Chapter 30.2, Problem 29SSC

To determine

To Explain:

The process for expulsion of electron during beta decay from a nucleus with no electron.

Answer to Problem 29SSC

During beta decay as the neutrons in the nucleus change into a proton which results in the emission of electrons and anti-neutrinos and the electron is expelled from the nucleus.

Explanation of Solution

Introduction:

Beta decay is a radioactive decay where a beta particle transforms the original nuclide to an isobar which is been emitted from an atomic nucleus.A beta particle is known to be a fast energetic electron.

In beta decay, conversion of neutron into proton takes place and however, the atomic number of the element is increased by 1.

In the nucleus, the neutrons convert into a proton.This process emits electrons and anti-neutrino.As beta particle is a fast energetic electron,however the process of beta decay require electron.Therefore, if nucleus has no electrons present, the electrons will be expelled from the nucleus during the process of beta decay.

Conclusion:

Hence, during beta decay as the neutrons in the nucleus convert into a proton which results in the emission of electrons and anti-neutrinos and the electron is expelled from the nucleus.