# Chapter 3, Problem 3.131QP

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### CHEMISTRY: ATOMS FIRST VOL 1 W/CON...

14th Edition
Burdge
ISBN: 9781259327933

#### Solutions

Chapter
Section
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### CHEMISTRY: ATOMS FIRST VOL 1 W/CON...

14th Edition
Burdge
ISBN: 9781259327933
Interpretation Introduction

Interpretation:

The number of photons emitted by the light bulb per second if 75 W light bulb converts 15.0 percent of the energy supplied to it into visible light having the wavelength of 550 nm should be calculated using the relation between speed, wavelength and frequency of a wave and Planck’s quantum theory.

Concept Introduction:

A wave is a disturbance or variation that travels through a medium transporting energy without transporting matter.  The wavelength is the distance between identical points on successive waves.  The frequency is the number of waves that pass through any particular point in 1 second.

Figure 1

The speed, wavelength and frequency of a wave are related by the equation: = λν where λ and ν are expressed in meters (m) and reciprocal seconds (s1) respectively.

Planck’s quantum theory

• Different atoms and molecules can emit or absorb energy in discreet quantities only.  The smallest amount of energy that can be emitted or absorbed in the form of electromagnetic radiation is known as quantum.
• The energy of the radiation absorbed or emitted is directly proportional to the frequency of the radiation.  The energy of radiation is expressed in terms of frequency as, = hν where, E = energy of the radiation; h = Planck’s constant (6.626 × 1034 Js); ν = frequency of radiation.

To find: The number of photons emitted by the light bulb per second if 75 W light bulb converts 15.0 percent of the energy supplied to it into visible light having the wavelength of 550 nm using the relation between speed, wavelength and frequency of a wave and Planck’s quantum theory

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