PHYSICS F/SCI.+ENGR.,CHAPTERS 1-37
5th Edition
ISBN: 9780134378060
Author: GIANCOLI
Publisher: RENT PEARS
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Chapter 37, Problem 20Q
To determine
The reason why the closely spaced energy levels correspond to closed spaced spectral lines.
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Students have asked these similar questions
(a) Determine the wavelength of the second Balmerline (n=4 to n=2 transition) using Fig. 27–29. Determine likewise (b) the wavelength of the second Lyman line and (c) the wavelength of the third Balmer line.
Calculate the wavelength of the Mo(Z = 42)K« X-ray line given that the
ionization energy of hydrogen is 13.6 eV
[Adapted from the University of London, Royal Holloway 2002]
(2) In this experiment, why couldn't we observe the series of spectral lines that arise from electrons
falling to the ground state, nfinal = 1? This is the Lyman series, for which 22 (see eq. (16)) must be
replaced by 12 in both the numerator and denominator of the equation: 2 =-
1 n2
n =
R (n2-1)'
2,3,4,5, ..
Chapter 37 Solutions
PHYSICS F/SCI.+ENGR.,CHAPTERS 1-37
Ch. 37 - Prob. 1QCh. 37 - Prob. 2QCh. 37 - Prob. 3QCh. 37 - Prob. 4QCh. 37 - Prob. 5QCh. 37 - Prob. 6QCh. 37 - Prob. 7QCh. 37 - Prob. 8QCh. 37 - Prob. 9QCh. 37 - Prob. 10Q
Ch. 37 - Prob. 11QCh. 37 - Prob. 12QCh. 37 - Prob. 13QCh. 37 - Prob. 14QCh. 37 - Prob. 15QCh. 37 - Prob. 16QCh. 37 - Prob. 17QCh. 37 - Prob. 18QCh. 37 - Prob. 19QCh. 37 - Prob. 20QCh. 37 - Prob. 1PCh. 37 - Prob. 3PCh. 37 - Prob. 7PCh. 37 - Prob. 9PCh. 37 - Prob. 13PCh. 37 - Prob. 25PCh. 37 - Prob. 26PCh. 37 - Prob. 27PCh. 37 - Prob. 32PCh. 37 - Prob. 34PCh. 37 - Prob. 37PCh. 37 - Prob. 45PCh. 37 - Prob. 52PCh. 37 - Prob. 76GPCh. 37 - Prob. 77GP
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- Check Your Understanding Can the magnitude of Lzever be equal to L?arrow_forwardDo the Balmer series and the Lyman series overlap? Why? Why not? (Hint: calculate the shortest Balmer line and the longest Lyman line.)arrow_forward= . Using the formula for the hydrogen atom energy levels, En constant can be written in terms of fundamental quantities, RH = Me 4 8€, ²h³c Me 4 1 860²h² n²¹ the Rydberg and its value approaches, RH → R∞ = 10,973,731.6 m-¹ in the limit u → me. (a) How would this constant be defined for a one-electron species containing Z protons in its nucleus? Consider how this changes the form of the Hamiltonian and the energy levels for that Hamiltonian. (b) The hydrogen atom emission lines in the Balmer series (n₂ = 2) lie in the visible portion of the electromagnetic spectrum. Would this also be true if Z> 1? Find the wavelength (in nm) of the n = 32 emission in hydrogen and that for a one-electron species with Z = 2. (You will be asked to report a quantity on the quiz that depends on these two values.)arrow_forward
- .55 The radial probability density for the ground state of the hydrogen atom is a maximum whenr = a, where a is the Bohr ra- dius. Show that the average value of r, defined as P(r) r dr, has the value 1.5a. In this expression for ravgs each value of P(r) is weighted with the value of r at which it occurs. Note that the average value of r is greater than the value of r for which P(r) is a maximum.arrow_forwarda) Consider that the first line of the Balmer series of the 1H spectrum is due to the transitions between the states described by the 3p and 2s orbitals. This line suffers unfolding when the system is subject to an intense magnetic fieldexternal. Calculate the wave numbers (in cm-1 ) of the lines observed when a10,0000T magnetic field is applied. (hint: pay attention to the numberssignificant and approximations made in the calculation steps)arrow_forward(2) Determine, the shortest and longest wavelengths of the Balmer series of hydrogen. = 1.097 x 107m-1) (RH Answerarrow_forward
- (1) Based on Bohr model assumptions, prove that the wavelength equation of the hydrogen emitted 1 radiation is given by RH Answerarrow_forwardcorrect Option is (d), explain whyarrow_forward2) A hydrogen atom is in the ground state with energy (-1/2) hartree. If this hydrogen atom were subjected to an applied external magnetic field of 10 gauss, by how much would the 1s energy state of the atom change?arrow_forward
- Please asaparrow_forwardThe shortest wavelength of the Lyman series of hydrogen is 91.13 nm. Find the three longest wavelengths in this series! Please Answer my question Im needed Max 30 minutes please.... Thank uarrow_forwardCalculate the frequency of the n = 4 line in the Lyman series of hydrogen. v゠ (Please type answer no write by hend)arrow_forward
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