EBK NUMERICAL METHODS FOR ENGINEERS
EBK NUMERICAL METHODS FOR ENGINEERS
7th Edition
ISBN: 9780100254145
Author: Chapra
Publisher: YUZU
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Chapter 27, Problem 7P

Differential equations like the one solved in Prob. 27.6can often be simplified by linearizing their nonlinear terms. For example, a first-order Taylor series expansion can be used to linearize the quartic term in Eq. (P27.6.1) as

1 × 10 7 ( T + 273 ) 4 = 1 × 10 7 ( T b + 273 ) 4 + 4 × 10 7 ( T b + 273 ) 3 ( T T b )

where T b is a base temperature about which the term is linearized. Substitute this relationship into Eq. (P27.6.1), and then solve the resulting linear equation with the finite-difference approach. Employ T b = 150  and  Δ x = 0.01 to obtain your solution.

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1. A spring mass system serving as a shock absorber under a car's suspension, supports the M 1000 kg mass of the car. For this shock absorber, k = 1 × 10°N /m and c = 2 × 10° N s/m. The car drives over a corrugated road with force %3| F = 2× 10° sin(@t) N . Use your notes to model the second order differential equation suited to this application. Simplify the equation with the coefficient of x'" as one. Solve x (the general solution) in terms of w using the complimentary and particular solution method. In determining the coefficients of your particular solution, it will be required that you assume w – 1z w or 1 – o z -w. Do not use Matlab as its solution will not be identifiable in the solution entry. Do not determine the value of w. You must indicate in your solution: 1. The simplified differential equation in terms of the displacement x you will be solving 2. The m equation and complimentary solution xe 3. The choice for the particular solution and the actual particular solution x,…
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Solve the following differential equation for axial deformation of a bar of length 12mm using Galerkin Weighted Residual method 2022/09/ d² dx² = -0.75(4- x)² One end of the bar is fixed whereas the displacement is 12 mm at the other end of the bar. You may use Matlab for computations. Use the trial function û(x) = Co + ₂x + ₂x²

Chapter 27 Solutions

EBK NUMERICAL METHODS FOR ENGINEERS

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