EBK COLLEGE PHYSICS
3rd Edition
ISBN: 9780321989246
Author: Knight
Publisher: PEARSON CO
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Chapter 29, Problem 53GP
To determine
Speed of the alpha particle when it is closest to nucleus.
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In Rutherford's famous scattering experiments that led
to the planetary model of the atom, alpha particles (having
charges of +2e and masses of 6.64 x 10-27 kg) were fired
toward a gold nucleus with charge +79e. An alpha particle,
The oxygen nucleus 16O has a radius of 3.0 fm.a. With what speed must a proton be fired toward an oxygen nucleus to have a turning point 1.0 fm from the surface?Assume that the nucleus is heavy enough to remain stationary during the collision.b. What is the proton’s kinetic energy in MeV?
An alpha particle (charge +3.20 x 10^-19C, mass 6.64 x10^-27kg) is initially 5.2cm away from a fixed golden nucleus (charge +1.36 x10^-17C, mass 3.29x10^-25kg), and moving toward the nucleus with a speed of 8.1x10^5m/s. How close to the nucleus does te alpha particle get? Note: the nucleus diameter is approximately 10^-14m and the alpha particles's is 10^-15m
Chapter 29 Solutions
EBK COLLEGE PHYSICS
Ch. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - Prob. 8CQCh. 29 - Prob. 9CQCh. 29 - Prob. 10CQ
Ch. 29 - Prob. 11CQCh. 29 - Prob. 12CQCh. 29 - Prob. 13CQCh. 29 - Prob. 14CQCh. 29 - Prob. 15CQCh. 29 - Prob. 16CQCh. 29 - Prob. 17CQCh. 29 - Prob. 18CQCh. 29 - Prob. 19CQCh. 29 - Prob. 20CQCh. 29 - Prob. 21CQCh. 29 - Prob. 22CQCh. 29 - Prob. 23CQCh. 29 - Prob. 24MCQCh. 29 - Prob. 25MCQCh. 29 - Prob. 26MCQCh. 29 - Prob. 27MCQCh. 29 - Prob. 28MCQCh. 29 - Prob. 29MCQCh. 29 - Prob. 30MCQCh. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - Prob. 27PCh. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - Prob. 35PCh. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 38PCh. 29 - Prob. 39PCh. 29 - Prob. 40PCh. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 44GPCh. 29 - Prob. 45GPCh. 29 - Prob. 46GPCh. 29 - Prob. 47GPCh. 29 - Prob. 48GPCh. 29 - Prob. 49GPCh. 29 - Prob. 50GPCh. 29 - Prob. 51GPCh. 29 - Prob. 52GPCh. 29 - Prob. 53GPCh. 29 - Prob. 54GPCh. 29 - Prob. 55GPCh. 29 - Prob. 56GPCh. 29 - Prob. 57GPCh. 29 - Prob. 58GPCh. 29 - Prob. 59GPCh. 29 - Prob. 60GPCh. 29 - Prob. 61GPCh. 29 - Prob. 62GPCh. 29 - Prob. 63GPCh. 29 - Prob. 64GPCh. 29 - Prob. 65GPCh. 29 - Prob. 66GPCh. 29 - Prob. 67GPCh. 29 - Prob. 68GPCh. 29 - Prob. 69GPCh. 29 - Prob. 70GPCh. 29 - Prob. 71GPCh. 29 - Prob. 73GPCh. 29 - Prob. 74GPCh. 29 - Prob. 75GPCh. 29 - Prob. 76MSPPCh. 29 - Prob. 77MSPPCh. 29 - Prob. 78MSPPCh. 29 - Prob. 79MSPP
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- (a) What voltage must be applied to an X-ray tube to obtain 0.0100-fm-wavelength X-rays for use in exploring the details of nuclei? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forward(a) Calculate the velocity of an electron that has a wavelength of 1.00 m. (b) Through what voltage must the electron be accelerated to have this velocity?arrow_forwardPart 1 Find the speed an alpha particle requires to come within 4 x 10-14 m of a gold nucleus. Coulomb's constant is 8.99 x 109 Nm2/C2, the charge on an electron is 1.6 × 10-19 C, and the mass of the alpha particle is 6.64 x 10-27 kg. Answer in units of m/s. Part 2 Find the energy of the alpha particle. Answer in units of MeV.arrow_forward
- Now you have a nucleus with 20 protons at x = 7.9 Angstroms on the x-axis. How much work would it take to bring in ANOTHER nucleus with 4 protons from 1 m away and place it at y = 7.0 Angstroms on the y-axis? Question 10 options: A 50.4 eV B 100.8 eV C -8.2 eV D 109.0 eVarrow_forwardA 20 MeV alpha particle is fired toward a 238U nucleus. It follows the path as shown. What is the alpha particle’s speed when it is closest to the nucleus, 20 fm from its center? Assume that the nucleus doesn’t move.arrow_forwardA charged particle with initial kinetic energy of 80.3 keV ionizes an electron in the K shell of a silver atom. The binding energy for K-shell electrons in silver is 25.5 keV. The charged particle has kinetic energy of 43.7 keV after the interaction. What is the kinetic energy of the secondary electron, after it is ejected from the silver atom?arrow_forward
- Consider an object of mass 56.6 kg. Assume that it s made up of equal numbers of protons, neutrons, and electrons. How many protons does this object contain? Question 1 options: 8.45E+27 1.69E+28 3.38E+28 6.76E+28arrow_forwardThe figure provided shows the potential energy of a proton, q = +e, and a lead nucleus, q = +82e. If a proton is fired toward a lead nucleus from very far away with kinetic energy K = 3.00×10-12 J, how much kinetic energy does it have when it is 20.0 fm from the nucleus and moving toward it, before the collision? 5.00×10-12 J 4.00×10-12 J 3.00×10-12 J 2.00×10-12 Jarrow_forwardAlpha particles are projected toward a gold foil from a distance that is sufficiently large to consider the Coulomb force negligible. The gold nuclei have 118 neutrons and 79 protons. If a 3.45 MeV alpha particle has a scattering angle of 180° and the gold nucleus does not recoil, determine the distance of closest approach of the alpha particle.arrow_forward
- Now you have a nucleus with 15 protons at x = 7.3 Angstroms on the x-axis. How much work would it take to bring in ANOTHER nucleus with 12 protons from 1 m away and place it at y = 3.0 Angstroms on the y-axis? 189.4 eV 270.5 eV -57.5 eV 328.1 eVarrow_forwardAn 8.3 MeV alpha particle is shot directly toward the nucleus of a gold atom (atomic number 79). What is the distance of closest approach of the alpha particle to the nucleus?arrow_forwardEach a particle in a beam of a particles has a kinetic energy of 4.5 MeV. Through what potential difference would you have to accelerate these a particles in order that they would have enough energy so that if one is fired head-on at a gold nucleus it could reach a point 1.9 10^-14 m from the center of the nucleus?arrow_forward
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