(a) Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a C − H bond is to be shown. Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

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Answer 1

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Chapter 27, Problem 27.46P

Interpretation Introduction

(a)

Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a C−H bond is to be shown.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Interpretation Introduction

(b)

Interpretation: The reasons as to why 2−methylcyclopenta−1,3−diene is not formed directly from 5−methylcyclopenta−1,3−diene by a [1,3] rearrangement.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

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A solution of 5-methylcyclopenta-1,3-diene rearranges at roomtemperature to a mixture containing 1-methyl-, 2-methyl-, and 5-methylcyclopenta-1,3-diene. (a) Show how both isomeric products areformed from the starting material by a sigmatropic rearrangementinvolving a C–H bond. (b) Explain why 2-methylcyclopenta-1,3-diene isnot formed directly from 5-methylcyclopenta-1,3-diene by a [1,3]rearrangement.

Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products. Explain why A is the major product despite the fact that it contains the less substituted double bond.

4.35 Formulate the reaction of cyclohexene with (i) Br2 and (ii) meta-chloro- peroxybenzoic acid followed by H30+. Show the reaction intermediates and the final products with correct cis or trans stereochemistry. 4.36 What products would you expect to obtain from reaction of cyclohexa- 1,3-diene with each of the following? (a) 1 mol Br2 in CH2C12 (c) 1 mol DCl (D = deuterium, ²H) (b) 1 mol HCl (d) 2 mol H2 over a Pd catalyst 4.37 Predict the products of the following reactions on hex-1-yne: (a) 1 equiv HBr ? (b) 1 equiv Cl2 ? (c) H2, Lindlar catalyst

Answer 2

Question

Chapter 27, Problem 27.46P

Interpretation Introduction

(a)

Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a C−H bond is to be shown.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Interpretation Introduction

(b)

Interpretation: The reasons as to why 2−methylcyclopenta−1,3−diene is not formed directly from 5−methylcyclopenta−1,3−diene by a [1,3] rearrangement.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

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Answer 3

Question

Chapter 27, Problem 27.46P

Interpretation Introduction

(a)

Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a C−H bond is to be shown.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Interpretation Introduction

(b)

Interpretation: The reasons as to why 2−methylcyclopenta−1,3−diene is not formed directly from 5−methylcyclopenta−1,3−diene by a [1,3] rearrangement.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

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Answer 4

Question

Chapter 27, Problem 27.46P

Interpretation Introduction

(a)

Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a C−H bond is to be shown.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Interpretation Introduction

(b)

Interpretation: The reasons as to why 2−methylcyclopenta−1,3−diene is not formed directly from 5−methylcyclopenta−1,3−diene by a [1,3] rearrangement.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

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Answer 5

Chapter 27, Problem 27.46P

Interpretation Introduction

(a)

Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a C−H bond is to be shown.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Interpretation Introduction

(b)

Interpretation: The reasons as to why 2−methylcyclopenta−1,3−diene is not formed directly from 5−methylcyclopenta−1,3−diene by a [1,3] rearrangement.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Answer 6

Chapter 27, Problem 27.46P

Interpretation Introduction

(a)

Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a C−H bond is to be shown.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Answer 7

Chapter 27, Problem 27.46P

Interpretation Introduction

(a)

Interpretation: The formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving a C−H bond is to be shown.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Answer 8

Interpretation Introduction

(b)

Interpretation: The reasons as to why 2−methylcyclopenta−1,3−diene is not formed directly from 5−methylcyclopenta−1,3−diene by a [1,3] rearrangement.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Answer 9

Interpretation Introduction

(b)

Interpretation: The reasons as to why 2−methylcyclopenta−1,3−diene is not formed directly from 5−methylcyclopenta−1,3−diene by a [1,3] rearrangement.

Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 27 - Prob. 27.1P Ch. 27 - Problem 27.2 For each molecular orbital in Figure...Ch. 27 - Problem 27.3 (a) Using Figure 27.2 as a guide,...Ch. 27 - Problem 27.4 (a) How many molecular orbitals are...Ch. 27 - Prob. 27.5P Ch. 27 - Prob. 27.6P Ch. 27 - Prob. 27.7P Ch. 27 - Prob. 27.8P Ch. 27 - Prob. 27.9P Ch. 27 - Prob. 27.10P

Solution Summary: The author explains the formation of both the isomeric products from the starting material by a sigmatropic rearrangement involving C- H bond.

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Chapter 27 Solutions