Essential University Physics, Volume 1 and Volume 2 - With Access
3rd Edition
ISBN: 9780134645490
Author: Wolfson
Publisher: PEARSON
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Chapter 37, Problem 30P
To determine
The energy levels between which the transition takes place.
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Consider a CO molecule that is initially in the ground state of n = 0, l = 0. If the energy of a vibrational transition from the n = 0 state to the n = 1 state in CO could instead be absorbed in a rotational transition, what would be the value of l for the final state?
The vibrational frequency n for Br2 is 323 cm-1 and the energy difference between its two lowest rotational energy levels, J = 0 and J = 1, is 0.164 cm-1. Calculate the relative populations of the v = 1 and v = 0 vibrational energylevels and the relative populations of the two lowest rotational energy levels for Br2 at 300 K. Comment on your results.
Cold interstellar molecular clouds often contain the molecule cyanogen (CN), whose first rotational excited states have an energy of 4.7x 10-4 eV (above the ground state). There are actually three such excited states, all with the same energy. In 1941, studies of the absorption spectrum of starlight that passes through these molecular clouds showed that for every ten CN molecules that are in the ground state, approximately three others are in the three first excited states (that is, an average of one in each of these states). To account for this data, astronomers suggested that the molecules might be in thermal equilibrium with some "reservoir" with a well-defined temperature. What is that temperature?*
Chapter 37 Solutions
Essential University Physics, Volume 1 and Volume 2 - With Access
Ch. 37.1 - Prob. 37.1GICh. 37.2 - If a scientist uses microwave technology to study...Ch. 37.3 - Prob. 37.3GICh. 37 - If you push two atoms together to form a molecule,...Ch. 37 - Prob. 2FTDCh. 37 - Prob. 3FTDCh. 37 - Does it make sense to distinguish individual NaCl...Ch. 37 - Prob. 5FTDCh. 37 - Prob. 6FTDCh. 37 - Radio astronomers have discovered many complex...
Ch. 37 - Prob. 8FTDCh. 37 - Prob. 9FTDCh. 37 - Prob. 10FTDCh. 37 - Prob. 11FTDCh. 37 - Prob. 12FTDCh. 37 - Prob. 13FTDCh. 37 - Prob. 14FTDCh. 37 - Prob. 15FTDCh. 37 - Prob. 16ECh. 37 - Prob. 17ECh. 37 - Prob. 18ECh. 37 - Prob. 19ECh. 37 - Prob. 20ECh. 37 - Prob. 21ECh. 37 - Prob. 22ECh. 37 - Prob. 23ECh. 37 - Prob. 24ECh. 37 - Prob. 25ECh. 37 - Prob. 26ECh. 37 - Prob. 27ECh. 37 - Prob. 28ECh. 37 - Prob. 29PCh. 37 - Prob. 30PCh. 37 - Prob. 31PCh. 37 - Prob. 32PCh. 37 - Prob. 33PCh. 37 - Prob. 34PCh. 37 - Prob. 35PCh. 37 - Prob. 36PCh. 37 - Prob. 37PCh. 37 - Prob. 38PCh. 37 - Prob. 39PCh. 37 - Prob. 40PCh. 37 - Prob. 41PCh. 37 - Prob. 42PCh. 37 - Prob. 43PCh. 37 - Prob. 44PCh. 37 - Prob. 45PCh. 37 - Prob. 46PCh. 37 - Prob. 47PCh. 37 - Prob. 48PCh. 37 - Prob. 49PCh. 37 - Prob. 50PCh. 37 - Prob. 51PCh. 37 - Prob. 52PCh. 37 - Prob. 53PCh. 37 - Prob. 54PCh. 37 - Prob. 55PCh. 37 - The transition from the ground state to the first...Ch. 37 - Prob. 57PCh. 37 - Prob. 58PCh. 37 - Youre troubled that Example 37.1 neglects the mass...Ch. 37 - Prob. 60PCh. 37 - The Madelung constant (Section 37.3) is...Ch. 37 - Prob. 62PCh. 37 - Prob. 63PCh. 37 - Prob. 64PCh. 37 - Prob. 65PCh. 37 - Prob. 66PCh. 37 - Prob. 67PCh. 37 - Prob. 68PPCh. 37 - Prob. 69PPCh. 37 - Prob. 70PPCh. 37 - Prob. 71PP
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