Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Chapter 28, Problem 9P
Heteroduplex DNA Formation in Recombination From the information in Figures 28.17 and 28.18, diagram the recombinational event leading to the formation of a heteroduplex DNA region within a bacteriophage chromosome.
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Chapter 28 Solutions
Biochemistry
Ch. 28 - Semiconservative or Conservative DNA Replication...Ch. 28 - The Enzymatic Activities of DNA Polymerase I (a)...Ch. 28 - Multiple Replication Forks in E. coli I Assuming...Ch. 28 - Multiple Replication Forks in E. coli II On the...Ch. 28 - Molecules of DNA Polymerase III per Cell vs....Ch. 28 - Number of Okazaki Fragments in E. coli and Human...Ch. 28 - The Roles of Helicases and Gyrases How do DNA...Ch. 28 - Human Genome Replication Rate Assume DNA...Ch. 28 - Heteroduplex DNA Formation in Recombination From...Ch. 28 - Homologous Recombination, Heteroduplex DNA, and...
Ch. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Chemical Mutagenesis of DNA Bases Show the...Ch. 28 - Prob. 14PCh. 28 - Recombination in Immunoglobulin Genes If...Ch. 28 - Helicase Unwinding of the E. coli Chromosome...Ch. 28 - Prob. 17PCh. 28 - Functional Consequences of Y-Family DNA Polymerase...Ch. 28 - Figure 28.11 depicts the eukaryotic cell cycle....Ch. 28 - Figure 28.41 gives some examples of recombination...Ch. 28 - Prob. 21PCh. 28 - Prob. 22P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.Similar questions
- Homologous Recombination, Heteroduplex DNA, and Mismatch Repair Homologous recombination in E. coli leads to the formation of regions of heteroduplex DNA. By definition, such regions contain mismatched bases. Why doesn’t the mismatch repair system of E. coli eliminate these mismatches?arrow_forwardHelicase Unwinding of the E. coli Chromosome Hexameric helicases, such as DnaB, the MCM proteins, and papilloma virus El helicase (illustrated in Figures 16.22 to 16.25), unwind DNA by passing one strand of the DNA duplex through the central pore, using a mechanism based on ATP-dependent binding interactions with the bases of that strand. The genome of E. coli K12 consists of 4,686,137 nucleotides. Assuming that DnaB functions like papilloma virus El helicase, from the information given in Chapter 16 on ATP-coupled DNA unwinding, calculate how many molecules of ATP would be needed to completely unwind the E. coli K 12 chromosome.arrow_forwardMultiple Replication Forks in E. coli I Assuming DNA replication proceeds at a rate of 750 base pairs per second, calculate how long it will take to replicate the entire E. coli genome. Under optimal conditions, E. coli cells divide every 20 minutes. What is the minimal number of replication forks per E. coli chromosome in order to sustain such a rate of cell division?arrow_forward
- Number of Okazaki Fragments in E. coli and Human DNA Replication Approximately how many Okazaki fragments are synthesized in the course of replicating an E. coli chromosome? How many in replicating an “averageâ€� human chromosome?arrow_forwardDraw the structures of two tautomeric forms of guanine, one a lactam, theother a lactim. Explain the possible involvement of the lactim form in causingspontaneous mutation during replication.arrow_forwardIn E. coli, all newly synthesized DNA appears to be fragmented (an observation that could be interpreted to mean that the leading strand as well as the lagging strand is synthesized discontinuously). However, in E. coli mutants that are defective in uracil–DNA glycosylase, only about half the newly synthesized DNA is fragmented. Explain.arrow_forward
- Not just generic "degradation" or even shorter DNA fragments, what specific structure change in double-stranded DNA does the hyperchromicity effect show?arrow_forwardUsing the formulae for dsDNA to calculate g/mol: You have a 4110 bp cloning vector Want to ligate a 245 bp insert for molecular cloning. efficient cloning requires that a 1:5 molar ratio of vector to insert is optimal for the ligation reaction. What are the relative weights of vector and the insert DNA necessary in g?arrow_forwardPlease answer You have received a dehydrated sample of DNA primer at a concentration of 19.9 microM. what volume (in microlitres) of buffer would you add to achieve a solution of 100nM of this primer? Show workings.arrow_forward
- The relative proportions of cytosine-guanine and adeninethymine bonds in a DNA sample can be estimated by measuring its “melting temperature,” the temperature at which half of the DNA strands have pulled apart. Samples with a high percentage of cytosine-guanine pairs have a higher melting temperature than samples with a high percentage of adeninethymine pairs. Explain why this is so, considering the nature of the bonds that hold the base pairs together (look back at as shown).arrow_forwardBase analysis of DNA from maize (corn) shows it to have 23 mole percent cytosine (moles per 100 moles total nucleotide). What are the percentages of the other three bases?arrow_forwardHomologous recombination in E. coli forms heteroduplex regions of DNA containing mismatched bases. Why are these mismatches not eliminated bythe mismatch repair system?arrow_forward
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