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How much time would be required to shape a flat surface 254 mm (1 in.) wide and 203 mm (8 in.) long on a hydraulic drive shaper, using a cutting speed of 45-7 m (150 ft)per minute, a feed of 0.51 mm (0.020 in.) per stroke, and an overrun of
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- 21.36 Why does the temperature in cutting depend on the cutting speed, feed, and depth of cut? Explain in terms of the relevant process variables.arrow_forward21.53 An orthogonal cutting operation is being carried out under the following conditions: to = 0.1 mm, tc = 0.2 mm, width of cut = 4 mm, V = 3 m/s, rake angle = 10°, Fc = 500 N, and Ft = 200 N. Calculate the percentage of the total energy that is dissipated in the shear plane.arrow_forwardMachining time required reduce a mild steel rod of diameter 60mm, initial length (L) 125mm to final length (L1) 120mm to 58 mm by turning a carbide insert. If the approach length and over run length are 5 mm and 1 mm respectively, take Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mmarrow_forward
- If a fairing operation is executed at a rotational speed of 40.0 rev / min, the feed is 0.015 in / rev and the depth of cut is 0.180 in, it determines: a) cutting time to complete the fairing operation; and b) the cutting speed; and c) The speed of metal removal at the beginning and end of the cut d) The power dissipated.arrow_forwardAssume that, in orthogonal cutting, the rake angle, oz,is 20° and the friction angle, B, is 35° at the chip-tool interface.Determine the percentage change in chip thickness when the friction angle is 50°. (Note: do not use Eq. (21.3)arrow_forward21.51 Taking carbide as an example and using Eq. (21.24), determine how much the feed should be reduced in order to keep the mean temperature constant when the cutting speed is doubled.arrow_forward
- Find the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by using a carbide insert. If the approach length and over run length is taken as 5 mm, Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mmarrow_forward21.56 Assume that, in orthogonal cutting, the rake angle,α , is 20° and the friction angle, β , is 35° at the chip–tool interface. Determine the percentage change in chip thickness when the friction angle is 45°. [Note: do not use Eq. (21.4) or Eq. (21.5).]arrow_forwardA tool with zero rake angle used in orthogonal cutting when its clearance angle a is changed from 10 to 7 deg, Calculate the approximate % change in the life of the tool.arrow_forward
- Precision Machining Technology (MindTap Course Li...Mechanical EngineeringISBN:9781285444543Author:Peter J. Hoffman, Eric S. Hopewell, Brian JanesPublisher:Cengage Learning