Concept explainers
a.
The graph of the data and connect each pair of adjacent points with a line
a.
Explanation of Solution
The season represented by x-axis.
The average points per game (PPG) represented by y-axis.
The given table is:
Season (x-axis) | PPG (y-axis) |
1 | 2.2 |
2 | 11.4 |
3 | 15.1 |
4 | 21.7 |
5 | 23 |
6 | 25.4 |
7 | 26.7 |
8 | 22.7 |
9 | 21.2 |
Using the above table the graph can be plotted.
Graph:
Conclusion:
The above is the required graph.
b.
The interval in which the rate of change is maximum.
b.
Answer to Problem 47PPS
The maximum rate of change is in the interval of the season 1-2.
Explanation of Solution
Formula Used:
For the two points
Calculation:
The calculation for the rate of change for the intervals:
Interval | Rate of Change |
1-2 | |
2-3 | |
3-4 | |
4-5 | |
5-6 | |
6-7 | |
7-8 | |
8-9 |
Interpretation:
From above table, it is clear that, the maximum rate of change is 9.2 which is in the interval of season 1-2.
Conclusion:
The required interval is from season 1-2.
c.
The difference of rate of change from season 1 through season 4 , from season 4 through season 7 and from season 7 through season 9.
c.
Answer to Problem 47PPS
The difference is 7.58.
Explanation of Solution
Formula Used:
For the two points
Calculation:
The calculation for the rate of change for required intervals is shown below.
Interval | Rate of Change |
1-4 | |
4-7 | |
7-9 |
Interpretation:
The rate of change from season 1 through season 4 is 6.5.
The rate of change from season 4 through season 7 is 1.67.
The rate of change from season 7 through season 9 is -2.75.
The required difference of rate of change from season 1 through season 4 , from season 4 through season 7 and from season 7 through season 9 =
Conclusion:
The final rate of change is 7.58.
Chapter 3 Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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