BIOCHEMISTRY-ACHIEVE (1 TERM)
BIOCHEMISTRY-ACHIEVE (1 TERM)
9th Edition
ISBN: 9781319402853
Author: BERG
Publisher: MAC HIGHER
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Chapter 29, Problem 8P
Interpretation Introduction

(a)

Interpretation:

From the given twist number and writhe number, the linking number is to be calculated .

Concept introduction:

Circular DNA generally undergoes super coiling in order to fit itself inside a smaller space like a cell. Plasmids are the number of extra chromosomal material found inside bacterial cells. They are generally found in super coiled state.

Interpretation Introduction

(b)

Interpretation:

The writhe number is to be calculated based on the twist number and the linking number.

Concept introduction:

Circular DNA generally undergoes super coiling in order to fit itself inside a smaller space like a cell. Plasmids are the number of extra chromosomal material found inside bacterial cells. They are generally found in super coiled state.

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gene. If the JM109 strain is transformed by the PBKSK plasmid, the strain will produce the B-galactosidase (from the lac gene) and will hydrolyze X-gal to produce the blue compound. Therefore, colonies that were transformed and contain the pBSKS wil you appear blue. IPTG & X-Gal & NO colonies Amp E. coli JM109 E. coli JM109 50 mM calcium chloride-15% glycerol lac lac lac IPTG & I Recovery X-Gal solution at -702C PBSKS White colonies E. coli JM109 E. coli JM109 ampR amp I amp lac lac Heat Shock Non-transformed 42°C E. coli JM109 E. coli JM109 amps amps lac lac IPTG & X-Gal lac I Recovery lac PBSKS BLUE colonies PBSKS ampRI (amp Transformed IPTG & X-Gal & BLUE colonies Amp Hypotheses: Circle the correct answer 1. If PBSKS is transformed into JM109 cells, colonies will be (able/not able) to grow in the presence of ampicillin. a. Why? _ 2. If PBSKS is transformed into JM109 cells, colonies in media with IPTG (will/will not) induce the production the B- galactosidase enzyme. a. Why?_ 3. If…
Pick a plasmid . What was its approximate transformation? Express it in # colonies per microgram of DNA transformed. Assume the original DNA was about .001 ug/ul . Count how many colonies you got on one plate (or estimate that number) and figure out how much of the total solution you plated on that plate. Multiply by all the plates, if you plated all of it. OR, if you only plated some of it, figure out how many colonies you would have gotten had you plated all of it. Divide by the number of ug used.
Pstl. EcoRI Origin of replication (ori) Ampicillin Tetracycline resistance resistance (Amp) (Tet") pBR322 (4,361 bp) BamHI Pvull Sall Recombinant Plasmid DNA Bacterial cell contains... No plasmid DNA pBR322 (no insert) Recombinant plasmid 00,000. Host DNA Transformation of E. coli cells +AMP plate pBR322 Figure 7-5 +TET plate Based on the recombinant plasmid growth pattern (bottom row of blue table), which of the depicted plasmid's restriction sites was used to prepare this sample? Explain how you can tell.
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