Modified Mastering Physics With Pearson Etext -- Standalone Access Card -- For Physics For Scientists & Engineers With Modern Physics (5th Edition)
5th Edition
ISBN: 9780134402628
Author: Douglas C. Giancoli
Publisher: PEARSON
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Chapter 32, Problem 6Q
To determine
Whether mirror equation hold for plane mirror or not.
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Chapter 32 Solutions
Modified Mastering Physics With Pearson Etext -- Standalone Access Card -- For Physics For Scientists & Engineers With Modern Physics (5th Edition)
Ch. 32 - What would be the appearance of the Moon if it had...Ch. 32 - Archimedes is said to have burned the whole Roman...Ch. 32 - What is the focal length of a plane mirror? What...Ch. 32 - An object is placed along the principal axis of a...Ch. 32 - Using the rules for the three rays discussed with...Ch. 32 - Prob. 6QCh. 32 - If a concave mirror produces a real image, is the...Ch. 32 - Prob. 8QCh. 32 - When you look at the Moons reflection from a...Ch. 32 - How can a spherical mirror have a negative object...
Ch. 32 - Prob. 11QCh. 32 - When you look down into a swimming pool or a lake,...Ch. 32 - Draw a ray diagram to show why a stick looks bent...Ch. 32 - (I) When you look at yourself in a 60-cm-tall...Ch. 32 - (II) Show that if two plane mirrors meet at an...Ch. 32 - (II) The block of glass (n = 1.5) shown in cross...Ch. 32 - (II) Show in general that for a light beam...Ch. 32 - (III) A light ray is incident on a flat piece of...Ch. 32 - (I) By what percent is the speed of blue light...Ch. 32 - (I) A light beam strikes a piece of glass at a...Ch. 32 - (II) A parallel beam of light containing two...Ch. 32 - Two identical concave mirrors are set facing each...Ch. 32 - A kaleidoscope makes symmetric patterns with two...
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- For specular reflection, what is the situation with an angle of incidence of (a) 0 and (b) 90?arrow_forwardA lamp of height S cm is placed 40 cm in front of a converging lens of focal length 20 cm. There is a plane mirror 15 cm behind the lens. Where would you find the image when you look in the mirror?arrow_forwardThe disk of the Sun subtends an angle of 0.533 at the Earth. What are (a) the position and (b) the diameter of the solar image formed by a concave spherical mirror with a radius of curvature of magnitude 3.00 m?arrow_forward
- Two rays travelling parallel to the principal axis strike a large plano-convex lens having a refractive index of 1.60 (Fig. P23.54). If the convex face is spherical, a ray near the edge does not pass through the local point (spherical aberration occurs). Assume this face has a radius of curvature of R = 20.0 cm and the two rays are at distances h1 = 0.500 cm and h2 = 12.0 cm from the principal axis. Find the difference x in the position where each crosses the principal axis. Figure P23.54arrow_forwardFigure P38.43 shows a concave meniscus lens. If |r1| = 8.50 cm and |r2| = 6.50 cm, find the focal length and determine whether the lens is converging or diverging. The lens is made of glass with index of refraction n = 1.55. CHECK and THINK: How do your answers change if the object is placed on the right side of the lens? FIGURE P38.43arrow_forwardA thin plastic lens with index of refraction n = 1.67 has radii of curvature given by R1 = 12 0 cm and R2 = 40.0 cm. Determine (a) the focal length of the lens, (b) whether the lens Ls converging or diverging and the image distances for object distances of (c) infinity, (d) 8,00 cm, and (e) 50.0 cm.arrow_forward
- A student’s eyes, while reading the blackboard, have a power of 51.0 D. How far is the board from his eyes?arrow_forwardFigure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forwardA point source of light is 50 cm in front of a converging lens of focal length 30 cm. A concave mirror with a focal length of 20 cm is placed 25 cm behind the lens. Where does the final image form, and what are its orientation and magnification?arrow_forward
- An object is placed a distance of 10.0 cm to the left of a thin converging lens of focal length f = 8.00 cm, and a concave spherical mirror with radius of curvature +18.0 cm is placed a distance of 45.0 cm to the right of the lens (Fig. P38.129). a. What is the location of the final image formed by the lensmirror combination as seen by an observer positioned to the left of the object? b. What is the magnification of the final image as seen by an observer positioned to the left of the object? c. Is the final image formed by the lensmirror combination upright or inverted? FIGURE P38.129arrow_forwardTwo thin lenses of focal lengths f1 = 15.0 and f2 = 10.0 cm, respectively, are separated by 35.0 cm along a common axis. The f1 lens is located to the left of the f2 lens. An object is now placed 50.0 cm to the left of the f1 lens, and a final image due to light passing though both lenses forms. By what factor is the final image different in size from the object? (a) 0.600 (b) 1.20 (c) 2.40 (d) 3.60 (e) none of those answersarrow_forwardAn object 2.00 cm high is placed 40.0 cm to the left of a converging lens having a focal length of 30.0 cm. A diverging lens with a focal length of -20.0 cm is placed 110 cm to the right of the converging lens. Determine (a) the position and (b) the magnification of the final image, (c) Is the image upright or inverted? (d) What If? Repeat parts (a) through (c) for the case in which the second lens is a converging lens having a focal length of 20.0 cm.arrow_forward
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