Pushing Electrons
4th Edition
ISBN: 9781133951889
Author: Weeks, Daniel P.
Publisher: Cengage Learning
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NO2- is an ion that can from a one double bond while NO2+ will have 2. (True/False)
The structure of Vitamin C (ascorbic acid) is shown below. As the name indicates, the molecule is somewhat acidic. Actually, one of the hydrogens on the four OH groups is much more acidic than the other three ones. Which one is the acidic hydrogen?
Hints: To find the answer, you will again have to draw some resonance structures of the product formed after loss of H+. Consider the product after the loss of H+ for each of the OH groups. Only two of the OH groups have resonance structures after deprotonation; one of these two groups has a much better resonance structure than the other one (again after deprotonation). Note that the oxygen atom that is part of the five-membered ring has nothing to do with the problem.
true or false
BH3 is a useful reagent to add an OH to the least hindered side of a double bond.
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- Label each double bond E, Z, or neither. (It may help to draw in some missing H’s.)arrow_forwardRank the following acids in order of strength. H2S, CHCl3, H2Se, CH2Ch2arrow_forwardThe curved arrow notation introduced in Section 1.6 is a powerful method used by organic chemists to show the movement of electrons not only in resonance structures, but also in chemical reactions. Since each curved arrow shows the movement of two electrons, following the curved arrows illustrates what bonds are broken and formed in a reaction. Consider the following three-step process. (a) Add curved arrows in Step [1] to show the movement of electrons. (b) Use the curved arrows drawn in Step [2] to identify the structure of X. X is converted in Step [3] to phenol and HCl.arrow_forward
- The following molecule, the silicon analog of formaldehyde, has never been successfully prepared. H2SiO or H2Si=O The following reaction was attempted by researchers in order to synthesize this unusual compound: H2Si=S + P4O10 → H2Si=O + P4O9S None of the desired compound (H2Si=O) was obtained. Instead, the following molecule was obtained: (H2SiO)2 a molecule in which the O and Si form an …Si-O-Si-O… square. Further research indicated that although H2Si=O formed, it immediately formed (H2SiO)2 and released a substantial amount of energy according to the reaction: 2 H2Si=O → (H2SiO)2 + heat Based on the information above and your knowledge, what can be concluded about the relative strength of the Si-O and Si=O bonds? Question 24 options: A) An Si=O bond is stronger than two Si-O bonds. B) An Si=O bond is weaker than two Si-O bonds. C) An Si-O bond has the same strength as an Si=O.…arrow_forwardA benzene ring alters the reactivity of a neighboring group in the so-called “benzylic” position, similarly to how a double bond alters the reactivity of groups in the “allylic” position. Benzylic cations, anions, and radicals are all more stable than simple alkyl intermediates. a) Use resonance structures to show the delocalization of the positive charge, negative charge, and unpaired electron of the benzyl cation, anion, and radical.arrow_forwardfor part b)why do we write AlCl3 at top of the arrow and AlCl4 at the bottom of arrow??is it any connection between the two?does it means that AlCl 4 need to be present in order to make AlCl3 reacts to the molecule and make the reaction to process?? 2. why when AlCl3 added,Cl was removed from the ring?what princeiple theory is that ? 2. when SO3 is added ,SO3 attached to the ring,why ?what principle is behind this phenamonane 3.Just confused about why AlCl3 removes Cl from the ring,while HSO3 donate SO3 to the ring. Is it Something about nucleohilic or eletrciohillic?arrow_forward
- Calculate the heat of reaction deltaH for the following reaction: 2HCl(g)+Br2(g)——> 2HBr2(g)+ Cl2(g) Round your answer to the nearest kJ/mol.arrow_forwardDetermine the kind of reaction from the chemical equation below: methyl bromide + hydroxide ion ➡️ methyl alcohol + bromide ion SN2 SN1 SN1 and SN2 neither SN1 nor SN2arrow_forwardDraw curved arrows to show the movement of the electrons that result in the formation of the given product(s)arrow_forward
- Pairs of unshared electrons can be pushed. One Lewis structure for the methoxy-methyl cation is . The structure contains a pair of pushable electrons, namely, the unshared electrons on the atom. The structure also contains a positively charged atom that can act as a . A second resonance structure can be generated by pushing the unshared electrons to the receptor. Thus, It is not possible to push electrons toward the other carbon, because it is not a receptor. If you tried to push electrons to this carbon, you would generate a pentavalent carbon, which is not possible.arrow_forwardWhat reaction would acetylene likely undergo if it were kept at 1500 °C for too long?9arrow_forwardWhat are the next favourable resonance structures being asked for?arrow_forward
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