McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
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Chapter 3.3, Problem 12ST1
To determine

To find: m8 and mEDC given that m2=65 .

Expert Solution & Answer
Check Mark

Answer to Problem 12ST1

  m8=65

  mEDC=115

Explanation of Solution

Given:

The diagram:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 3.3, Problem 12ST1 , additional homework tip  1

Concept Used:

Corresponding angles: These are the two angles which relative to the two lines are in the corresponding position.

Postulate 10: If two parallel lines are cut by a transversal then the corresponding angles are congruent.

Alternate interior angles: These are the two non adjacent interior angles which are on the opposite sides of the transversal.

Theorem 3-2: If two parallel lines are cut by a transversal then the alternate interior angles are congruent.

Theorem 3-3: If two parallel lines are cut by a transversal then the same-side interior angles are supplementary.

Consider the given figure:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 3.3, Problem 12ST1 , additional homework tip  2

In this figure, lines ED¯AC¯ and EB¯ is a transversal, so by theorem 3-2,

  28 (Alternate-interior angles)

This implies that,

  m8=m2=65

Similarly, lines EB¯DC¯ and BC¯ is a transversal, so by postulate 10,

  52 (Corresponding angles)

This implies that,

  m5=m2=65

Now, lines EB¯DC¯ and DC¯ is a transversal, so by theorem 3-3, EDC and 5 are supplementary, that is,

  mEDC+m5=180mEDC+65=180mEDC=18065mEDC=115

Chapter 3 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 3.1 - Prob. 11CECh. 3.1 - Prob. 12CECh. 3.1 - Prob. 13CECh. 3.1 - Prob. 14CECh. 3.1 - Prob. 15CECh. 3.1 - Prob. 16CECh. 3.1 - Prob. 17CECh. 3.1 - Prob. 18CECh. 3.1 - Prob. 19CECh. 3.1 - Prob. 1WECh. 3.1 - Prob. 2WECh. 3.1 - Prob. 3WECh. 3.1 - Prob. 4WECh. 3.1 - Prob. 5WECh. 3.1 - Prob. 6WECh. 3.1 - Prob. 7WECh. 3.1 - Prob. 8WECh. 3.1 - Prob. 9WECh. 3.1 - Prob. 10WECh. 3.1 - Prob. 11WECh. 3.1 - Prob. 12WECh. 3.1 - Prob. 13WECh. 3.1 - Prob. 14WECh. 3.1 - Prob. 15WECh. 3.1 - Prob. 16WECh. 3.1 - Prob. 17WECh. 3.1 - Prob. 18WECh. 3.1 - Prob. 19WECh. 3.1 - Prob. 20WECh. 3.1 - Prob. 21WECh. 3.1 - Prob. 22WECh. 3.1 - Prob. 23WECh. 3.1 - Prob. 24WECh. 3.1 - Prob. 25WECh. 3.1 - Prob. 26WECh. 3.1 - Prob. 27WECh. 3.1 - Prob. 28WECh. 3.1 - Prob. 29WECh. 3.1 - Prob. 30WECh. 3.1 - Prob. 31WECh. 3.1 - Prob. 32WECh. 3.1 - Prob. 33WECh. 3.1 - Prob. 34WECh. 3.1 - Prob. 35WECh. 3.1 - Prob. 36WECh. 3.1 - Prob. 37WECh. 3.1 - Prob. 38WECh. 3.1 - Prob. 39WECh. 3.1 - Prob. 40WECh. 3.1 - Prob. 41WECh. 3.1 - 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