21ST CENT.AST.W/WKBK+SMARTWORK >BI<
6th Edition
ISBN: 9780393415216
Author: Kay
Publisher: NORTON
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Chapter 3 Solutions
21ST CENT.AST.W/WKBK+SMARTWORK >BI<
Ch. 3.1 - Prob. 3.1ACYUCh. 3.1 - Prob. 3.1BCYUCh. 3.2 - Prob. 3.2CYUCh. 3.3 - Prob. 3.3CYUCh. 3.4 - Prob. 3.4CYUCh. 3 - Prob. 1QPCh. 3 - Prob. 2QPCh. 3 - Prob. 3QPCh. 3 - Prob. 4QPCh. 3 - Prob. 5QP
Ch. 3 - Prob. 6QPCh. 3 - Prob. 7QPCh. 3 - Prob. 8QPCh. 3 - Prob. 9QPCh. 3 - Prob. 10QPCh. 3 - Prob. 11QPCh. 3 - Prob. 12QPCh. 3 - Prob. 13QPCh. 3 - Prob. 14QPCh. 3 - Prob. 15QPCh. 3 - Prob. 16QPCh. 3 - Prob. 17QPCh. 3 - Prob. 18QPCh. 3 - Prob. 19QPCh. 3 - Prob. 20QPCh. 3 - Prob. 21QPCh. 3 - Prob. 22QPCh. 3 - Prob. 23QPCh. 3 - Prob. 24QPCh. 3 - Prob. 25QPCh. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Prob. 28QPCh. 3 - Prob. 29QPCh. 3 - Prob. 30QPCh. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QPCh. 3 - Prob. 37QPCh. 3 - Prob. 38QPCh. 3 - Prob. 39QPCh. 3 - Prob. 40QPCh. 3 - Prob. 41QPCh. 3 - Prob. 42QPCh. 3 - Prob. 43QPCh. 3 - Prob. 44QPCh. 3 - Prob. 45QP
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- If the orbital distance to a planet doubles, its period will be: a. Half b. Larger, but less than double c. less than half d. More than double e. Doublearrow_forwardDirection: Complete the table below. Calculate the problem using the Laws of Planetary Motion based on the given basic planetary data below. F Earth Mars Saturn Uranus Neptune Jupiter 1. 3. Mean Distance(r) Period of 1.496 x 108 44.97x108 2.28 x 108 14.27x108 2. 4. Revolution (T) 365.2 days 1.88 yrs. 11.86 yrs. 84 yrs. Using the Earth as reference, determine the mean distance(r) or the Period of revolution (T) of each planet. Here is the formula in the Law of Period. (T₁)² (r₁)² (T₂)² (r₂)² = 1. Find the Mean distance of Jupiter. 2. Find the Period of Saturn 3. Find the mean distance of Uranus. 4. Find the Period of Neptune.arrow_forwardA newly discovered planet orbits a star with the same mass as the Sun with a semi-major axis of 239.36 million kilometers. Its orbital eccentricity is 0.1.A. Find the planet's orbital period.B. Find the planet's perihelion distance.C. Find the planet's aphelion distance.arrow_forward
- 3. The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.arrow_forwardKepler's third law of planetary motion describes a relationship between the__ * a, shape of orbit and the location of the Sun. b. orbital velocity and position in orbit c. distance from the Sun and length of year. d. path of epicycle and position.arrow_forwardHow would the strength of the force between the Moon and Earth change if the mass of the Moon were somehow made two times greater than its actual mass? A. It would double. B. It would quadruple. C. It would decrease by half. D. It would not change.arrow_forward
- 6. Determine what the period of revolution of the Earth would be if its distance from the Sun were 4 AU rather than 1 AU. Assume that the mass of the Sun remains the same.arrow_forwardAccording to Lunar Laser Ranging experiments the average distance LM from the Earth to the Moon is approximately 3.85 × 10° km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). How can the mass of the Earth be calculated using the information above? Select the correct statements. Select one or more: O a. Use Newton's third law. O b. Use Newton's first law. c. Use Coulombs law. O d. Use Newton's second law.arrow_forward9. Which of the following is NOT one of Kepler's Laws of Planetary Motion? A. The square of a planet's period is proportional to its distance from the sun cubed, B. The area of a planet's orbital plane is inversely proportional to its speed. C. A planet sweeps out equal area in an equal time interval. D. Planets move around the sun in elliptical orbits.arrow_forward
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