Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
2nd Edition
ISBN: 9780076602919
Author: McGraw-Hill Education
Publisher: McGraw-Hill Education
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Question
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Chapter 3.8, Problem 66PFA

(a)

To determine

The graph of the function.

(a)

Expert Solution
Check Mark

Answer to Problem 66PFA

Therefore, graph of the function is represented as,

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip  1

Explanation of Solution

Given information: The equation in terms of x is given as,

  g(x)=15|x20|+2

The general form is given as,

  f(x)=a|xh|+kOn compairing with general form,a=15,h=20,k=2

Therefore, graph of the function is represented as,

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip  2

(b)

To determine

The vertex of the function.

(b)

Expert Solution
Check Mark

Answer to Problem 66PFA

Therefore, the vertex of the function is (20,2) it is represented as by (h,k).

Explanation of Solution

Given information: The equation in terms of x is given as,

  g(x)=15|x20|+2

The vertex for the function’s graph is given as by comparing it with general form,

  f(x)=a|xh|+kOn compairing with general form,a=15,h=20,k=2

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip  3

The vertex of the function is (20,2) it is represented as by (h,k).

(c)

To determine

The distance between ship and lighthouse when spotted by captain.

(c)

Expert Solution
Check Mark

Answer to Problem 66PFA

Therefore, distance between ship and lighthouse is 6 units.

Explanation of Solution

Given information: The equation in terms of x is given as,

  g(x)=15|x20|+2

The distance from ship to lighthouse when the captain first spots it,

  Putting x=0 we get,g(0)=15|020|+2g(0)=6.

So, therefore distance between ship and lighthouse is 6 units.

(d)

To determine

The graph g(x) as a transformation of the graph of f(x)=|x|.

(d)

Expert Solution
Check Mark

Answer to Problem 66PFA

Thereforetransformation of g(x) as f(x) is ,

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip  4

Explanation of Solution

Given information: The equation in terms of x is given as,

  g(x)=15|x20|+2

The graph g(x)=15|x20|+2 as a transformation of the graph of f(x)=|x| is represented as,

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 3.8, Problem 66PFA , additional homework tip  5

Chapter 3 Solutions

Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42PPSCh. 3.1 - Prob. 43PPSCh. 3.1 - Prob. 44PPSCh. 3.1 - Prob. 45PPSCh. 3.1 - Prob. 46PPSCh. 3.1 - Prob. 47PPSCh. 3.1 - Prob. 48PPSCh. 3.1 - Prob. 49PPSCh. 3.1 - 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Prob. 3CYUCh. 3.5 - Prob. 4CYUCh. 3.5 - Prob. 5CYUCh. 3.5 - Prob. 6CYUCh. 3.5 - Prob. 7CYUCh. 3.5 - Prob. 8CYUCh. 3.5 - Prob. 9CYUCh. 3.5 - Prob. 10CYUCh. 3.5 - Prob. 11CYUCh. 3.5 - Prob. 12PPSCh. 3.5 - Prob. 13PPSCh. 3.5 - Prob. 14PPSCh. 3.5 - Prob. 15PPSCh. 3.5 - Prob. 16PPSCh. 3.5 - Prob. 17PPSCh. 3.5 - Prob. 18PPSCh. 3.5 - Prob. 19PPSCh. 3.5 - Prob. 20PPSCh. 3.5 - Prob. 21PPSCh. 3.5 - Prob. 22PPSCh. 3.5 - Prob. 23PPSCh. 3.5 - Prob. 24PPSCh. 3.5 - Prob. 25PPSCh. 3.5 - Prob. 26PPSCh. 3.5 - Prob. 27PPSCh. 3.5 - Prob. 28PPSCh. 3.5 - Prob. 29PPSCh. 3.5 - Prob. 30PPSCh. 3.5 - Prob. 31PPSCh. 3.5 - Prob. 32PPSCh. 3.5 - Prob. 33PPSCh. 3.5 - Prob. 34PPSCh. 3.5 - Prob. 35PPSCh. 3.5 - Prob. 36PPSCh. 3.5 - Prob. 37PPSCh. 3.5 - Prob. 38PPSCh. 3.5 - Prob. 39PPSCh. 3.5 - Prob. 40PPSCh. 3.5 - Prob. 41PPSCh. 3.5 - Prob. 42PPSCh. 3.5 - Prob. 43PPSCh. 3.5 - Prob. 44PPSCh. 3.5 - Prob. 45PPSCh. 3.5 - Prob. 46PPSCh. 3.5 - Prob. 47PPSCh. 3.5 - Prob. 48PPSCh. 3.5 - Prob. 49PPSCh. 3.5 - Prob. 50PPSCh. 3.5 - Prob. 51PPSCh. 3.5 - Prob. 52HPCh. 3.5 - Prob. 53HPCh. 3.5 - Prob. 54HPCh. 3.5 - Prob. 55HPCh. 3.5 - Prob. 56HPCh. 3.5 - Prob. 57PFACh. 3.5 - Prob. 58PFACh. 3.5 - Prob. 59PFACh. 3.5 - Prob. 60PFACh. 3.5 - Prob. 61PFACh. 3.5 - Prob. 62PFACh. 3.5 - Prob. 63PFACh. 3.5 - Prob. 64PFACh. 3.6 - Prob. 1AGPCh. 3.6 - Prob. 1BGPCh. 3.6 - Prob. 2GPCh. 3.6 - Prob. 3AGPCh. 3.6 - Prob. 3BGPCh. 3.6 - Prob. 3CGPCh. 3.6 - Prob. 3DGPCh. 3.6 - Prob. 4GPCh. 3.6 - Prob. 1CYUCh. 3.6 - Prob. 2CYUCh. 3.6 - Prob. 3CYUCh. 3.6 - Prob. 4CYUCh. 3.6 - Prob. 5CYUCh. 3.6 - Prob. 6CYUCh. 3.6 - Prob. 7CYUCh. 3.6 - Prob. 8PPSCh. 3.6 - Prob. 9PPSCh. 3.6 - Prob. 10PPSCh. 3.6 - Prob. 11PPSCh. 3.6 - Prob. 12PPSCh. 3.6 - Prob. 13PPSCh. 3.6 - Prob. 14PPSCh. 3.6 - Prob. 15PPSCh. 3.6 - Prob. 16PPSCh. 3.6 - Prob. 17PPSCh. 3.6 - Prob. 18PPSCh. 3.6 - Prob. 19PPSCh. 3.6 - Prob. 20PPSCh. 3.6 - Prob. 21PPSCh. 3.6 - Prob. 22PPSCh. 3.6 - Prob. 23PPSCh. 3.6 - Prob. 24PPSCh. 3.6 - Prob. 25PPSCh. 3.6 - Prob. 26PPSCh. 3.6 - Prob. 27PPSCh. 3.6 - 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Prob. 13MCQCh. 3 - Prob. 14MCQCh. 3 - Prob. 15MCQCh. 3 - Prob. 16MCQCh. 3 - Prob. 17MCQCh. 3 - Prob. 18MCQCh. 3 - Prob. 19MCQCh. 3 - Prob. 20MCQCh. 3 - Prob. 21MCQCh. 3 - Prob. 22MCQCh. 3 - Prob. 23MCQCh. 3 - Prob. 24MCQCh. 3 - Prob. 25MCQCh. 3 - Prob. 26MCQCh. 3 - Prob. 1SGRCh. 3 - Prob. 2SGRCh. 3 - Prob. 3SGRCh. 3 - Prob. 4SGRCh. 3 - Prob. 5SGRCh. 3 - Prob. 6SGRCh. 3 - Prob. 7SGRCh. 3 - Prob. 8SGRCh. 3 - Prob. 9SGRCh. 3 - Prob. 10SGRCh. 3 - Prob. 11SGRCh. 3 - Prob. 12SGRCh. 3 - Prob. 13SGRCh. 3 - Prob. 14SGRCh. 3 - Prob. 15SGRCh. 3 - Prob. 16SGRCh. 3 - Prob. 17SGRCh. 3 - Prob. 18SGRCh. 3 - Prob. 19SGRCh. 3 - Prob. 20SGRCh. 3 - Prob. 21SGRCh. 3 - Prob. 22SGRCh. 3 - Prob. 23SGRCh. 3 - Prob. 24SGRCh. 3 - Prob. 25SGRCh. 3 - Prob. 26SGRCh. 3 - Prob. 27SGRCh. 3 - Prob. 28SGRCh. 3 - Prob. 29SGRCh. 3 - Prob. 30SGRCh. 3 - Prob. 31SGRCh. 3 - Prob. 32SGRCh. 3 - Prob. 33SGRCh. 3 - Prob. 34SGRCh. 3 - Prob. 35SGRCh. 3 - Prob. 36SGRCh. 3 - Prob. 37SGRCh. 3 - Prob. 38SGRCh. 3 - Prob. 39SGRCh. 3 - Prob. 40SGRCh. 3 - 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Prob. 17PTCh. 3 - Prob. 18PTCh. 3 - Prob. 19PTCh. 3 - Prob. 20PTCh. 3 - Prob. 21PTCh. 3 - Prob. 22PTCh. 3 - Prob. 23PTCh. 3 - Prob. 24PTCh. 3 - Prob. 25PTCh. 3 - Prob. 26PTCh. 3 - Prob. 27PTCh. 3 - Prob. 1CRCh. 3 - Prob. 2CRCh. 3 - Prob. 3CRCh. 3 - Prob. 4CRCh. 3 - Prob. 5CRCh. 3 - Prob. 6CRCh. 3 - Prob. 7CRCh. 3 - Prob. 8CRCh. 3 - Prob. 9CRCh. 3 - Prob. 10CRCh. 3 - Prob. 11CRCh. 3 - Prob. 12CRCh. 3 - Prob. 13CRCh. 3 - Prob. 14CR
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Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
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Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
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College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
Inverse Functions; Author: Professor Dave Explains;https://www.youtube.com/watch?v=9fJsrnE1go0;License: Standard YouTube License, CC-BY