21ST CENT.AST.W/WKBK+SMARTWORK >BI<
6th Edition
ISBN: 9780393415216
Author: Kay
Publisher: NORTON
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Chapter 3, Problem 11QP
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8. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of
Mercury from the Sun is 57.9 x 10° km. The period of Earth's revolutions is 1 year,
what is the period of Mercury's revolution?
a. 0.24 year on Earth
b. 0.42 year on Earth
C. 1.13 year on Earth
d. 1.31 year on Earth
9. The planet Delta has 2 times the gravitational field strength and 3 times the radius of
Earth. How does the mass of the planet Delta compare with the mass of Earth?
2. From Kepler's Third Law, the period (P) squared divided by the cube of semi-major axis (d) is
the same for all planets and is expressed as P2 / d = k, where k is a constant. One can
conclude that
A. In the same amount of time, every planet orbits the sun.
B. At the same distance from the sun, every planet orbits the sun.
C. It takes more time to orbit the sun if the planets are farthest from the sun.
D. It takes less time to orbit the sun if the planets are farthest from the sun.
The orbit of a planet around the sun is :
O A. hyperbolic.
O B. parabolic.
OC. elliptic.
OD. circular.
Chapter 3 Solutions
21ST CENT.AST.W/WKBK+SMARTWORK >BI<
Ch. 3.1 - Prob. 3.1ACYUCh. 3.1 - Prob. 3.1BCYUCh. 3.2 - Prob. 3.2CYUCh. 3.3 - Prob. 3.3CYUCh. 3.4 - Prob. 3.4CYUCh. 3 - Prob. 1QPCh. 3 - Prob. 2QPCh. 3 - Prob. 3QPCh. 3 - Prob. 4QPCh. 3 - Prob. 5QP
Ch. 3 - Prob. 6QPCh. 3 - Prob. 7QPCh. 3 - Prob. 8QPCh. 3 - Prob. 9QPCh. 3 - Prob. 10QPCh. 3 - Prob. 11QPCh. 3 - Prob. 12QPCh. 3 - Prob. 13QPCh. 3 - Prob. 14QPCh. 3 - Prob. 15QPCh. 3 - Prob. 16QPCh. 3 - Prob. 17QPCh. 3 - Prob. 18QPCh. 3 - Prob. 19QPCh. 3 - Prob. 20QPCh. 3 - Prob. 21QPCh. 3 - Prob. 22QPCh. 3 - Prob. 23QPCh. 3 - Prob. 24QPCh. 3 - Prob. 25QPCh. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Prob. 28QPCh. 3 - Prob. 29QPCh. 3 - Prob. 30QPCh. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QPCh. 3 - Prob. 37QPCh. 3 - Prob. 38QPCh. 3 - Prob. 39QPCh. 3 - Prob. 40QPCh. 3 - Prob. 41QPCh. 3 - Prob. 42QPCh. 3 - Prob. 43QPCh. 3 - Prob. 44QPCh. 3 - Prob. 45QP
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- The rotation of the planets around the sun is governed by: A. The gravitational field of the sun. B. The gravity of the stars. C. The heat energy of the sun. D. The gravity of the other planets of the solar system. Kelper's second law relates between them: O A. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the sun. OB. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the earth. C. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the moon. OD. The time period of rotation of the orbiting planet around the earth and the average distance of the planet to the sun.arrow_forwardCurrently, the moon goes around the earth once every 27.3 days. If the moon could be brought into a new circular orbit with a smaller radius, its orbital period would beA. More than 27.3 days.B. 27.3 days.C. Less than 27.3 days.arrow_forwardDirection: Complete the table below. Calculate the problem using the Laws of Planetary Motion based on the given basic planetary data below. F Earth Mars Saturn Uranus Neptune Jupiter 1. 3. Mean Distance(r) Period of 1.496 x 108 44.97x108 2.28 x 108 14.27x108 2. 4. Revolution (T) 365.2 days 1.88 yrs. 11.86 yrs. 84 yrs. Using the Earth as reference, determine the mean distance(r) or the Period of revolution (T) of each planet. Here is the formula in the Law of Period. (T₁)² (r₁)² (T₂)² (r₂)² = 1. Find the Mean distance of Jupiter. 2. Find the Period of Saturn 3. Find the mean distance of Uranus. 4. Find the Period of Neptune.arrow_forward
- A newly discovered planet orbits a star with the same mass as the Sun with a semi-major axis of 239.36 million kilometers. Its orbital eccentricity is 0.1.A. Find the planet's orbital period.B. Find the planet's perihelion distance.C. Find the planet's aphelion distance.arrow_forward25. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of Mercury from the Sun is 57.9 x 106 km. The period of Earth's revolutions is 1 year, what is the period of Mercury's revolution? a. 0.24 year on Earth b. 0.42 year on Earth C. 1.13 year on Earth d. 1.31 year on Eartharrow_forward2. An unknown planet was accidentally discovered by NASA. It has a mean distance of 2.15 E11 meters from the sun. Assuming it has a mass of 6.02 E24 kg, how long (in Earth Years) will it take for the said planet to revolve around the sun?arrow_forward
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