Physics
Physics
5th Edition
ISBN: 9781260486919
Author: GIAMBATTISTA
Publisher: MCG
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Question
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Chapter 26, Problem 63P

(a)

To determine

To show that γ1<<1 implies that v<<c, which means that v can be considered a nonrelativistic speed.

(a)

Expert Solution
Check Mark

Answer to Problem 63P

It is showed that γ1<<1 implies that v<<c, which means that v can be considered a nonrelativistic speed.

Explanation of Solution

Write the statement given in the problem.

  γ1<<1

Here, γ is the Lorentz factor.

Rearrange above inequality to get range of γ.

  γ<<2                                                                                                                    (I)

Write the expression for γ.

  γ=11v2c2

Here, v is the relativistic velocity and c is the speed of light in vacuum.

Substitute 11v2c2 for γ in expression (I) to expand relation to show that v<<c.

  11v2c2<<21(1v2c2)<<41<<44v2c2

Rearrange above inequality to get v<<c.

  v2<<3c24<c2v<<c

Conclusion:

Thus, it is showed that, γ1<<1 implies that v<<c, which means that v can be considered a nonrelativistic speed.

(b)

To determine

To show that K<<mc2 implies that v<<c, which means that v can be considered a nonrelativistic speed.

(b)

Expert Solution
Check Mark

Answer to Problem 63P

It is showed that K<<mc2 implies that v<<c, which means that v can be considered a nonrelativistic speed.

Explanation of Solution

Write the statement given in the problem.

  K<<mc2                                                                                                                (II)

Here, K is the kinetic energy, m is the rest mass of the particle.

Write expression for the relativistic kinetic energy of a particle

  K=(γ1)mc2                                                                                                      (III)

Write (γ1)mc2 for K in inequality (II) to expand the equation

  (γ1)mc2<<mc2

Divide both side of above inequality by mc2 to show γ1<<1.

  (γ1)<<1

In part (a) it is showed that if (γ1)<<1, then v<<c. Thus, K<<mc2 .

Conclusion:

Therefore, it is showed that K<<mc2 implies that v<<c, which means that v can be considered a nonrelativistic speed.

(c)

To determine

To show that p<<mc implies that v<<c, which means that v can be considered a nonrelativistic speed.

(c)

Expert Solution
Check Mark

Answer to Problem 63P

It is showed that p<<mc implies that v<<c, which means that v can be considered a nonrelativistic speed.

Explanation of Solution

Write the statement given in the problem.

  p<<mc                                                                                                                 (IV)

Here, p is the relativistic momentum.

Write expression for the relativistic momentum of a particle.

  p=γmv                                                                                                                  (V)

Write γmv for p in inequality (IV) to expand the equation

  γmv<<mc

Divide both side of above inequality by mγ to show v<<c.

  v<<cγ                                                                                                                  (VI)

Since v<c , 1γ<1.

Rearrange inequality (VI) to get v<<c.

  v<<cγ<cv<<c

Conclusion:

Therefore, it is showed that p<<mc implies that v<<c, which means that v can be considered a nonrelativistic speed.

(d)

To determine

To show that Kp22m implies that v<<c, which means that v can be considered a nonrelativistic speed.

(d)

Expert Solution
Check Mark

Answer to Problem 63P

It is showed that Kp22m implies that v<<c, which means that v can be considered a nonrelativistic speed.

Explanation of Solution

Write the statement given in the problem.

  Kp22m                                                                                                               (VII)

Rearrange above expression to get p2.

  p22mK                                                                                                           (VIII)

Multiply both sides of above expression with c2.

  p2c22Kmc2

Replace p2c2 with K2+2KE0 and mc2 with E0 to get K.

  K2+2KE02KE0K0                                                                                               (IX)

From equation (III) K=(γ1)mc2.

Substitute (γ1)mc2 for K in expression (IX) to get γ.

  (γ1)mc20γ1

Substitute 11v2c2 for γ in above expression to show that v<<c.

  11v2c21v2c20v<<c

Conclusion:

Therefore ,it is showed that Kp22m implies that v<<c, which means that v can be considered a nonrelativistic speed.

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Chapter 26 Solutions

Physics

Ch. 26 - Prob. 1CQCh. 26 - Prob. 2CQCh. 26 - Prob. 3CQCh. 26 - Prob. 4CQCh. 26 - Prob. 5CQCh. 26 - Prob. 6CQCh. 26 - Prob. 7CQCh. 26 - Prob. 8CQCh. 26 - Prob. 9CQCh. 26 - Prob. 10CQCh. 26 - Prob. 11CQCh. 26 - Prob. 12CQCh. 26 - Prob. 1MCQCh. 26 - Prob. 2MCQCh. 26 - Prob. 3MCQCh. 26 - Prob. 4MCQCh. 26 - 5. Which best describes the proper time interval...Ch. 26 - Prob. 6MCQCh. 26 - Prob. 7MCQCh. 26 - Prob. 8MCQCh. 26 - Prob. 9MCQCh. 26 - Prob. 1PCh. 26 - Prob. 2PCh. 26 - Prob. 3PCh. 26 - Prob. 4PCh. 26 - Prob. 5PCh. 26 - Prob. 6PCh. 26 - Prob. 7PCh. 26 - Prob. 8PCh. 26 - Prob. 9PCh. 26 - Prob. 10PCh. 26 - Prob. 11PCh. 26 - Prob. 12PCh. 26 - Prob. 13PCh. 26 - Prob. 14PCh. 26 - Prob. 15PCh. 26 - Prob. 16PCh. 26 - Prob. 17PCh. 26 - Prob. 18PCh. 26 - Prob. 19PCh. 26 - Prob. 20PCh. 26 - Prob. 21PCh. 26 - Prob. 22PCh. 26 - Prob. 23PCh. 26 - Prob. 24PCh. 26 - Prob. 25PCh. 26 - Prob. 26PCh. 26 - Prob. 27PCh. 26 - Prob. 28PCh. 26 - Prob. 29PCh. 26 - Prob. 30PCh. 26 - Prob. 31PCh. 26 - Prob. 32PCh. 26 - Prob. 33PCh. 26 - Prob. 34PCh. 26 - Prob. 35PCh. 26 - Prob. 36PCh. 26 - Prob. 37PCh. 26 - Prob. 38PCh. 26 - Prob. 39PCh. 26 - 40. A white dwarf is a star that has exhausted its...Ch. 26 - Prob. 41PCh. 26 - Prob. 42PCh. 26 - Prob. 43PCh. 26 - Prob. 44PCh. 26 - Prob. 45PCh. 26 - Prob. 46PCh. 26 - Prob. 47PCh. 26 - Prob. 48PCh. 26 - Prob. 49PCh. 26 - Prob. 50PCh. 26 - Prob. 51PCh. 26 - Prob. 52PCh. 26 - Prob. 53PCh. 26 - Prob. 54PCh. 26 - Prob. 55PCh. 26 - Prob. 56PCh. 26 - Prob. 57PCh. 26 - Prob. 58PCh. 26 - Prob. 59PCh. 26 - Prob. 60PCh. 26 - Prob. 61PCh. 26 - Prob. 62PCh. 26 - Prob. 63PCh. 26 - Prob. 64PCh. 26 - Prob. 65PCh. 26 - Prob. 66PCh. 26 - Prob. 67PCh. 26 - Prob. 68PCh. 26 - Prob. 69PCh. 26 - 70. At the 10.0 km long Stanford Linear...Ch. 26 - Prob. 71PCh. 26 - Prob. 72PCh. 26 - Prob. 73PCh. 26 - Prob. 74PCh. 26 - Prob. 75PCh. 26 - Prob. 76PCh. 26 - Prob. 77PCh. 26 - Prob. 78PCh. 26 - Prob. 79PCh. 26 - Prob. 80PCh. 26 - Prob. 81PCh. 26 - Prob. 82PCh. 26 - Prob. 83PCh. 26 - Prob. 84PCh. 26 - Prob. 85PCh. 26 - Prob. 87PCh. 26 - Prob. 86PCh. 26 - Prob. 89PCh. 26 - Prob. 88PCh. 26 - Prob. 90PCh. 26 - Prob. 92PCh. 26 - Prob. 91PCh. 26 - Prob. 94PCh. 26 - Prob. 93PCh. 26 - 96. The solar energy arriving at the outer edge of...Ch. 26 - Prob. 96PCh. 26 - Prob. 97PCh. 26 - Prob. 98P
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