Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00 Edition
ISBN: 9780395977224
Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher: McDougal Littell
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Question
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Chapter 3.5, Problem 14P
To determine

To find: the dimensions of the rectangle

Expert Solution & Answer
Check Mark

Answer to Problem 14P

The length of the rectangle is 16.8 and width of the rectangle is 33.6

Explanation of Solution

Given information: “The length of the rectangle is twice the width”, “The perimeter is 84 cm more than the width”

Concept Involved:

Perimeter of rectangle means sum of all the sides of the rectangle

Assign variable for the unknown that we need to find.

Use the keywords in the statement to rewrite the statement to meaningful math equation.

“is” means =

“shorter than” means -

Solve the equation by getting the variable in one side of the equation and undoing whatever is done to it by performing reverse operation.

Calculation: Assign variable for the unknown that we need to find

Let x be the width of the rectangle.

Write an expression to represent the length of the rectangle given the description “The length of a rectangle is twice the width”

2x is the length of the rectangle

Replace the keywords to get an equation representing the sentence given “The perimeter is 84 more than the width”

  x+2x+x+2x=84+x

Combine like terms in right side of the equation

  6x=84+x

In the process of getting x in one side of the equation subtract x on both sides

  6xx=84+xx

Combine like terms on both sides

  5x=84

Divide 5 on both sides of the equation

  5x5=845

Simplify fraction on both sides of the equation

  x=16.8

Substitute 16.8 for x in the expression 2x to find the length of the rectangle

  2(16.8)=33.6

Conclusion:

The length of the rectangle is 16.8 and width of the rectangle is 33.6

  Algebra: Structure And Method, Book 1, Chapter 3.5, Problem 14P

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

Ch. 3.1 - Prob. 11OECh. 3.1 - Prob. 12OECh. 3.1 - Prob. 13OECh. 3.1 - Prob. 14OECh. 3.1 - Prob. 15OECh. 3.1 - Prob. 16OECh. 3.1 - Prob. 17OECh. 3.1 - Prob. 18OECh. 3.1 - Prob. 19OECh. 3.1 - Prob. 20OECh. 3.1 - Prob. 21OECh. 3.1 - Prob. 1WECh. 3.1 - Prob. 2WECh. 3.1 - Prob. 3WECh. 3.1 - Prob. 4WECh. 3.1 - Prob. 5WECh. 3.1 - Prob. 6WECh. 3.1 - Prob. 7WECh. 3.1 - Prob. 8WECh. 3.1 - Prob. 9WECh. 3.1 - Prob. 10WECh. 3.1 - Prob. 11WECh. 3.1 - Prob. 12WECh. 3.1 - Prob. 13WECh. 3.1 - Prob. 14WECh. 3.1 - Prob. 15WECh. 3.1 - Prob. 16WECh. 3.1 - Prob. 17WECh. 3.1 - Prob. 18WECh. 3.1 - Prob. 19WECh. 3.1 - Prob. 20WECh. 3.1 - Prob. 21WECh. 3.1 - Prob. 22WECh. 3.1 - Prob. 23WECh. 3.1 - Prob. 24WECh. 3.1 - Prob. 25WECh. 3.1 - Prob. 26WECh. 3.1 - Prob. 27WECh. 3.1 - Prob. 28WECh. 3.1 - Prob. 29WECh. 3.1 - Prob. 30WECh. 3.1 - Prob. 31WECh. 3.1 - Prob. 32WECh. 3.1 - Prob. 33WECh. 3.1 - Prob. 34WECh. 3.1 - Prob. 35WECh. 3.1 - Prob. 36WECh. 3.1 - Prob. 37WECh. 3.1 - Prob. 38WECh. 3.1 - Prob. 39WECh. 3.1 - 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