Database System Concepts
7th Edition
ISBN: 9789332901384
Author: Henry F. Korth & S. Sudarshan Abraham Silberschatz
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Table: Employee
| Column Name| Type|
| id
| int |
| int |
| salary
+-
-------+
id is the primary key column for this table.
Each row of this table contains information about the salary of an employee.
Write an SQL query to report the second highest salary from the Employee table. If there is no second highest salary, the query should report
null.
Using the university schema, write an SQL query to find section(s) with maximum enrollment. The result columns should appear in the order “courseid, secid, year, semester, num”. (It may be convenient to use the with construct.)
Employee (Lastname, FirstName, MidInitial, gender, street, city)
Works (Lastname, FirstName, MidInitial, company-name, salary)
Company (company-name, city)
Write an RA query (Not SQL command) Find the names of companies which have employees living in Lincoln and Omaha. (If a company only has employees live in one of these two cities, not both, then it should not be included in the result.)
Chapter 3 Solutions
Database System Concepts
Ch. 3 - Prob. 1PECh. 3 - Prob. 2PECh. 3 - Prob. 3PECh. 3 -
Suppose that we have a relation marks(ID, score)...Ch. 3 - Suppose that we have a relation marks(ID, score)...Ch. 3 -
The SQL like operator is case sensitive (in most...Ch. 3 - Prob. 7PECh. 3 - Prob. 8PECh. 3 - Prob. 9PECh. 3 - Prob. 10PE
Ch. 3 - Prob. 11ECh. 3 - Prob. 12ECh. 3 - Prob. 13ECh. 3 -
Consider the insurance database of Figure 3.17,...Ch. 3 - Prob. 15ECh. 3 - Prob. 16ECh. 3 - Prob. 17ECh. 3 - Prob. 18ECh. 3 -
List two reasons why null values might be...Ch. 3 - Prob. 20ECh. 3 - Prob. 21ECh. 3 - Prob. 22ECh. 3 - Prob. 23ECh. 3 - Prob. 24ECh. 3 - Prob. 25ECh. 3 - Prob. 26ECh. 3 - Using the university schema, write an SQL query to...Ch. 3 - Prob. 28ECh. 3 - Prob. 29ECh. 3 - Prob. 30ECh. 3 - Prob. 31ECh. 3 - Prob. 32ECh. 3 - Prob. 33ECh. 3 - Prob. 34ECh. 3 - Prob. 35E
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- Repeat Exercise 4, but this time use the EXISTS operator in your query.arrow_forwardWrite the SQL code to calculate the ASSIGN_CHARGE values in the ASSIGNMENT table in the Ch07_ConstructCo database. (See Figure P7.1.) Note that ASSIGN_CHARGE is a derived attribute that is calculated by multiplying ASSIGN_CHG_HR by ASSIGN_HOURS.arrow_forward*Query in SQL required* Write a query to display student's Id and First Name whose from Coimbatore or Chennai and born on 8th Oct 1997. Sort the result set by student's Id. Student - Course Enrollement Management STUDENT COURSE PK Studld Number(4) PK courseid number(4) FirstName Varchar2(20) varchar2(20) number(2) CourseName LastName Varchar2(20) Duration Street Varchar2(20) Fees number(7,2) City Varchar2(20) DOB Date REGISTRATION number(4) number(4) PK-Primary key FK-Foreign key FK CourselD FK Studld DOJ Datearrow_forward
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