   Chapter 2.7, Problem 11E ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343

#### Solutions

Chapter
Section ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343
Textbook Problem

# (a) A particle starts by moving to the right along a horizontal line; the graph of its position function is shown in the figure. When is the particle moving to the right? Moving to the left? Standing still?(b) Draw a graph of the veloc.ity function. (a)

To determine

To state: The position at which the particle is moving to the right, moving to the left and standing still on the time intervals.

Explanation

Formula used:

The average velocity over the time interval [a,a+h] is,

Average velocity=displacementtime

=f(a+h)f(a)(a+h)a (1)

Note 1: The average velocity is same as the instantaneous velocity when the particle is moving along a straight line.

Note 2: The particle is moving to the right when the velocity is positive.

Note 3: The particle is moving to the left when the velocity is negative.

Note 4: The particle is standing still when the velocity is zero.

Calculation:

At the time interval (0, 1):

From the given graph, it is observed that the straight line is passing through the points (0, 0) and (1,3).

Substitute (0, 0) for (a,f(a)) and (1,3) for (a+h,f(a+h)) in equation (1),

Average velocity=3010=31=3

Thus, the average velocity of the particle moving along a straight line is 3 m/s.

By Note 1, the velocity of the particle on the time interval (0, 1) is 3 m/s.

By Note 2, the particle is moving to the right on the time interval (0, 1) since the velocity is positive.

Thus, the particle is moving to the right when s(t) is increasing on the interval (0, 1).

At the time interval (1, 2):

From the given graph, it is observed that the straight line is passing through the points (1, 3) and (2,3).

Substitute (1, 3) for (a,f(a)) and (2,3) for (a+h,f(a+h)) in equation (1),

Average velocity=3321=01=0

Thus, the average velocity of the particle moving along a straight line is 0 m/s.

By Note 1, the velocity of the particle on the time interval (1, 2) is 0 m/s.

By Note 4, the particle is standing still on the time interval (1, 2), since the velocity is zero.

Thus, the particle is standing still when s(t) is constant on the interval (1, 2).

At the time interval (2, 3):

From the given graph, it is observed that the straight line is passing through the points (2, 3) and (3,1)

(b)

To determine

To sketch: The graph of the velocity function.

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Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 