introduction: Carbohydrates are naturally occurring organic compounds. The monosaccharide glucose is called an Aldohexose as it contains six carbon atoms as well as an aldehyde functional group and fructose is known as ketohexose as it contains six carbons with a ketone functional group.

Glucose and mannose are C2 epimers that is they differ in position of hydroxyl group at second carbon atom.

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The following isomerization reaction, drawn using D-glucose as starting material, occurs with all aldohexoses in the presence of base. Draw a stepwise mechanism that illustrates how each compound is formed. сно сно сно CH2OH C=0 H- OH H- -OH но- H- но H- "OH но H- Но H- но H- H- -H- H20 H- HO- O- H- -O- H- -OH -O- OH ČHOH CH,OH ČH2OH ČH2OH (recovered starting material) D-glucose
All are true or false  a)In solution, glucose is in the cyclic acetal form only. b)The driving force for the Wittig reaction is the elimination of triphenylphosphine oxide c)1H NMR spectroscopy, you can tell the difference between an aldehyde and a ketone because an aldehyde has a proton signal between 9–10 ppm. d)When an aldehyde is reacted with excess ethanol with an acid as a catalyst it is called hemiacetal e) You can't use acidic conditions (such as aqueous hydrochloric acid) for the addition of a Grignard reagent to a ketone because the ketone will be protonated and thus unreactive
The following isomerization reaction, drawn using D-glucose as starting material, occurs with all aldohexoses in the presence of base. Draw a stepwise mechanism that illustrates how each compound is formed.

Chapter 26 Solutions

ORGANIC CHEMISTRY (LOOSELEAF)

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