21ST CENT.AST.W/WKBK+SMARTWORK >BI<
6th Edition
ISBN: 9780393415216
Author: Kay
Publisher: NORTON
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Chapter 3, Problem 2QP
To determine
What happens when Earth catches up to a slower-moving outer planet and passes it in its orbit.
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Which of the following is a measurable effect of the tidal interactions between the Earth and the moon?
choose 1 of the following:
a.
The moon is constantly getting closer to the Earth, and will one day collide with our planet.
b.
The rotation rate of the Earth is gradually slowing down.
c.
The rotation rate of the moon is gradually speeding up.
d.
The moon pulls more strongly on the far side of the Earth than it does on the near side.
The rotation of the planets around the sun is governed by:
A. The gravitational field of the sun.
B. The gravity of the stars.
C. The heat energy of the sun.
D. The gravity of the other planets of the solar system.
Kelper's second law relates between them:
O A. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the
sun.
OB. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the
earth.
C. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the
moon.
OD. The time period of rotation of the orbiting planet around the earth and the average distance of the planet to
the sun.
When tidal bulges are NOT in a direct Earth-moon line but slightly ahead of the moon,
a.
Earth’s gravity weakens.
b.
their gravitational field pulls the moon forward in its orbit, causing it to recede from Earth.
c.
their gravitational field pulls the moon back in its orbit, causing the moon to fall toward Earth.
d.
Earth’s gravity strengthens, causing the moon to orbit faster.
e.
the tidal bulges have no effect on the moon.
Chapter 3 Solutions
21ST CENT.AST.W/WKBK+SMARTWORK >BI<
Ch. 3.1 - Prob. 3.1ACYUCh. 3.1 - Prob. 3.1BCYUCh. 3.2 - Prob. 3.2CYUCh. 3.3 - Prob. 3.3CYUCh. 3.4 - Prob. 3.4CYUCh. 3 - Prob. 1QPCh. 3 - Prob. 2QPCh. 3 - Prob. 3QPCh. 3 - Prob. 4QPCh. 3 - Prob. 5QP
Ch. 3 - Prob. 6QPCh. 3 - Prob. 7QPCh. 3 - Prob. 8QPCh. 3 - Prob. 9QPCh. 3 - Prob. 10QPCh. 3 - Prob. 11QPCh. 3 - Prob. 12QPCh. 3 - Prob. 13QPCh. 3 - Prob. 14QPCh. 3 - Prob. 15QPCh. 3 - Prob. 16QPCh. 3 - Prob. 17QPCh. 3 - Prob. 18QPCh. 3 - Prob. 19QPCh. 3 - Prob. 20QPCh. 3 - Prob. 21QPCh. 3 - Prob. 22QPCh. 3 - Prob. 23QPCh. 3 - Prob. 24QPCh. 3 - Prob. 25QPCh. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Prob. 28QPCh. 3 - Prob. 29QPCh. 3 - Prob. 30QPCh. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QPCh. 3 - Prob. 37QPCh. 3 - Prob. 38QPCh. 3 - Prob. 39QPCh. 3 - Prob. 40QPCh. 3 - Prob. 41QPCh. 3 - Prob. 42QPCh. 3 - Prob. 43QPCh. 3 - Prob. 44QPCh. 3 - Prob. 45QP
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- 6. A synchronous orbit is an orbit about a planet's equator that always remains above the same spot of the planet because the synchronous orbit matches the planet's rotational period. The pilot of the Mars spacecraft (which was named Cheetah 1 and had a 9556 kg mass) asked Tarzan to calculate the altitude of a synchronous orbit so they could remain over a particular geological feature on the Martian equator. Calculate the altitude above the Martian equator using the data above and Johannes Kepler's genius.arrow_forward2. An unknown planet was accidentally discovered by NASA. It has a mean distance of 2.15 E11 meters from the sun. Assuming it has a mass of 6.02 E24 kg, how long (in Earth Years) will it take for the said planet to revolve around the sun?arrow_forwardWhich statement describes the sun's position relative to planetary orbits? A. The sun is at the center of each planet's circular orbit. B. The sun is midway between the foci of each planet's elliptical orbit. C. The sun is one focus of each planet's elliptical orbit. D. The sun alternates between the two foci of planetary orbits.arrow_forward
- 7. The brightest four moons of Jupiter were discovered by Galileo with one of his earliest telescopes. These moons, lo, Europa, Ganymede, and Callisto, are called the Galilean moons in his honour. Some of the available data about these moons are given below. MOON r (km) V T (earthyears) 0.004837 lo a. Europa Ganymede Callisto 4.219 x 105 6.712 x 105 1.853 x 106 0.0195884 The radii are from the centre of Jupiter to the centre of the moon in question. One earth year has 365 days. Using the data for above, find the mass of Jupiter. Be specific as to which line of data was used and why. Show all work.arrow_forward8. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of Mercury from the Sun is 57.9 x 10° km. The period of Earth's revolutions is 1 year, what is the period of Mercury's revolution? a. 0.24 year on Earth b. 0.42 year on Earth C. 1.13 year on Earth d. 1.31 year on Earth 9. The planet Delta has 2 times the gravitational field strength and 3 times the radius of Earth. How does the mass of the planet Delta compare with the mass of Earth?arrow_forward5. Calculate the acceleration due to gravity on the surface of Jupiter? (mj = 6.67×10¹¹1 N·m²/kg²) = 1.90×1027 kg, TJ = 69,911 km, Garrow_forward
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