Chapter 3, Problem 18CUR

To determine

To find: the measure of $\angle BHC$

Answer to Problem 18CUR

The angle $\angle BHC={60}^0$

Explanation of Solution

Given information:

The given figure is as follows

  $\angle AHD={60}^0,\overleftrightarrow{AB}\perp \overline{GH},\overleftrightarrow{AB}\parallel \overleftrightarrow{CD}$

  $\overleftrightarrow{AB}$ bisects $\angle DHF$

Calculation:

From the given data,

  $\angle BHC$ and $\angle AHF$ are vertical angles and they are congruent.

  $\angle AHF=\angle AHD={60}^0$

Since, $\overleftrightarrow{AB}$ bisects $\angle DHF$

Hence, the angle $\angle BHC={60}^0$