a. Answer The scatter plot of the data is given as Explanation Calculation: The scatter plot of the data is given as Hence, the graph is shown above. b. To determine Decide the model for data . Answer logarithmic model. Explanation Calculation: The best model for these points is logarithmic model Hence, the data could be modelled by a logarithmic model c. To determine Explain the model of part ( b ) . Answer From the graph, we can see that points are increasing non-linearly, so, we cannot use a model linear model for this. We can also see that points are not growing rapidly,so, exponential model is not suitable. Explanation Calculation: From the graph, we can see that points are increasing non-linearly, so, we cannot use a model linear model for this. We can also see that points are not growing rapidly,so, exponential model is not suitable. Hence, we chose logarithmic model. d. To determine find the model you chose in part (b) for the data and graph the model with scatter plot. Answer y = 2.151 + 2.7043 ln ( x ) Explanation Calculation: Now, by using the values of and from the data and graphing utility we get, X : V e c t o r ( [ 1 , 1.5 , 2 , 4 , 6 , 8 ] , d a t a t y p e = f l o a t ) ; X = 1. 1.50000000000000000 2. 4. 6. 8. Y : V e c t o r ( [ 2 , 3 , 5 , 4 , 5.8 , 7 , 7.8 ] , d a t a t y p e = f l o a t ) ; Y = 2. 3.50000000000000000 4. 5.79999999999999982 7. 7.79999999999999982 Hence, the required model is y = 2.151 + 2.7043 ln ( x ) . Now, the graph of scatter plot is, Hence, the graph is shown above. e. To determine Determine if the model you chose fits the data. Answer From the graph we can see that the model we get fits the data very well. Explanation Calculation: From the graph we can see that the model we get fits the data very well. Hence, logarithmic model fits the data very well.

4th Edition

ISBN: 9781337516853

Author: Larson

Publisher: CENGAGE CO

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Question

Chapter 3, Problem 23PS

To determine

Use a graphical utility to create a sactter plot of the data.

Expert Solution

Answer to Problem 23PS

The scatter plot of the data is given as

EBK PRECALCULUS W/LIMITS, Chapter 3, Problem 23PS , additional homework tip 1

Explanation of Solution

Calculation:

The scatter plot of the data is given as

EBK PRECALCULUS W/LIMITS, Chapter 3, Problem 23PS , additional homework tip 2

Hence, the graph is shown above.

To determine

Decide the model for data .

Expert Solution

Answer to Problem 23PS

logarithmic model.

Explanation of Solution

Calculation:

The best model for these points is logarithmic model

Hence, the data could be modelled by a logarithmic model

To determine

Explain the model of part (b) .

Expert Solution

Answer to Problem 23PS

From the graph, we can see that points are increasing non-linearly, so, we cannot use a model linear model for this. We can also see that points are not growing rapidly,so, exponential model is not suitable.

Explanation of Solution

Calculation:

Hence, we chose logarithmic model.

To determine

find the model you chose in part (b) for the data and graph the model with scatter plot.

Expert Solution

Answer to Problem 23PS

y=2.151+2.7043ln(x)

EBK PRECALCULUS W/LIMITS, Chapter 3, Problem 23PS , additional homework tip 3

Explanation of Solution

Calculation:

Now, by using the values of and from the data and graphing utility we get,

X:Vector([1,1.5,2,4,6,8],datatype=float);

X=1.1.500000000000000002.4.6.8.

Y:Vector([2,3,5,4,5.8,7,7.8],datatype=float);

Y=2.3.500000000000000004.5.799999999999999827.7.79999999999999982

Hence, the required model is y=2.151+2.7043ln(x) .

Now, the graph of scatter plot is,

EBK PRECALCULUS W/LIMITS, Chapter 3, Problem 23PS , additional homework tip 4

Hence, the graph is shown above.

To determine

Determine if the model you chose fits the data.

Expert Solution

Answer to Problem 23PS

From the graph we can see that the model we get fits the data very well.

Explanation of Solution

Calculation:

From the graph we can see that the model we get fits the data very well.

Hence, logarithmic model fits the data very well.

Chapter 3, Problem 22PS

Chapter 3, Problem 24PS

Chapter 3 Solutions

EBK PRECALCULUS W/LIMITS

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Publisher:Cengage Learning

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