Physics for Scientists and Engineers With Modern Physics
9th Edition
ISBN: 9781133953982
Author: SERWAY, Raymond A./
Publisher: Cengage Learning
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Question
Chapter 35, Problem 18P
To determine
The proof of the statement that the emerging ray intersects the incident ray at an angle
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Chapter 35 Solutions
Physics for Scientists and Engineers With Modern Physics
Ch. 35.4 - Prob. 35.1QQCh. 35.5 - If beam is the incoming beam in Figure 34.10b,...Ch. 35.5 - Light passes from a material with index of...Ch. 35.7 - Prob. 35.4QQCh. 35.8 - Prob. 35.5QQCh. 35 - Prob. 1OQCh. 35 - Prob. 2OQCh. 35 - Prob. 3OQCh. 35 - Prob. 4OQCh. 35 - Prob. 5OQ
Ch. 35 - Prob. 6OQCh. 35 - Prob. 7OQCh. 35 - Prob. 8OQCh. 35 - Prob. 9OQCh. 35 - Prob. 10OQCh. 35 - Prob. 11OQCh. 35 - Prob. 12OQCh. 35 - Prob. 13OQCh. 35 - Prob. 14OQCh. 35 - Prob. 15OQCh. 35 - Prob. 1CQCh. 35 - Prob. 2CQCh. 35 - Prob. 3CQCh. 35 - Prob. 4CQCh. 35 - Prob. 5CQCh. 35 - Prob. 6CQCh. 35 - Prob. 7CQCh. 35 - Prob. 8CQCh. 35 - Prob. 9CQCh. 35 - Prob. 10CQCh. 35 - Prob. 11CQCh. 35 - (a) Under what conditions is a mirage formed?...Ch. 35 - Prob. 13CQCh. 35 - Prob. 14CQCh. 35 - Prob. 15CQCh. 35 - Prob. 16CQCh. 35 - Prob. 17CQCh. 35 - Prob. 1PCh. 35 - Prob. 2PCh. 35 - In an experiment to measure the speed of light...Ch. 35 - As a result of his observations, Ole Roemer...Ch. 35 - Prob. 5PCh. 35 - Prob. 6PCh. 35 - Prob. 7PCh. 35 - Prob. 8PCh. 35 - Prob. 9PCh. 35 - Prob. 10PCh. 35 - Prob. 11PCh. 35 - A ray of light strikes a flat block of glass (n =...Ch. 35 - Prob. 13PCh. 35 - Prob. 14PCh. 35 - Prob. 15PCh. 35 - Prob. 16PCh. 35 - Prob. 17PCh. 35 - Prob. 18PCh. 35 - When you look through a window, by what time...Ch. 35 - Two flat, rectangular mirrors, both perpendicular...Ch. 35 - Prob. 21PCh. 35 - Prob. 22PCh. 35 - Prob. 23PCh. 35 - Prob. 24PCh. 35 - Prob. 25PCh. 35 - Prob. 26PCh. 35 - Prob. 27PCh. 35 - Prob. 28PCh. 35 - Prob. 29PCh. 35 - Prob. 30PCh. 35 - Prob. 31PCh. 35 - Prob. 32PCh. 35 - Prob. 33PCh. 35 - A submarine is 300 m horizontally from the shore...Ch. 35 - Prob. 35PCh. 35 - Prob. 36PCh. 35 - Prob. 37PCh. 35 - Prob. 39PCh. 35 - Prob. 40PCh. 35 - Prob. 41PCh. 35 - Prob. 42PCh. 35 - Prob. 43PCh. 35 - Prob. 44PCh. 35 - Assume a transparent rod of diameter d = 2.00 m...Ch. 35 - Consider a light ray traveling between air and a...Ch. 35 - Prob. 47PCh. 35 - Prob. 48PCh. 35 - Prob. 49PCh. 35 - Prob. 50PCh. 35 - Prob. 51APCh. 35 - Prob. 52APCh. 35 - Prob. 53APCh. 35 - Prob. 54APCh. 35 - Prob. 55APCh. 35 - Prob. 56APCh. 35 - Prob. 57APCh. 35 - Prob. 58APCh. 35 - Prob. 59APCh. 35 - A light ray enters the atmosphere of a planet and...Ch. 35 - Prob. 61APCh. 35 - Prob. 62APCh. 35 - Prob. 63APCh. 35 - Prob. 64APCh. 35 - Prob. 65APCh. 35 - Prob. 66APCh. 35 - Prob. 67APCh. 35 - Prob. 68APCh. 35 - Prob. 69APCh. 35 - Prob. 70APCh. 35 - Prob. 71APCh. 35 - Prob. 72APCh. 35 - Prob. 73APCh. 35 - Prob. 74APCh. 35 - Prob. 75APCh. 35 - Prob. 76APCh. 35 - Prob. 77APCh. 35 - Prob. 78APCh. 35 - Prob. 79APCh. 35 - Prob. 80APCh. 35 - Prob. 81CPCh. 35 - Prob. 82CPCh. 35 - Prob. 83CPCh. 35 - Prob. 84CPCh. 35 - Prob. 85CPCh. 35 - Prob. 86CPCh. 35 - Prob. 87CP
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- Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forwardLight is incident on a prism as shown in Figure P38.31. The prism, an equilateral triangle, is made of plastic with an index of refraction of 1.46 for red light and 1.49 for blue light. Assume the apex angle of the prism is 60.00. a. Sketch the approximate paths of the rays for red and blue light as they travel through and then exit the prism. b. Determine the measure of dispersion, the angle between the red and blue rays that exit the prism. Figure P38.31arrow_forwardIn Figure P35.30, a thin converging lens of focal length 14.0 cm forms an image of the square abed, which is he = hb = 10.0 cm high and lies between distances of pd = 20.0 cm and pa = 30.0 cm from the lens. Let a, b, c. and d represent the respective corners of the image. Let qa represent the image distance for points a and b, qd represent the image distance for points c and d, hb, represent the distance from point b to the axis, and hc represent the height of c. (a) Find qa, qd, hb, and hc. (b) Make a sketch of the image. (c) The area of the object is 100 cm2. By carrying out the following steps, you will evaluate the area of the image. Let q represent the image distance of any point between a and d, for which the object distance is p. Let h represent the distance from the axis to the point at the edge of the image between b and c at image distance q. Demonstrate that h=10.0q(114.01q) where h and q are in centimeters. (d) Explain why the geometric area of the image is given by qaqdhdq (e) Carry out the integration to find the area of the image. Figure P35.30arrow_forward
- Two converging lenses having focal lengths of f1 = 10.0 cm and f2 = 20.0 cm are placed a distance d = 50.0 cm apart as shown in Figure P35.48. The image due to light passing through both lenses is to be located between the lenses at the position x = 31.0 cm indicated. (a) At what value of p should the object be positioned to the left of the first lens? (b) What is the magnification of the final image? (c) Is the final image upright or inverted? (d) Is the final image real or virtual?arrow_forwardFigure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2 . The surface forms an image I of object o. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin θ1 = n2 sin02 . For paraxial rays, we assume θ1 and θ2 are small, so we may write n1 tan θ1 = n2 tan θ2. The magnification is defined as M =h′/h. Prove that the magnification is given by M = −n1 q/n2p.arrow_forwardA fish that is d=d= 2.9 m below the surface looks up and sees a child fishing from the shore. What angle of incidence (θ1) does the ray from the person’s face make with the perpendicular to the water at the point where the ray enters? The angle of refraction (θ2) between the ray in the water and the perpendicular to the water is 35.8°. θ1 =arrow_forward
- A transparent cylinder of radius R = 2.00 m has a mirrored surface on its right half, as shown in Figure P22.55 (page 800). A light ray traveling in air is incident on the left side of the cylinder. The incident light ray and the exiting light ray are parallel, and d = 2.00 m. Determine the index of refraction of the material.arrow_forwardTwo plane mirrors are at an angle of Θ1 5 50.0° with eachother as in the side view shown in Figure P22.14. If a horizontalray is incident on mirror 1, at what angle Θ2 does the outgoingreflected ray make with the surface of mirror 2?arrow_forwardA fish that is d=d= 2.6 m below the surface looks up and sees a woman fishing from the shore. Part (a) What angle of incidence (θ1θ1) does the ray from the person’s face make with the perpendicular to the water at the point where the ray enters? The angle of refraction (θ2θ2) between the ray in the water and the perpendicular to the water is 37.1°. Part (b) What is the height of the person’s head above the water? Assume the person is standing L=L= 3.2 m away from the point where the incident ray intersects the water.arrow_forward
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