Explanation Write the expression for the Compton Effect in terms of energy for θ = 90 ° . 1 E = 1 E 0 + 1 m c 2 E 0 is the initial photon energy m is the mass of electron E is the photon energy c is the speed of light Rewrite the above equation in terms of E . 1 E = E 0 + m c 2 E 0 m c 2 E = E 0 m c 2 E 0 + m c 2 Write the expression for the kinetic energy of the electron. K = ( γ − 1 ) m c 2 (1) K is the kinetic energy of the electron Write the expression for the kinetic energy of the electron in terms of initial photon energy. K = E 0 − E Use E 0 m c 2 E 0 + m c 2 for E in the above equation to rewrite. K = E 0 − E 0 m c 2 E 0 + m c 2 = E 0 2 + E 0 m c 2 − E 0 m c 2 E 0 + m c 2 = E 0 2 E 0 + m c 2 (2) Equate equation (1) and (2) to calculate initial photon energy. E 0 2 E 0 + m c 2 = ( γ − 1 ) m c 2 E 0 ( γ − 1 ) m c 2 + ( γ − 1 ) m 2 c 4 = E 0 2 E 0 2 − E 0 ( γ − 1 ) m c 2 − ( γ − 1 ) m 2 c 4 = 0 The above equations are in quadratic form with a = 1 , b = − ( γ − 1 ) m c 2 and c = − ( γ − 1 ) m 2 c 4

Modified Mastering Physics With Pearson Etext -- Standalone Access Card -- For Essential University Physics (3rd Edition)

3rd Edition

ISBN: 9780133857221

Author: Richard Wolfson

Publisher: PEARSON

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Chapter 34, Problem 75P

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The expression for the initial photon energy.

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Chapter 34, Problem 74P

Chapter 34, Problem 76P

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Chapter 34 Solutions

Modified Mastering Physics With Pearson Etext -- Standalone Access Card -- For Essential University Physics (3rd Edition)

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The expression for the initial photon energy.

Solution Summary: The author explains the expression for the Compton Effect in terms of energy for theta =90°.

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Chapter 34 Solutions