   Chapter 2.7, Problem 25E

Chapter
Section
Textbook Problem

Sketch the graph of a function q that is continuous on its domain (–5, 5) and where g(0) = 1, g'(0) = 1, g'(– 2) = 0, lim x → − 5 + g ( x ) = ∞ ,   a n d   lim x → 5 − g ( x ) = 3.

To determine

To sketch: The graph of a function g.

Explanation

Given:

The function f(x) is continuous on its domain (5,5).

The values. g(0)=1,g(0)=1,g(2)=0,limx5+g(x)=, and limg(x)=3x5.

Calculation:

Here given value g(0)=1,

That is, the point of the graph of the function g(x) is (0,1)

Note that, f(a) means that the slope of the tangent to the function f(x) at the point (a,f(a)).

The given value g(2)=0.

That is, the slopes of tangent to the function g(x) at (2,g(2)) are zero.

Note that, the slope zero at a point means horizontal tangent line at that point.

Thus, the graph of the function g(x) has horizontal tangent at (2,g(2)).

Note that, the value f(a) means that the instantaneous rate of change of y=f(x) at x when x=a

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 