Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

1st Edition

ISBN: 9781680331141

Author: HOUGHTON MIFFLIN HARCOURT

Publisher: Houghton Mifflin Harcourt

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Concept explainers

Unitary Method

The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.

Speed, Time, and Distance

Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …

Profit and Loss

The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.

Units and Measurements

Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…

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Question

Chapter 3.6, Problem 65E

To determine

ToCalculate:The value of r using the information given in the graph.

Expert Solution & Answer

Answer to Problem 65E

Thevalue of r is r=2

Explanation of Solution

Given:

The graph representingthe two functions f(x)=3x−6 and g(x)=rf(x)

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015, Chapter 3.6, Problem 65E , additional homework tip 2

Calculation:

For the graph representing the two functions f(x)=3x−6 and g(x)=rf(x)

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015, Chapter 3.6, Problem 65E , additional homework tip 3

Since, g(x)=rf(x) and f(x)=3x−6

That is

g(x)=rf(x)=r(3x−6)=3rx−6r

Since, the graph of g(x) intersects the coordinate (0,−12) . That means, the coordinate (0,−12) satisfies the function g(x) .

That is

g(x)=3rx−6r−12=3r(0)−6r Substitute (0,−12) in the function g(x)−12=0−6r−12=−6r

−12−6=−6r−6 Divide both sides by −62=r

Therefore, the value of r is r=2

Conclusion:

Thevalue of r is r=2

Chapter 3.6, Problem 64E

Chapter 3.6, Problem 66E

Chapter 3 Solutions

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E

Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 35E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - Prob. 42E Ch. 3.1 - Prob. 43E Ch. 3.1 - Prob. 44E Ch. 3.1 - Prob. 45E Ch. 3.1 - Prob. 46E Ch. 3.1 - Prob. 47E Ch. 3.1 - Prob. 48E Ch. 3.1 - Prob. 49E Ch. 3.1 - Prob. 50E Ch. 3.1 - Prob. 51E Ch. 3.2 - Prob. 1E Ch. 3.2 - Prob. 2E Ch. 3.2 - Prob. 3E Ch. 3.2 - Prob. 4E Ch. 3.2 - Prob. 5E Ch. 3.2 - Prob. 6E Ch. 3.2 - Prob. 7E Ch. 3.2 - Prob. 8E Ch. 3.2 - Prob. 9E Ch. 3.2 - 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Prob. 2CR Ch. 3 - Prob. 3CR Ch. 3 - Prob. 4CR Ch. 3 - Prob. 5CR Ch. 3 - Prob. 6CR Ch. 3 - Prob. 7CR Ch. 3 - Prob. 8CR Ch. 3 - Prob. 9CR Ch. 3 - Prob. 10CR Ch. 3 - Prob. 11CR Ch. 3 - Prob. 12CR Ch. 3 - Prob. 13CR Ch. 3 - Prob. 14CR Ch. 3 - Prob. 15CR Ch. 3 - Prob. 16CR Ch. 3 - Prob. 17CR Ch. 3 - Prob. 18CR Ch. 3 - Prob. 19CR Ch. 3 - Prob. 20CR Ch. 3 - Prob. 21CR Ch. 3 - Prob. 22CR Ch. 3 - Prob. 23CR Ch. 3 - Prob. 24CR Ch. 3 - Prob. 25CR Ch. 3 - Prob. 26CR Ch. 3 - Prob. 27CR Ch. 3 - Prob. 28CR Ch. 3 - Prob. 29CR Ch. 3 - Prob. 30CR Ch. 3 - Prob. 31CR Ch. 3 - Prob. 32CR Ch. 3 - Prob. 33CR Ch. 3 - Prob. 34CR Ch. 3 - Prob. 35CR Ch. 3 - Prob. 36CR Ch. 3 - Prob. 37CR Ch. 3 - Prob. 1CT Ch. 3 - Prob. 2CT Ch. 3 - Prob. 3CT Ch. 3 - Prob. 4CT Ch. 3 - Prob. 5CT Ch. 3 - Prob. 6CT Ch. 3 - Prob. 7CT Ch. 3 - Prob. 8CT Ch. 3 - Prob. 9CT Ch. 3 - Prob. 10CT Ch. 3 - Prob. 11CT Ch. 3 - Prob. 12CT Ch. 3 - Prob. 13CT Ch. 3 - Prob. 14CT Ch. 3 - Prob. 1CA Ch. 3 - Prob. 2CA Ch. 3 - Prob. 3CA Ch. 3 - Prob. 4CA Ch. 3 - Prob. 5CA Ch. 3 - Prob. 6CA Ch. 3 - Prob. 7CA Ch. 3 - Prob. 8CA Ch. 3 - Prob. 9CA Ch. 3 - Prob. 10CA

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ToCalculate: The value of r using the information given in the graph.

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ToCalculate:The value of r using the information given in the graph.

Answer to Problem 65E

Explanation of Solution

Chapter 3 Solutions