Essential University Physics, Volume 1 and Volume 2 - With Access
3rd Edition
ISBN: 9780134645490
Author: Wolfson
Publisher: PEARSON
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Chapter 37, Problem 8FTD
To determine
To explain: Why the rotational energy levels excite at lower temperature compared to vibrational energy level.
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Consider a CO molecule that is initially in the ground state of n = 0, l = 0. If the energy of a vibrational transition from the n = 0 state to the n = 1 state in CO could instead be absorbed in a rotational transition, what would be the value of l for the final state?
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Chapter 37 Solutions
Essential University Physics, Volume 1 and Volume 2 - With Access
Ch. 37.1 - Prob. 37.1GICh. 37.2 - If a scientist uses microwave technology to study...Ch. 37.3 - Prob. 37.3GICh. 37 - If you push two atoms together to form a molecule,...Ch. 37 - Prob. 2FTDCh. 37 - Prob. 3FTDCh. 37 - Does it make sense to distinguish individual NaCl...Ch. 37 - Prob. 5FTDCh. 37 - Prob. 6FTDCh. 37 - Radio astronomers have discovered many complex...
Ch. 37 - Prob. 8FTDCh. 37 - Prob. 9FTDCh. 37 - Prob. 10FTDCh. 37 - Prob. 11FTDCh. 37 - Prob. 12FTDCh. 37 - Prob. 13FTDCh. 37 - Prob. 14FTDCh. 37 - Prob. 15FTDCh. 37 - Prob. 16ECh. 37 - Prob. 17ECh. 37 - Prob. 18ECh. 37 - Prob. 19ECh. 37 - Prob. 20ECh. 37 - Prob. 21ECh. 37 - Prob. 22ECh. 37 - Prob. 23ECh. 37 - Prob. 24ECh. 37 - Prob. 25ECh. 37 - Prob. 26ECh. 37 - Prob. 27ECh. 37 - Prob. 28ECh. 37 - Prob. 29PCh. 37 - Prob. 30PCh. 37 - Prob. 31PCh. 37 - Prob. 32PCh. 37 - Prob. 33PCh. 37 - Prob. 34PCh. 37 - Prob. 35PCh. 37 - Prob. 36PCh. 37 - Prob. 37PCh. 37 - Prob. 38PCh. 37 - Prob. 39PCh. 37 - Prob. 40PCh. 37 - Prob. 41PCh. 37 - Prob. 42PCh. 37 - Prob. 43PCh. 37 - Prob. 44PCh. 37 - Prob. 45PCh. 37 - Prob. 46PCh. 37 - Prob. 47PCh. 37 - Prob. 48PCh. 37 - Prob. 49PCh. 37 - Prob. 50PCh. 37 - Prob. 51PCh. 37 - Prob. 52PCh. 37 - Prob. 53PCh. 37 - Prob. 54PCh. 37 - Prob. 55PCh. 37 - The transition from the ground state to the first...Ch. 37 - Prob. 57PCh. 37 - Prob. 58PCh. 37 - Youre troubled that Example 37.1 neglects the mass...Ch. 37 - Prob. 60PCh. 37 - The Madelung constant (Section 37.3) is...Ch. 37 - Prob. 62PCh. 37 - Prob. 63PCh. 37 - Prob. 64PCh. 37 - Prob. 65PCh. 37 - Prob. 66PCh. 37 - Prob. 67PCh. 37 - Prob. 68PPCh. 37 - Prob. 69PPCh. 37 - Prob. 70PPCh. 37 - Prob. 71PP
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- The Madelung constant for the NaCl structure may be found by summing an infinite alternating series of terms giving the electrostatic potential energy between an Na+ ion and its 6 nearest Cl neighbors, its 12 next-nearest N+ neighbors, and so on (see Fig. 12.1a). (a) From this expression, show that the first three terms of the infinite series for the Madelung constant for the NaCl structure yield = 2.13. (b) Does this infinite series converge rapidly? Calculate the fourth term as a check.arrow_forwardConsider the HCl molecule, which consists of a hydrogen atom of mass 1 u bound to a chlorine atom of mass 35 u. The equilibrium separation between the atoms is 0.128 nm, and it requires 0.15 eV of work to increase or decrease this separation by 0.01 nm. (a) Calculate the four lowest rotational energies (in eV) that are possible, assuming the molecule rotates rigidly. (b) Find the molecules spring constant and its classical frequency of vibration. (Hint: Recall that U=12Kx2.) (c) Find the two lowest vibrational energies and the classical amplitude of oscillation corresponding to each of these energies. (d) Determine the longest wavelength radiation that the molecule can emit in a pure rotational transition and in a pure vibrational transition.arrow_forwardCompare the effective force constant for the CO molecule deduced here with that of an ordinary laboratory spring that stretches 0.5 m when a 1.0 kg mass is suspended from it.arrow_forward
- The measured density of a CsCl crystal is 3.988 g/cm3. What is the equilibrium separate distance of Cs+ and Cl- ions?arrow_forwardFor the following cases, what type of bonding expected? (a) KCl molecule; (b) N2 molecule.arrow_forwardSn, C, and Si, Ge are all group XIV elements. Yet, Sn is a conductor, C is an insulator while Si and Ge are semiconductors. Why?arrow_forward
- If the moment of inertia of 1H 127I is 4.31 x 10-47 kg m2. Determine the bond length of HI and the rotational energy at quantum number J=5 Please to respond quickly.arrow_forwardThe figure above shows the absorption spectrum of the molecule HBr. Following the basic procedures of Section 9.6, find:(a) the energy of the “missing” transition;(b) the effective force constant k;(c) the rotational spacing 2B. Estimate the value of the rotational spacing expected for HBr and compare with the value deduced from the spectrum. Why are there only single lines and not double lines as in the case of HCl?arrow_forwardWhen an OH molecule undergoes a transition from the n = 0 to the n = 1 vibrational level, its internal vibrational energy increases by 0.463 eV. Calculate the frequency of vibration and the force constant for the interatomic force. (The mass of an oxygen atom is 2.66 * 10-26 kg, and the mass of a hydrogen atom is 1.67 * 10-27 kg.)arrow_forward
- Show that the moment of inertia of a diatomic molecule composed of atoms of masses mA and mB and bond length R is equal to meffR2, where meff = mAmB/(mA+mB).arrow_forwardShow that the moment of inertia of a diatomic molecule composed of atoms of masses mA and mB and bond length R is equal to meffR2, where meff = mAmB/(mA + mB).arrow_forwardA CO molecule is initially in the n = 2 vibrational level. If this molecule loses both vibrational and rotational energy and emits a photon, what are the photon wavelength and frequency if the initial angular momentum quantum number is l = 3?arrow_forward
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