Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
2nd Edition
ISBN: 9780076602919
Author: McGraw-Hill Education
Publisher: McGraw-Hill Education
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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Question
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Chapter 3.4, Problem 74PFA

a.

To determine

To calculate: The monthly cost of the gym.

a.

Expert Solution
Check Mark

Answer to Problem 74PFA

The monthly cost of the gym is $40.

Explanation of Solution

Given:

Paul joins a gym that has an initial membership fee and a monthly cost. He pays a total of $295 after 3 months, and $495 after 8 months.

Calculation:

Let the initial membership fee be x and monthly cost be y .

Then, after 3 months total cost will be x+3y

And, after 8 months total cost will be x+8y

By problem, Paul pays a total of $295 after 3 months, and $495 after 8 months.

Then,

  x+3y=295...............(1)x+8y=495...............(2)

Subtracting (1) from (2),

  x+8y−x−3y=495−295⇒8y−3y=200⇒5y=200⇒y=40

Conclusion:

The monthly cost of the gym is $40.

b.

To determine

To calculate:The initial membership fee of the gym.

b.

Expert Solution
Check Mark

Answer to Problem 74PFA

The initial membership fee of the gym is $175.

Explanation of Solution

Given:

Paul joins a gym that has an initial membership fee and a monthly cost. He pays a total of $295 after 3 months, and $495 after 8 months.

Calculation:

Putting y=40 in (1),

  x+3y=295⇒x+3×40=295⇒x+120=295⇒x=295−120⇒x=175

Conclusion:

The initial membership fee of the gym is $175.

c.

To determine

To calculate:An equation for the total cost C as a function of the number of months, m .

c.

Expert Solution
Check Mark

Answer to Problem 74PFA

An equation for the total cost C as a function of the number of months, m is C=175+40m

Explanation of Solution

Given:

Paul joins a gym that has an initial membership fee and a monthly cost. He pays a total of $295 after 3 months, and $495 after 8 months.

Calculation:

The initial fee of the gym is $175.

The monthly cost of the gym per month is $40.

Then, the monthly cost for m months is $ 40m .

Therefore, total cost of the gym for m months =175+40m

Here C is the total cost.

Then, C=175+40m

Conclusion:

An equation for the total cost C as a function of the number of months, m is C=175+40m

d.

To determine

To calculate:The amount Paul will be paid after one year.

d.

Expert Solution
Check Mark

Answer to Problem 74PFA

Paul will pay $655 after one year.

Explanation of Solution

Given:

Paul joins a gym that has an initial membership fee and a monthly cost. He pays a total of $295 after 3 months, and $495 after 8 months.

Calculation:

The total cost of gym for m months is 175+40m

Then, the total cost for one year, that is, 12 months

  =175+40×12=175+480=655

Conclusion:

Paul will pay $655 after one year.

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Chapter 3.4, Problem 73PFA
Next
Chapter 3.5, Problem 1AGP

Chapter 3 Solutions

Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)

Ch. 3.1 - Prob. 1AGPCh. 3.1 - Prob. 1BGPCh. 3.1 - Prob. 2GPCh. 3.1 - Prob. 3GPCh. 3.1 - Prob. 4AGPCh. 3.1 - Prob. 4BGPCh. 3.1 - Prob. 5AGPCh. 3.1 - Prob. 5BGPCh. 3.1 - Prob. 5CGPCh. 3.1 - Prob. 1CYU
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Prob. 13MCQCh. 3 - Prob. 14MCQCh. 3 - Prob. 15MCQCh. 3 - Prob. 16MCQCh. 3 - Prob. 17MCQCh. 3 - Prob. 18MCQCh. 3 - Prob. 19MCQCh. 3 - Prob. 20MCQCh. 3 - Prob. 21MCQCh. 3 - Prob. 22MCQCh. 3 - Prob. 23MCQCh. 3 - Prob. 24MCQCh. 3 - Prob. 25MCQCh. 3 - Prob. 26MCQCh. 3 - Prob. 1SGRCh. 3 - Prob. 2SGRCh. 3 - Prob. 3SGRCh. 3 - Prob. 4SGRCh. 3 - Prob. 5SGRCh. 3 - Prob. 6SGRCh. 3 - Prob. 7SGRCh. 3 - Prob. 8SGRCh. 3 - Prob. 9SGRCh. 3 - Prob. 10SGRCh. 3 - Prob. 11SGRCh. 3 - Prob. 12SGRCh. 3 - Prob. 13SGRCh. 3 - Prob. 14SGRCh. 3 - Prob. 15SGRCh. 3 - Prob. 16SGRCh. 3 - Prob. 17SGRCh. 3 - Prob. 18SGRCh. 3 - Prob. 19SGRCh. 3 - Prob. 20SGRCh. 3 - Prob. 21SGRCh. 3 - Prob. 22SGRCh. 3 - Prob. 23SGRCh. 3 - Prob. 24SGRCh. 3 - Prob. 25SGRCh. 3 - Prob. 26SGRCh. 3 - Prob. 27SGRCh. 3 - Prob. 28SGRCh. 3 - Prob. 29SGRCh. 3 - Prob. 30SGRCh. 3 - Prob. 31SGRCh. 3 - Prob. 32SGRCh. 3 - Prob. 33SGRCh. 3 - Prob. 34SGRCh. 3 - Prob. 35SGRCh. 3 - Prob. 36SGRCh. 3 - Prob. 37SGRCh. 3 - Prob. 38SGRCh. 3 - Prob. 39SGRCh. 3 - Prob. 40SGRCh. 3 - Prob. 41SGRCh. 3 - Prob. 42SGRCh. 3 - Prob. 43SGRCh. 3 - Prob. 44SGRCh. 3 - Prob. 45SGRCh. 3 - Prob. 46SGRCh. 3 - Prob. 47SGRCh. 3 - Prob. 48SGRCh. 3 - Prob. 49SGRCh. 3 - Prob. 50SGRCh. 3 - Prob. 51SGRCh. 3 - Prob. 52SGRCh. 3 - Prob. 53SGRCh. 3 - Prob. 54SGRCh. 3 - Prob. 55SGRCh. 3 - Prob. 56SGRCh. 3 - Prob. 57SGRCh. 3 - Prob. 58SGRCh. 3 - Prob. 59SGRCh. 3 - Prob. 60SGRCh. 3 - Prob. 61SGRCh. 3 - Prob. 62SGRCh. 3 - Prob. 63SGRCh. 3 - Prob. 64SGRCh. 3 - Prob. 65SGRCh. 3 - Prob. 66SGRCh. 3 - Prob. 67SGRCh. 3 - Prob. 68SGRCh. 3 - Prob. 69SGRCh. 3 - Prob. 70SGRCh. 3 - Prob. 71SGRCh. 3 - Prob. 72SGRCh. 3 - Prob. 73SGRCh. 3 - Prob. 74SGRCh. 3 - Prob. 75SGRCh. 3 - Prob. 76SGRCh. 3 - Prob. 77SGRCh. 3 - Prob. 78SGRCh. 3 - Prob. 1PTCh. 3 - Prob. 2PTCh. 3 - Prob. 3PTCh. 3 - Prob. 4PTCh. 3 - Prob. 5PTCh. 3 - Prob. 6PTCh. 3 - Prob. 7PTCh. 3 - Prob. 8PTCh. 3 - Prob. 9PTCh. 3 - Prob. 10PTCh. 3 - Prob. 11PTCh. 3 - Prob. 12PTCh. 3 - Prob. 13PTCh. 3 - Prob. 14PTCh. 3 - Prob. 15PTCh. 3 - Prob. 16PTCh. 3 - Prob. 17PTCh. 3 - Prob. 18PTCh. 3 - Prob. 19PTCh. 3 - Prob. 20PTCh. 3 - Prob. 21PTCh. 3 - Prob. 22PTCh. 3 - Prob. 23PTCh. 3 - Prob. 24PTCh. 3 - Prob. 25PTCh. 3 - Prob. 26PTCh. 3 - Prob. 27PTCh. 3 - Prob. 1CRCh. 3 - Prob. 2CRCh. 3 - Prob. 3CRCh. 3 - Prob. 4CRCh. 3 - Prob. 5CRCh. 3 - Prob. 6CRCh. 3 - Prob. 7CRCh. 3 - Prob. 8CRCh. 3 - Prob. 9CRCh. 3 - Prob. 10CRCh. 3 - Prob. 11CRCh. 3 - Prob. 12CRCh. 3 - Prob. 13CRCh. 3 - Prob. 14CR

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