HUMAN HEREDITY (LL)-W/MINDTAP ACCESS
11th Edition
ISBN: 9781305717022
Author: Cummings
Publisher: CENGAGE L
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Chapter 3, Problem 9QP
Crossing Pea Plants: Mendel’s Study of Single Traits
Sickle cell anemia (SCA) is a human genetic disorder caused by a recessive allele. A couple plan to marry and want to know the probability that they will have an affected child. With your knowledge of
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Mendelian Genetics and Non-Mendelian Genetics: Huntington’s disease, a neurodegenerative genetic disorder that typically becomes noticeable in middle age, is due to an autosomal dominant allele. Sickle cell anemia, on the other hand, is a genetic blood disorder due to a recessive allele. Jillian is a carrier of the allele for sickle cell anemia but has no sign of any neurodegenerative disorder in her family. She married Jacobwhose father died of Huntington’s disease. His mother, however, is not inflicted with that condition. Neither of his parents exhibit sickle cell anemia.
1. Give the genotypes of Jillian and Jacob.
Assuming that they will have 4 children, what is the probability that:
2. all their children will be normal?
3. they will have a son with Huntington’s disease?
4. they will have a daughter inflicted with both conditions
YOUR SISTER DIED FROM TAY-SACHS DISEASE, INHERITED AS A RECESSIVE ALLELE (t). you're married and planning to start your family. you're worried about the disease and decide to have genetic testing to see if you or your spouse is a carrier of the tay-sachs allele. the test results show that you're a carrier of the allele, but your spouse isn't. what is the probability that you and your spouse will have a child with tay-sachs disease? show your work.
Mendel’s observation that two different traits could be inherited independently of each other can be explained by understanding that:
During meiosis, the process of chromosome assortment into daughter cells is random
Alleles of the genes reside on homologous chromosomes
All of the listed choices are correct
During meiosis, maternal and paternal members of homologous chromosomes are distributed separately into daughter cells
Chapter 3 Solutions
HUMAN HEREDITY (LL)-W/MINDTAP ACCESS
Ch. 3.4 - Why do scientists design experiments to disprove...Ch. 3.4 - Should Ockhams razor be considered an irrefutable...Ch. 3.7 - Prob. 1EGCh. 3.7 - For most cases, a p value of 0.05 is used to...Ch. 3 - Prob. 1CSCh. 3 - Prob. 2CSCh. 3 - Prob. 3CSCh. 3 - Prob. 1QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...
Ch. 3 - Prob. 4QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Prob. 6QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Prob. 14QPCh. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Prob. 17QPCh. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Variations on a Theme by Mendel A characteristic...Ch. 3 - Prob. 29QPCh. 3 - Variations on a Theme by Mendel Pea plants usually...Ch. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QP
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- A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?arrow_forwardPedigree analysis is a fundamental tool for investigating whether or not a trait is following a Mendelian pattern of inheritance. It can also be used to help identify individuals within a family who may be at risk for the trait. Adam and Sarah, a young couple of Eastern European Jewish ancestry, went to a genetic counselor because they were planning a family and wanted to know what their chances were for having a child with a genetic condition. The genetic counselor took a detailed family history from both of them and discovered several traits in their respective families. Sarahs maternal family history is suggestive of an autosomal dominant pattern of cancer predisposition to breast and ovarian cancer because of the young ages at which her mother and grandmother were diagnosed with their cancers. If a mutant allele that predisposed to breast and ovarian cancer was inherited in Sarahs family, she, her sister, and any of her own future children could be at risk for inheriting this mutation. The counselor told her that genetic testing is available that may help determine if this mutant allele is present in her family members. Adams paternal family history has a very strong pattern of early onset heart disease. An autosomal dominant condition known as familial hypercholesterolemia may be responsible for the large number of deaths from heart disease. As with hereditary breast and ovarian cancer, genetic testing is available to see if Adam carries the mutant allele. Testing will give the couple more information about the chances that their children could inherit this mutation. Adam had a first cousin who died from Tay-Sachs disease (TSD), a fatal autosomal recessive condition most commonly found in people of Eastern European Jewish descent. Because TSD is a recessively inherited disorder, both of his cousins parents must have been heterozygous carriers of the mutant allele. If that is the case, Adams father could be a carrier as well. If Adams father carries the mutant TSD allele, it is possible that Adam inherited this mutation. Because Sarah is also of Eastern European Jewish ancestry, she could also be a carrier of the gene, even though no one in her family has been affected with TSD. If Adam and Sarah are both carriers, each of their children would have a 25% chance of being afflicted with TSD. A simple blood test performed on both Sarah and Adam could determine whether they are carriers of this mutation. If Sarah carries the mutant cancer allele and Adam carries the mutant heart disease allele, what is the chance that they would have a child who is free of both diseases? Are these good odds?arrow_forwardPedigree analysis is a fundamental tool for investigating whether or not a trait is following a Mendelian pattern of inheritance. It can also be used to help identify individuals within a family who may be at risk for the trait. Adam and Sarah, a young couple of Eastern European Jewish ancestry, went to a genetic counselor because they were planning a family and wanted to know what their chances were for having a child with a genetic condition. The genetic counselor took a detailed family history from both of them and discovered several traits in their respective families. Sarahs maternal family history is suggestive of an autosomal dominant pattern of cancer predisposition to breast and ovarian cancer because of the young ages at which her mother and grandmother were diagnosed with their cancers. If a mutant allele that predisposed to breast and ovarian cancer was inherited in Sarahs family, she, her sister, and any of her own future children could be at risk for inheriting this mutation. The counselor told her that genetic testing is available that may help determine if this mutant allele is present in her family members. Adams paternal family history has a very strong pattern of early onset heart disease. An autosomal dominant condition known as familial hypercholesterolemia may be responsible for the large number of deaths from heart disease. As with hereditary breast and ovarian cancer, genetic testing is available to see if Adam carries the mutant allele. Testing will give the couple more information about the chances that their children could inherit this mutation. Adam had a first cousin who died from Tay-Sachs disease (TSD), a fatal autosomal recessive condition most commonly found in people of Eastern European Jewish descent. Because TSD is a recessively inherited disorder, both of his cousins parents must have been heterozygous carriers of the mutant allele. If that is the case, Adams father could be a carrier as well. If Adams father carries the mutant TSD allele, it is possible that Adam inherited this mutation. Because Sarah is also of Eastern European Jewish ancestry, she could also be a carrier of the gene, even though no one in her family has been affected with TSD. If Adam and Sarah are both carriers, each of their children would have a 25% chance of being afflicted with TSD. A simple blood test performed on both Sarah and Adam could determine whether they are carriers of this mutation. Would you want to know the results of the cancer, heart disease, and TSD tests if you were Sarah and Adam? Is it their responsibility as potential parents to gather this type of information before they decide to have a child?arrow_forward
- Pedigree analysis is a fundamental tool for investigating whether or not a trait is following a Mendelian pattern of inheritance. It can also be used to help identify individuals within a family who may be at risk for the trait. Adam and Sarah, a young couple of Eastern European Jewish ancestry, went to a genetic counselor because they were planning a family and wanted to know what their chances were for having a child with a genetic condition. The genetic counselor took a detailed family history from both of them and discovered several traits in their respective families. Sarahs maternal family history is suggestive of an autosomal dominant pattern of cancer predisposition to breast and ovarian cancer because of the young ages at which her mother and grandmother were diagnosed with their cancers. If a mutant allele that predisposed to breast and ovarian cancer was inherited in Sarahs family, she, her sister, and any of her own future children could be at risk for inheriting this mutation. The counselor told her that genetic testing is available that may help determine if this mutant allele is present in her family members. Adams paternal family history has a very strong pattern of early onset heart disease. An autosomal dominant condition known as familial hypercholesterolemia may be responsible for the large number of deaths from heart disease. As with hereditary breast and ovarian cancer, genetic testing is available to see if Adam carries the mutant allele. Testing will give the couple more information about the chances that their children could inherit this mutation. Adam had a first cousin who died from Tay-Sachs disease (TSD), a fatal autosomal recessive condition most commonly found in people of Eastern European Jewish descent. Because TSD is a recessively inherited disorder, both of his cousins parents must have been heterozygous carriers of the mutant allele. If that is the case, Adams father could be a carrier as well. If Adams father carries the mutant TSD allele, it is possible that Adam inherited this mutation. Because Sarah is also of Eastern European Jewish ancestry, she could also be a carrier of the gene, even though no one in her family has been affected with TSD. If Adam and Sarah are both carriers, each of their children would have a 25% chance of being afflicted with TSD. A simple blood test performed on both Sarah and Adam could determine whether they are carriers of this mutation. Would you decide to have a child if the test results said that you carry the mutation for breast and ovarian cancer? The heart disease mutation? The TSD mutation? The heart disease and the mutant alleles?arrow_forwardCystic fibrosis is an autosomal disease that mainly affects the white population, and 1 in 20 whites are heterozygotes. Genetic testing can diagnose heterozygotes. Should a genetic screening program for cystic fibrosis be instituted? Should the federal government fund it? Should the program be voluntary or mandatory, and why?arrow_forwardAn allele responsible for Marfan syndrome Section 13.4 is inherited in an autosomal dominant pattern. What is the chance that a child will inherit the allele if one parent does not carry it and the other is heterozygous?arrow_forward
- Analysis of X-Linked Dominant and Recessive Traits As a genetic counselor investigating a genetic disorder in a family, you are able to collect a four-generation pedigree that details the inheritance of the disorder in question. Analyze the information in the pedigree to determine whether the trait is inherited as: a. autosomal dominant b. autosomal recessive c. X-linked dominant d. X-linked recessive e. Y-linkedarrow_forwardRed-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___arrow_forwardGeneticists are concerned about three different genetic conditions present within their family. Achondroplasia is an autosomal dominant genetic disorder that results in short-limbed dwarfism. (A = achondroplasia allele; a = average height allele). Red-Green Color blindness is an X-linked recessive genetic disorder (Xc = color blindness allele; XC = normal color vision allele). The 7-year-old son has an autosomal recessive form of deafness. (h = deafness allele; H = normal hearing allele.) All three family members were karyotyped, and additional genetic testing was performed to determine the chromosomal location of the genes being studied. The figures below show the karyotypes of the mother and father with respect to the chromosomes containing the three genes mentioned above. Question: The couple’s 7-year-old son has all three of these genetic conditions (achondroplasia, color blindness and deafness). Taking into consideration the genotypes of his parents, what is the complete…arrow_forward
- Sickle cell anemia is a blood disorder that is expressed with incomplete dominance. The homozygous recessive phenotype has sickle shaped red blood cells that cause anemia and often death if untreated. If an unaffected father and mother move to the United States from Sub-Saharan Africa and several of their offspring have sickle cell anemia, what do we know about both parents' genotypes? One is homozygous recessive, the other is heterozygous They are both heterozygous They are both homozygous recessive One is homozygous dominant, the other is heterozygousarrow_forwardRegarding Mendelian inheritance in diploid individuals, (Read each statement carefully. Select all of the statements below that are true (that you agree with). Leave any statements that are false (that you do not agree with) un- selected.) a diploid individual receives two copies of every autosome from the previous generation. for every autosomal gene inherited by an individual, both copies can come from one parent. a diploid individual gives two copies of every autosome to a child in the next generation. to be diploid means that two independent genes are specified in the individual's genotype.arrow_forwardMendel's independent assortment: Draw a cell with a diploid chromosome number of 4. The gene controlling flower color (pink/white) is not linked to the gene for height (short/tall). Draw the cells and chromosomes in the process of meiosis (meiosis I followed by meiosis II, not all individual stages) in a plant clearly heterozygous for both traits. Be sure your answer demonstrates your understanding of Mendel’s 2nd law of inheritance. PLEASE HELP. This is all of the information.arrow_forward
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