Angeline and Brad are planning to divide the chocolate-strawberry cake shown in Fig 3-40(a) using the divider-chooser method, with Angelina being the divider. Suppose that Angelina values chocolate cake three times as much as she values strawberry cake. Fig 3-40(a) shows a generic cut made by Angelina dividing the cake into two shares s 1 and s 2 of equal value to her. Think of s 1 as an " x " chocolate- y ° strawberry” share. For each given measure of the angel x , find the corresponding measure of the angle of y . F i g u r e 3 - 3 0 F u l l A l t e r n a t i v e T e x t _ a. x = 60 ° . b. x = 72 ° . c. x = 108 ° . d. x = 120 ° .
Angeline and Brad are planning to divide the chocolate-strawberry cake shown in Fig 3-40(a) using the divider-chooser method, with Angelina being the divider. Suppose that Angelina values chocolate cake three times as much as she values strawberry cake. Fig 3-40(a) shows a generic cut made by Angelina dividing the cake into two shares s 1 and s 2 of equal value to her. Think of s 1 as an " x " chocolate- y ° strawberry” share. For each given measure of the angel x , find the corresponding measure of the angle of y . F i g u r e 3 - 3 0 F u l l A l t e r n a t i v e T e x t _ a. x = 60 ° . b. x = 72 ° . c. x = 108 ° . d. x = 120 ° .
Solution Summary: The author illustrates how Angeline and Brad are planning to divide the chocolate-strawberry cake using the divider-chooser method.
Angeline and Brad are planning to divide the chocolate-strawberry cake shown in Fig 3-40(a) using the divider-chooser method, with Angelina being the divider. Suppose that Angelina values chocolate cake three times as much as she values strawberry cake. Fig 3-40(a) shows a generic cut made by Angelina dividing the cake into two shares
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At noon, ship A is 20 kilometers north of Ship B. Ship A is traveling south at 50 kilometers per hour, and ship B is traveling east at 40 kilometers per hour. If visibility is 10 kilometers, could the people on the two ships ever see each other?
Can you show the working for 2A + 2b = 6 and
3A - B = 1, in equation one I, want to follow all the steps
At 9:00AM, ship B is 65 km due east of another ship A. Ship B is then sailing due west at 10 km/h and A is sailing due south at 15 km/h. If they continue on their respective courses when will they be nearest one another?
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