Algebra: Structure And Method, Book 1

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 3.6, Problem 5P

To determine

To find the number of Calories in an orange and in a peach for the given problem.

Expert Solution & Answer

Answer to Problem 5P

A peach has 35 calories and an orange has 65 calories.

Explanation of Solution

Given information:

An orange has 30 calories more than a peach and 13 peaches have as many calories as 7 oranges.

Solution:

Let the calories in a peach = x calories.

According to the first condition:

Calories in an orange (30 more than x calories) = x+30 calories.

According to the second condition:

Number of Calories in 13 peaches = Number of calories in 7 oranges.

Therefore,

13x=7(x+30)

Distribute 7(x+30) we get 7x+210 .

⇒13x=7x+210

Subtract 7x on both sides:

13x−7x=7x+210−7x

⇒6x=210

Divide both sides by 6

6x6=2106

⇒x=35

Therefore, the calories in a peach are 35.

And calories in an orange = x+30 = x+30=35+30=65 .

Chapter 3.6, Problem 4P

Chapter 3.6, Problem 6P

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

Ch. 3.1 - Prob. 1OE Ch. 3.1 - Prob. 2OE Ch. 3.1 - Prob. 3OE Ch. 3.1 - Prob. 4OE Ch. 3.1 - Prob. 5OE Ch. 3.1 - Prob. 6OE Ch. 3.1 - Prob. 7OE Ch. 3.1 - Prob. 8OE Ch. 3.1 - Prob. 9OE Ch. 3.1 - Prob. 10OE

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